anonymous
  • anonymous
Please help What is the sum of the arithmetic sequence 134, 122, 110 …, if there are 32 terms?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
tpaulus
  • tpaulus
Find the general form, then use that to find the last term. then use the sum of an arithmetic sequence equation to find the sum.\[s = n/2 * (n1 + n32)\]
campbell_st
  • campbell_st
well the sum is simply \[S_{n} = \frac{n}{2}[2a + (n -1)d]\] a = 1st term, n = number of terms and d = common difference in your question you know n = 32, the 1st term is 134 find the common difference. ..d and then substitute and evaluate. the value of d will be negative
anonymous
  • anonymous
–1,664 –1,632 –1,600 –1,568

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Those are the answers.^
anonymous
  • anonymous
S = [134 - (0)(12)] + [134 - (1)(12)] + [134 - (2)(12)] + . . . + [134 - (31)(12)] S = (134)(32) - (12)(1 + 2 + 3 + . . . + 31) S = (134)(32) - (12)(31)(32)/2
anonymous
  • anonymous
All good now, @maria-17 ?
anonymous
  • anonymous
THanksss.
anonymous
  • anonymous
uw!
anonymous
  • anonymous
Good luck to you in all of your studies and thx for the recognition! @maria-17
anonymous
  • anonymous
Can you help me with one more?
anonymous
  • anonymous
Sure, why not? Best though to close this one and just start another post.

Looking for something else?

Not the answer you are looking for? Search for more explanations.