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eLgBest ResponseYou've already chosen the best response.1
you can use quadratic formula\[x=\frac{ b ^{2}\pm \sqrt{b ^{2}4ac} }{ 2a }\] \[a=15 b= 116 c=32\]
 8 months ago

eLgBest ResponseYou've already chosen the best response.1
if \[D= \sqrt{b ^{2}4ac}<0\rightarrow No Roots , Cannot be factored\] \[D= \sqrt{b ^{2}4ac}>0\rightarrow 2 Roots , Cant be factored\] \[D= \sqrt{b ^{2}4ac}=0\rightarrow 1 Root , Can be factored\]
 8 months ago

mathcalculusBest ResponseYou've already chosen the best response.0
i found the critical point..... x=8/3 and x=4/5
 8 months ago

eLgBest ResponseYou've already chosen the best response.1
my mistake the quadratic formula is \[x=\frac{ b \pm \sqrt{b ^{2}4ac}}{2a }\]
 8 months ago

eLgBest ResponseYou've already chosen the best response.1
I got x=8 and x=4/15 factors are (x8)(15x+4) \[x \frac{ 4 }{ 15}\] \[15x=4\] \[15x+4=0\]
 8 months ago
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