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mathcalculus
how can i factor this: ? :(
you can use quadratic formula\[x=\frac{ b ^{2}\pm \sqrt{b ^{2}-4ac} }{ 2a }\] \[a=15 b= -116 c=-32\]
if \[D= \sqrt{b ^{2}-4ac}<0\rightarrow No Roots , Cannot be factored\] \[D= \sqrt{b ^{2}-4ac}>0\rightarrow 2 Roots , Cant be factored\] \[D= \sqrt{b ^{2}-4ac}=0\rightarrow 1 Root , Can be factored\]
i found the critical point..... x=-8/3 and x=4/5
my mistake the quadratic formula is \[x=\frac{ b \pm \sqrt{b ^{2}-4ac}}{2a }\]
I got x=8 and x=-4/15 factors are (x-8)(15x+4) \[x \frac{ -4 }{ 15}\] \[15x=-4\] \[15x+4=0\]