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highschoolmom2010 Group Title

Find the value of each variable. If your answer is not an integer, express it in simplest radical form.

  • one year ago
  • one year ago

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  1. highschoolmom2010 Group Title
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    • one year ago
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  2. highschoolmom2010 Group Title
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    \[h=\sqrt{2}*leg\] \[h=\sqrt{2}*\sqrt[2]{3}\]

    • one year ago
  3. highschoolmom2010 Group Title
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    this is where im confused

    • one year ago
  4. mathstudent55 Group Title
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    Again, a 30-60-90 triangle, so we have a \(1 : \sqrt{3} : 2 \) ratio of sides.

    • one year ago
  5. highschoolmom2010 Group Title
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    so i have 2sqrt 3 for the side 1

    • one year ago
  6. mathstudent55 Group Title
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    No. Be careful. The long leg is 2sqrt(3). In the ratio, the long leg is sqrt(3)

    • one year ago
  7. mathstudent55 Group Title
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    Ratio: 1 : sqrt(3) : 2 Your triangle: y : 2sqrt(3) : x

    • one year ago
  8. mathstudent55 Group Title
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    Since the long leg is sqrt(3) times longer than the short leg, the short leg is sqrt(3) times shorter than the long leg. Divide the long leg by sqrt(3) to get the short leg, x. Then multiply the short leg by 2 to get the hypotenuse, y.

    • one year ago
  9. Zale101 Group Title
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    longer leg=√3*shorter leg 2√3=y√3

    • one year ago
  10. Zale101 Group Title
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    \[\frac{ 2√3}{ √3 }*\frac{ √3}{ √3 } simplify \]

    • one year ago
  11. robtobey Group Title
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    \[x\text{=}2 \sqrt{3}\text{Sec}[30{}^{\circ}]\text{=}4\]\[y=2 \sqrt{3}\text{Tan}[30{}^{\circ}]=2 \]

    • one year ago
  12. highschoolmom2010 Group Title
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    \[\frac{ 2\sqrt{3} }{ 2 }=\sqrt{3}\]

    • one year ago
  13. highschoolmom2010 Group Title
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    @robtobey what is that

    • one year ago
  14. highschoolmom2010 Group Title
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    @radar @hobbs978 @jdoe0001 @nincompoop @Psymon @thomaster @timo86m please can someone help me here

    • one year ago
  15. timo86m Group Title
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    i dont think she know trig :)

    • one year ago
  16. timo86m Group Title
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    its a 30 60 90 like math student said so solve the ratio :D

    • one year ago
  17. highschoolmom2010 Group Title
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    but i get to |dw:1375832123497:dw| and no one wants to say if i am going right or not and what to do next

    • one year ago
  18. hobbs978 Group Title
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    |dw:1375832312897:dw| does this picture help you a little

    • one year ago
  19. highschoolmom2010 Group Title
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    yes !!!

    • one year ago
  20. hobbs978 Group Title
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    |dw:1375832388157:dw|

    • one year ago
  21. highschoolmom2010 Group Title
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    |dw:1375832670924:dw|

    • one year ago
  22. timo86m Group Title
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    math student is wrong btw those are the wrong ratios the correct are the following 30-60-90 1 : sqrt(3) : 2 y : 2sqrt(3): x we can see that 60s side is sqrt(3) times larger than 30s side so y=2sqrt(3)/sqrt(3) dividing by sqrt 3 says it is 3 times smaller than 60s side now we just evaluate y=2sqrt(3)/sqrt(3) the sqrt(3)s cancel and now you have y = 2 with me so far fill in that chart 30-60-90 1 : sqrt(3) : 2 2 : 2sqrt(3): x ^ y is now 2 :D

    • one year ago
  23. highschoolmom2010 Group Title
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    |dw:1375833255952:dw|

    • one year ago
  24. highschoolmom2010 Group Title
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    im soo confused

    • one year ago
  25. timo86m Group Title
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    30 -60 -90 1 : sqrt(3) : 2 2 : 2sqrt(3): x ^ y is now 2 from the chart we know see 90s side is twice as big as 30s side Or conversely 30s side is twice as small 2=x*2 so 90 will be 4

    • one year ago
  26. timo86m Group Title
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    it has to do with a 30 60 90 triangle and its ratios. They are just given in your book if not google it :) it is presumed that you know it. I dont but i googled it since i haven't in so long. in a 30 60 90 you have these ratios 30 - 60 -90 1 : sqrt(3) : 2 |dw:1375833497906:dw|

    • one year ago
  27. timo86m Group Title
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    |dw:1375833605135:dw|

    • one year ago
  28. timo86m Group Title
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    from the figure and the labeled ratios it says x is twice as big as y. Not much you can do there since they are just variables. however it does say 60s oppossite side is 2sqrt(3) and if you take the ratio of it to 30s opposite side of y it says y is sqrt(3) times smaller so you can work up an equation for that y=2*sqrt(3)/sqrt(3) here the sqrts cancel so you left with y = 2. now you can say 90s oppossite side x is twice as big as 30s opposite side y which y = 2 so therefore x is just 4 and those are your sides x=4 y=2 and of course your given angle is just your given angle :)

    • one year ago
  29. timo86m Group Title
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    |dw:1375834030274:dw|

    • one year ago
  30. timo86m Group Title
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    |dw:1375834055304:dw|

    • one year ago
  31. hobbs978 Group Title
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    i will explain this in simple terms :) |dw:1375834066350:dw|

    • one year ago
  32. hobbs978 Group Title
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    |dw:1375834098059:dw| plug in your a to all your sides |dw:1375834135512:dw||dw:1375834150409:dw|

    • one year ago
  33. hobbs978 Group Title
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    but @timo86m had a very good explanation of this and would suggest go overing that this is just a summary of what he said

    • one year ago
  34. highschoolmom2010 Group Title
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    @timo86m good explaining

    • one year ago
  35. highschoolmom2010 Group Title
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    so x=4 and y=2

    • one year ago
  36. hobbs978 Group Title
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    :)

    • one year ago
  37. highschoolmom2010 Group Title
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    @hobbs978 yours was easier to understand thanks

    • one year ago
  38. highschoolmom2010 Group Title
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    thanks to everyone that helped out :DD

    • one year ago
  39. robtobey Group Title
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    @timo86m Your observation regarding a lack of trig knowledge is probably true after reviewing the back and forth comments. When jumping into the middle of a problem like this, I usually post an answer that involves a minimum of narrative.

    • 11 months ago
  40. mathstudent55 Group Title
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    @timo86m Why do you say my ratios are wrong and then you write exactlty the same ratios? I wrote: "Ratio: 1 : sqrt(3) : 2 Your triangle: y : 2sqrt(3) : x " You wrote: "math student is wrong btw those are the wrong ratios the correct are the following 30-60-90 1 : sqrt(3) : 2 y : 2sqrt(3): x " You have exactly the same ratios I have. How are mine wrong and yours not?

    • 11 months ago
  41. mathstudent55 Group Title
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    @highschoolmom2010 In the seventh response after you posted the figure at the top, I wrote: "Divide the long leg by sqrt(3) to get the short leg, x. Then multiply the short leg by 2 to get the hypotenuse, y." Then I had to leave. I thought I was pretty much telling you exactly what to do to solve this problem, but maybe you didn't understand. To find x: "Divide the long leg by sqrt(3) to get the short leg, x." means: \( x = \dfrac { 2 \sqrt{3} } {\sqrt{3}}\) (the \(\sqrt{3} \) in the numerator and the \(\sqrt{3}\) in the denominator cancel out, so \(x = 2\) To find y: "Then multiply the short leg by 2 to get the hypotenuse, y" \(y = 2 \times 2\) \(y = 4\) BTW, above you wrote your answer as "so x=4 and y=2 ", but you switched the values of x and y.

    • 11 months ago
  42. timo86m Group Title
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    @mathstudent55 It was you that is right. BUt I copied pasted your own ratios and when i pasted them it came out all wrong. I guess it is because you used latex and the pasting didn't interpet right sorry.

    • 11 months ago
  43. timo86m Group Title
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    30-60-90 triangle, so we have a 1:3√:2 ^ SEE again when i copy paste the sqrt is not on the 3 but instead it looks like it is on the 2 And therefore i thought you had wrong ratios when in fact it was OS's or Latex's wrong doing.

    • 11 months ago
  44. mathstudent55 Group Title
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    Thanks for answering. I see, but I didn't use Latex. I just copied and pasted myself to show you what I had written above. This is very strange.

    • 11 months ago
  45. highschoolmom2010 Group Title
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    @mathstudent55 i am more a visual learner so @hobbs978 showing me was easier yes you answer is correct too so thanks @mathstudent55

    • 11 months ago
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