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anonymous
 3 years ago
Please help
What is the sum of the arithmetic sequence 134, 122, 110 …, if there are 32 terms?
anonymous
 3 years ago
Please help What is the sum of the arithmetic sequence 134, 122, 110 …, if there are 32 terms?

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tpaulus
 3 years ago
Best ResponseYou've already chosen the best response.0Find the general form, then use that to find the last term. then use the sum of an arithmetic sequence equation to find the sum.\[s = n/2 * (n1 + n32)\]

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.0well the sum is simply \[S_{n} = \frac{n}{2}[2a + (n 1)d]\] a = 1st term, n = number of terms and d = common difference in your question you know n = 32, the 1st term is 134 find the common difference. ..d and then substitute and evaluate. the value of d will be negative

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0–1,664 –1,632 –1,600 –1,568

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Those are the answers.^

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0S = [134  (0)(12)] + [134  (1)(12)] + [134  (2)(12)] + . . . + [134  (31)(12)] S = (134)(32)  (12)(1 + 2 + 3 + . . . + 31) S = (134)(32)  (12)(31)(32)/2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0All good now, @maria17 ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Good luck to you in all of your studies and thx for the recognition! @maria17

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Can you help me with one more?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Sure, why not? Best though to close this one and just start another post.
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