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highschoolmom2010

  • 2 years ago

check my work

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  1. highschoolmom2010
    • 2 years ago
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    \[y=\sqrt{2*leg}\] \[y=\sqrt{2}*8\] \[y=8\sqrt{2}\]

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  2. phi
    • 2 years ago
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    yes, except for the very first statement... the leg is not inside the square root but your answer is correct. and it should be clear x is also 8

  3. highschoolmom2010
    • 2 years ago
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    i didnt know how to move it over -_- so y and x are the same value

  4. highschoolmom2010
    • 2 years ago
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    @phi

  5. phi
    • 2 years ago
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    ?

  6. phi
    • 2 years ago
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    **i didnt know how to move it over *** that is awfully cryptic. do you mean how to write y = sqrt{2} * leg ?

  7. phi
    • 2 years ago
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    you have an isosceles triangle (2 "base" angles are equal) so the two sides are also equal

  8. highschoolmom2010
    • 2 years ago
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    i wasnt sure if it would move it over by its self

  9. highschoolmom2010
    • 2 years ago
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    oh ty for explaining that to me :DD

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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