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mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
i found the derivative then i set it to zero. i factored then found the critical points: x=8/3
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
correct?
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
i tried to find y by plugging in the x into original function.... then got this: (8/3,419.92) and (4/5,58.16)
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
can someone tell me what i did wrong?
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
critical points *** x=8/3 and x=4/5
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
So did you get this for your derivative function?\[\large h'(x)=15x^2116x32\]
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Setting it equal to zero, tossing it into the Quadratic Formula gives us,\[\large x=\frac{116 \pm \sqrt{116^2+4\cdot15\cdot32}}{2\cdot15}\]
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
I'm coming up with different solutions, lemme know if that setup looks like what you have.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
do we have to use quadratic formula? i just factored
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
You were able to factor it into fractions? lol... You must've factored something incorrectly :[
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
i don't know i was told you can break it down bby multiplying the coefficient and constant= # and finding the factors and sums of that number. right?
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Mmm yah something like that, lemme try to factor it real quick. I'm not very good with factoring myself :) lol.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
lol ok
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
i got: x=8 and x=4/15 by using the quadratic formula
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Yah me too. \[\large 15=5\cdot3 \qquad \qquad 32=4\cdot8\] That relates to your factoring method somehow..\[\large \frac{4}{15}\qquad=\qquad \frac{4}{3 \cdot 5}\] I just can't seem to figure out how :)
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
oh okay thank you @zepdrix :)!
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
i think we can't factor so we use quadratic right away..
 one year ago
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