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mathcalculus
 2 years ago
how can i factor this: ? :(
mathcalculus
 2 years ago
how can i factor this: ? :(

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eLg
 2 years ago
Best ResponseYou've already chosen the best response.1you can use quadratic formula\[x=\frac{ b ^{2}\pm \sqrt{b ^{2}4ac} }{ 2a }\] \[a=15 b= 116 c=32\]

eLg
 2 years ago
Best ResponseYou've already chosen the best response.1if \[D= \sqrt{b ^{2}4ac}<0\rightarrow No Roots , Cannot be factored\] \[D= \sqrt{b ^{2}4ac}>0\rightarrow 2 Roots , Cant be factored\] \[D= \sqrt{b ^{2}4ac}=0\rightarrow 1 Root , Can be factored\]

mathcalculus
 2 years ago
Best ResponseYou've already chosen the best response.0i found the critical point..... x=8/3 and x=4/5

eLg
 2 years ago
Best ResponseYou've already chosen the best response.1my mistake the quadratic formula is \[x=\frac{ b \pm \sqrt{b ^{2}4ac}}{2a }\]

eLg
 2 years ago
Best ResponseYou've already chosen the best response.1I got x=8 and x=4/15 factors are (x8)(15x+4) \[x \frac{ 4 }{ 15}\] \[15x=4\] \[15x+4=0\]
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