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highschoolmom2010

  • 2 years ago

using Sin, Cos, Tan For parts (a)–(c), find the value of w to the nearest tenth

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  1. highschoolmom2010
    • 2 years ago
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  2. ganeshie8
    • 2 years ago
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    familiar wid SOH-CAH-TOA ?

  3. phi
    • 2 years ago
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    you are zipping along... now learning trig ?

  4. phi
    • 2 years ago
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    when you get time (if you want to see more info) http://www.khanacademy.org/math/trigonometry/basic-trigonometry/basic_trig_ratios/v/basic-trigonometry

  5. highschoolmom2010
    • 2 years ago
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    not really understand but @phi that is in my lessons for geometry

  6. ganeshie8
    • 2 years ago
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    yeah usually they put trig ratios right after similar triangles

  7. highschoolmom2010
    • 2 years ago
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    i can kinda do it not really well yet

  8. phi
    • 2 years ago
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    khan explains it better than trying to learn it from reading explanations here. This site is better for going over your problems

  9. highschoolmom2010
    • 2 years ago
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    ok ok so watch his videos first :D

  10. highschoolmom2010
    • 2 years ago
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    |dw:1375894551709:dw| doesnt really show how to do this @ganeshie8

  11. ganeshie8
    • 2 years ago
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    first go to the 54 degree corner and stare at the triangle from there

  12. ganeshie8
    • 2 years ago
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    |dw:1375895636780:dw|

  13. ganeshie8
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    |dw:1375895683012:dw|

  14. ganeshie8
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    thats opposite side eh ?

  15. highschoolmom2010
    • 2 years ago
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    yes thats the opposite

  16. ganeshie8
    • 2 years ago
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    wat about 17, wat is it

  17. phi
    • 2 years ago
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    Here is khan working this type of problem http://www.khanacademy.org/math/trigonometry/basic-trigonometry/basic_trig_ratios/v/example--trig-to-solve-the-sides-and-angles-of-a-right-triangle

  18. phi
    • 2 years ago
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    the hypotenuse is opposite the 90º angle. 17 in (a) is the hypotenuse

  19. highschoolmom2010
    • 2 years ago
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    idk what i was thinking it is hyp,

  20. highschoolmom2010
    • 2 years ago
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    this is really confusing

  21. highschoolmom2010
    • 2 years ago
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    @phi i think i got it |dw:1375975866022:dw| \[\sin 54=\frac{ w }{ 17 }\] \[17*\sin 54=\frac{ w }{ 17 }*17\] \[17\sin54=W\] \[W \approx13.8\]

  22. phi
    • 2 years ago
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    yes.

  23. highschoolmom2010
    • 2 years ago
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    ok now can yall check my b and c part when i get the posted

  24. ganeshie8
    • 2 years ago
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    yea sure. remember this - hypotenuse is the longest side. it wont change no matter which corner u go

  25. phi
    • 2 years ago
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    once you get the idea and stay focused (don't make a dumb mistake) and you know how to work a calculator this stuff is not hard.

  26. highschoolmom2010
    • 2 years ago
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    |dw:1375976336846:dw| this one i get mixed up \[\tan \frac{ 1.0 }{ W }\] \[W* \tan 28=\frac{ 1.0 }{ W }*W\] \[W \tan 28=1.0\] im unsure of how to do that

  27. phi
    • 2 years ago
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    remember that tan(28) is some (ugly) number which a calculator will know. divide both sides by tan(28)

  28. phi
    • 2 years ago
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    you get w= 1/tan(28)

  29. highschoolmom2010
    • 2 years ago
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    but when i plug in 1/tan(28) the calculator gave me this -3.55328644813

  30. phi
    • 2 years ago
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    your calculator is in "radian mode" you want to be in degree mode

  31. ganeshie8
    • 2 years ago
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    change the mode to degrees

  32. highschoolmom2010
    • 2 years ago
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    ohh ok

  33. highschoolmom2010
    • 2 years ago
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    1.88

  34. highschoolmom2010
    • 2 years ago
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    so approx 1.9

  35. phi
    • 2 years ago
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    yes

  36. highschoolmom2010
    • 2 years ago
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    horray ok and for the last pne

  37. highschoolmom2010
    • 2 years ago
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    |dw:1375977256082:dw| \[\cos(33)=\frac{ w }{ 4.5 }\] \[4.5*\cos(33)=\frac{ w }{ 4.5 }*4.5\] \[4.5\cos(33)=W\] \[W \approx3.8\]

  38. highschoolmom2010
    • 2 years ago
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    ty @phi & @ganeshie8 for the help

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