Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
What is the side length of the smallest square plate on which a 20cm chopstick can fit along a diagonal without any overhang? Round your answer to the nearest tenth of a centimeter.
 8 months ago
 8 months ago
What is the side length of the smallest square plate on which a 20cm chopstick can fit along a diagonal without any overhang? Round your answer to the nearest tenth of a centimeter.
 8 months ago
 8 months ago

This Question is Closed

dumbcowBest ResponseYou've already chosen the best response.1
use fact the diagonal of a square is sqrt2 times side length dw:1375640019150:dw
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.0
dw:1375640072724:dw
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.0
is that how i need to set it up?
 8 months ago

gypsy1274Best ResponseYou've already chosen the best response.1
Looks good to me. Do you know where to go from there?
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.0
eh not really well ....
 8 months ago

gypsy1274Best ResponseYou've already chosen the best response.1
I would use the pythagorean theorem to find the length of the sides. Does that help?
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.0
so x^2+x^2=20^2 x^2+x^2=400^@
 8 months ago

gypsy1274Best ResponseYou've already chosen the best response.1
Before taking the square root, divide both sides by 2.
 8 months ago

gypsy1274Best ResponseYou've already chosen the best response.1
\(x^2+x^2 = 20^2\) \(2x^2=400\)
 8 months ago

dumbcowBest ResponseYou've already chosen the best response.1
haha ok i guess you didn't get my drawing...you could just say \[\sqrt{2} x = 20\] \[x = \frac{20}{\sqrt{2}}\]
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.0
oh ok \[\frac{ 2x^2 }{ 2 }=\frac{ 400 }{ 2 }\] \[x^2=200\] \[\sqrt{x^2}=\sqrt{200}\]
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.0
dw:1375640872842:dw what do i do from here
 8 months ago

gypsy1274Best ResponseYou've already chosen the best response.1
Yes, that would be great if you were supposed to have a radical in your answer, but your question says to round to the nearest tenth, so use a calculator (or google) to get the square root of 200.
 8 months ago

dumbcowBest ResponseYou've already chosen the best response.1
they want answer as decimal so no point in simplifying radical ...
 8 months ago

gypsy1274Best ResponseYou've already chosen the best response.1
You might want to save @dumbcow's original picture and equation to spend a rainy day in contemplation. If you can remember it the next time you need it, that would be a quicker way of getting to the answer.
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.0
well if i needed the simple radical i was headed right :DD
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.0
\[\approx 14.14\]
 8 months ago

gypsy1274Best ResponseYou've already chosen the best response.1
Yes, you simplified the radical very well. And in later classes, you will probably need to leave your answer like that. Rounded to the nearest tenth is one place after the decimal....
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.0
\[\approx14\]
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.0
sorry i forgot that for a second
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.0
oh well i got that all mixed up
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.0
ty @gypsy1274 & @dumbcow
 8 months ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.