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mathcalculus

  • one year ago

finding critical points with polynomial functions (attached)

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  1. mathcalculus
    • one year ago
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  2. mathcalculus
    • one year ago
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    is it possible to use quadratic formula for this since it can't be factored...?

  3. abb0t
    • one year ago
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    To find critical points you need to take a derivative.

  4. mathcalculus
    • one year ago
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    okay, so -6x-7

  5. mathcalculus
    • one year ago
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    @abb0t

  6. abb0t
    • one year ago
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    Now, set it equal to zero and find the roots. Those value(s) are your critical point(s).

  7. mathcalculus
    • one year ago
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    i found one.

  8. mathcalculus
    • one year ago
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    @abb0t

  9. mathcalculus
    • one year ago
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    x=-7/6

  10. abb0t
    • one year ago
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    Yes,

  11. mathcalculus
    • one year ago
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    critical point is ((-7,6),0)?

  12. mathcalculus
    • one year ago
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    it's marking me wrong.

  13. mathcalculus
    • one year ago
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    @abb0t

  14. abb0t
    • one year ago
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    why is it 0 when you clearly found the value to be \(\frac{7}{6}\)...

  15. mathcalculus
    • one year ago
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    that's the problem.. after i find the critical point what do i do?

  16. mathcalculus
    • one year ago
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    @abb0t

  17. mathcalculus
    • one year ago
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    how would i write the point?

  18. abb0t
    • one year ago
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    That is your only critical point.

  19. mathcalculus
    • one year ago
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    just plug into original function?

  20. mathcalculus
    • one year ago
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    yes but it has to be written as a point @abb0t

  21. abb0t
    • one year ago
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    Yes, plug it into original.

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