Here's the question you clicked on:

## maria-17 Group Title Please help What is the sum of the arithmetic sequence 134, 122, 110 …, if there are 32 terms? 11 months ago 11 months ago

• This Question is Closed
1. tpaulus Group Title

Find the general form, then use that to find the last term. then use the sum of an arithmetic sequence equation to find the sum.$s = n/2 * (n1 + n32)$

2. campbell_st Group Title

well the sum is simply $S_{n} = \frac{n}{2}[2a + (n -1)d]$ a = 1st term, n = number of terms and d = common difference in your question you know n = 32, the 1st term is 134 find the common difference. ..d and then substitute and evaluate. the value of d will be negative

3. maria-17 Group Title

–1,664 –1,632 –1,600 –1,568

4. maria-17 Group Title

Those are the answers.^

5. tcarroll010 Group Title

S = [134 - (0)(12)] + [134 - (1)(12)] + [134 - (2)(12)] + . . . + [134 - (31)(12)] S = (134)(32) - (12)(1 + 2 + 3 + . . . + 31) S = (134)(32) - (12)(31)(32)/2

6. tcarroll010 Group Title

All good now, @maria-17 ?

7. maria-17 Group Title

THanksss.

8. tcarroll010 Group Title

uw!

9. tcarroll010 Group Title

Good luck to you in all of your studies and thx for the recognition! @maria-17

10. maria-17 Group Title

Can you help me with one more?

11. tcarroll010 Group Title

Sure, why not? Best though to close this one and just start another post.