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sweetpink365

  • 2 years ago

How do i factor 8x^3-27?

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  1. britbrat4290
    • 2 years ago
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    a^3 - b^3 = (a - b) * (a² + ab + b²) a = 2x and b = -3 <=> (2x)^3 - (-3)^3 = (2x - (-3)) * ((2x)² + (2x * (-3)) + (-3)²) = (2x + 3) * (4x² - 6x + 9)

  2. britbrat4290
    • 2 years ago
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    medal plzz :)

  3. britbrat4290
    • 2 years ago
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    hopefully u get the process

  4. Paynesdad
    • 2 years ago
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    Nice @britbrat4290

  5. goformit100
    • 2 years ago
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    You can do (2x + 3) * (4x² - 6x + 9)

  6. britbrat4290
    • 2 years ago
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    yea u can do it a couple ways

  7. goformit100
    • 2 years ago
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    And that will be your required answer

  8. britbrat4290
    • 2 years ago
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    ty @Paynesdad :)

  9. sweetpink365
    • 2 years ago
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    So I can solve (2x + 3) * (4x² - 6x + 9)

  10. Paynesdad
    • 2 years ago
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    There is no solving it is just factoring it.

  11. Paynesdad
    • 2 years ago
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    You can't solve something unless it is an equation or an inequality

  12. sweetpink365
    • 2 years ago
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    How do i come up with the answer? Like its 8x^3-27 but i dont see the GCF so how do i factor now?

  13. sweetpink365
    • 2 years ago
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    How did i get 2 for the x?

  14. britbrat4290
    • 2 years ago
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    if u do the math

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