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mathcalculus Group Title

finding critical points with polynomial functions (attached)

  • one year ago
  • one year ago

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  1. mathcalculus Group Title
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    • one year ago
  2. mathcalculus Group Title
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    is it possible to use quadratic formula for this since it can't be factored...?

    • one year ago
  3. abb0t Group Title
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    To find critical points you need to take a derivative.

    • one year ago
  4. mathcalculus Group Title
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    okay, so -6x-7

    • one year ago
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    @abb0t

    • one year ago
  6. abb0t Group Title
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    Now, set it equal to zero and find the roots. Those value(s) are your critical point(s).

    • one year ago
  7. mathcalculus Group Title
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    i found one.

    • one year ago
  8. mathcalculus Group Title
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    @abb0t

    • one year ago
  9. mathcalculus Group Title
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    x=-7/6

    • one year ago
  10. abb0t Group Title
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    Yes,

    • one year ago
  11. mathcalculus Group Title
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    critical point is ((-7,6),0)?

    • one year ago
  12. mathcalculus Group Title
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    it's marking me wrong.

    • one year ago
  13. mathcalculus Group Title
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    @abb0t

    • one year ago
  14. abb0t Group Title
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    why is it 0 when you clearly found the value to be \(\frac{7}{6}\)...

    • one year ago
  15. mathcalculus Group Title
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    that's the problem.. after i find the critical point what do i do?

    • one year ago
  16. mathcalculus Group Title
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    @abb0t

    • one year ago
  17. mathcalculus Group Title
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    how would i write the point?

    • one year ago
  18. abb0t Group Title
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    That is your only critical point.

    • one year ago
  19. mathcalculus Group Title
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    just plug into original function?

    • one year ago
  20. mathcalculus Group Title
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    yes but it has to be written as a point @abb0t

    • one year ago
  21. abb0t Group Title
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    Yes, plug it into original.

    • one year ago
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