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mathcalculusBest ResponseYou've already chosen the best response.0
i found the derivative then i set it to zero. i factored then found the critical points: x=8/3
 8 months ago

mathcalculusBest ResponseYou've already chosen the best response.0
i tried to find y by plugging in the x into original function.... then got this: (8/3,419.92) and (4/5,58.16)
 8 months ago

mathcalculusBest ResponseYou've already chosen the best response.0
can someone tell me what i did wrong?
 8 months ago

mathcalculusBest ResponseYou've already chosen the best response.0
critical points *** x=8/3 and x=4/5
 8 months ago

zepdrixBest ResponseYou've already chosen the best response.1
So did you get this for your derivative function?\[\large h'(x)=15x^2116x32\]
 8 months ago

zepdrixBest ResponseYou've already chosen the best response.1
Setting it equal to zero, tossing it into the Quadratic Formula gives us,\[\large x=\frac{116 \pm \sqrt{116^2+4\cdot15\cdot32}}{2\cdot15}\]
 8 months ago

zepdrixBest ResponseYou've already chosen the best response.1
I'm coming up with different solutions, lemme know if that setup looks like what you have.
 8 months ago

mathcalculusBest ResponseYou've already chosen the best response.0
do we have to use quadratic formula? i just factored
 8 months ago

zepdrixBest ResponseYou've already chosen the best response.1
You were able to factor it into fractions? lol... You must've factored something incorrectly :[
 8 months ago

mathcalculusBest ResponseYou've already chosen the best response.0
i don't know i was told you can break it down bby multiplying the coefficient and constant= # and finding the factors and sums of that number. right?
 8 months ago

zepdrixBest ResponseYou've already chosen the best response.1
Mmm yah something like that, lemme try to factor it real quick. I'm not very good with factoring myself :) lol.
 8 months ago

mathcalculusBest ResponseYou've already chosen the best response.0
i got: x=8 and x=4/15 by using the quadratic formula
 8 months ago

zepdrixBest ResponseYou've already chosen the best response.1
Yah me too. \[\large 15=5\cdot3 \qquad \qquad 32=4\cdot8\] That relates to your factoring method somehow..\[\large \frac{4}{15}\qquad=\qquad \frac{4}{3 \cdot 5}\] I just can't seem to figure out how :)
 8 months ago

mathcalculusBest ResponseYou've already chosen the best response.0
oh okay thank you @zepdrix :)!
 8 months ago

mathcalculusBest ResponseYou've already chosen the best response.0
i think we can't factor so we use quadratic right away..
 8 months ago
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