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## highschoolmom2010 3 years ago check my work

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1. highschoolmom2010

$y=\sqrt{2*leg}$ $y=\sqrt{2}*8$ $y=8\sqrt{2}$

2. phi

yes, except for the very first statement... the leg is not inside the square root but your answer is correct. and it should be clear x is also 8

3. highschoolmom2010

i didnt know how to move it over -_- so y and x are the same value

4. highschoolmom2010

@phi

5. phi

?

6. phi

**i didnt know how to move it over *** that is awfully cryptic. do you mean how to write y = sqrt{2} * leg ?

7. phi

you have an isosceles triangle (2 "base" angles are equal) so the two sides are also equal

8. highschoolmom2010

i wasnt sure if it would move it over by its self

9. highschoolmom2010

oh ty for explaining that to me :DD

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