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mathcalculus
 one year ago
Locate all critical points of s(t) = (2 t  3)^(2) (8  2 t)^(3)?
mathcalculus
 one year ago
Locate all critical points of s(t) = (2 t  3)^(2) (8  2 t)^(3)?

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Paynesdad
 one year ago
Best ResponseYou've already chosen the best response.1Ok is this a calc problem?

Paynesdad
 one year ago
Best ResponseYou've already chosen the best response.1SO your critical points are max, min, and points of inflection, right?

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0critical points are x

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0we have to solve for x... to find the y's and that gives us our point

Paynesdad
 one year ago
Best ResponseYou've already chosen the best response.1Right but when the question says critical points...In calculus that is usually the maximum, minimum an/or points of inflection.

SithsAndGiggles
 one year ago
Best ResponseYou've already chosen the best response.2\[s(t)=(2t3)^2(82t)^3\\ \Rightarrow~s'(t)=4(2t3)(82t)^36(2t3)^2(82t)^2\\ \Rightarrow~s'(t)=(2t3)(82t)^2\left[4(82t)6(2t3)\right]\\ \Rightarrow~s'(t)=(2t3)(82t)^2(5020t)\] It should be fairly easy to find when \(s'(t)=0\).

Paynesdad
 one year ago
Best ResponseYou've already chosen the best response.1That would locate your max and minimums but not your points of inflection. @SithsAndGiggles

SithsAndGiggles
 one year ago
Best ResponseYou've already chosen the best response.2@Paynesdad, usually when a problem asks for critical points, it's referring to the critical points of \(f(x)\). Points of inflection for \(f(x)\) are critical points of \(f'(x)\), not \(f(x)\), so I would think that's the assumption to be used here.

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0@SithsAndGiggles we used the product AND chain rule right?

SithsAndGiggles
 one year ago
Best ResponseYou've already chosen the best response.2Product, chain, power (not necessarily in that order).

SithsAndGiggles
 one year ago
Best ResponseYou've already chosen the best response.2@Paynesdad, but that doesn't mean critical points can't be inflection points. Depends on the function.

Paynesdad
 one year ago
Best ResponseYou've already chosen the best response.1Correct .. I just wanted to know if she would need to go on and get the 2nd derivative to find the points of inflection as well or just the first derivative critical points.

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0@Paynesdad oh sorry, no i was only looking for the critical points.

Paynesdad
 one year ago
Best ResponseYou've already chosen the best response.1Sounds like you have a good handle on this problem...Nice work @SithsAndGiggles and @mathcalculus
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