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highschoolmom2010
using Sin, Cos, Tan For parts (a)–(c), find the value of w to the nearest tenth
familiar wid SOH-CAH-TOA ?
you are zipping along... now learning trig ?
when you get time (if you want to see more info) http://www.khanacademy.org/math/trigonometry/basic-trigonometry/basic_trig_ratios/v/basic-trigonometry
not really understand but @phi that is in my lessons for geometry
yeah usually they put trig ratios right after similar triangles
i can kinda do it not really well yet
khan explains it better than trying to learn it from reading explanations here. This site is better for going over your problems
ok ok so watch his videos first :D
|dw:1375894551709:dw| doesnt really show how to do this @ganeshie8
first go to the 54 degree corner and stare at the triangle from there
|dw:1375895636780:dw|
|dw:1375895683012:dw|
thats opposite side eh ?
yes thats the opposite
wat about 17, wat is it
Here is khan working this type of problem http://www.khanacademy.org/math/trigonometry/basic-trigonometry/basic_trig_ratios/v/example--trig-to-solve-the-sides-and-angles-of-a-right-triangle
the hypotenuse is opposite the 90º angle. 17 in (a) is the hypotenuse
idk what i was thinking it is hyp,
this is really confusing
@phi i think i got it |dw:1375975866022:dw| \[\sin 54=\frac{ w }{ 17 }\] \[17*\sin 54=\frac{ w }{ 17 }*17\] \[17\sin54=W\] \[W \approx13.8\]
ok now can yall check my b and c part when i get the posted
yea sure. remember this - hypotenuse is the longest side. it wont change no matter which corner u go
once you get the idea and stay focused (don't make a dumb mistake) and you know how to work a calculator this stuff is not hard.
|dw:1375976336846:dw| this one i get mixed up \[\tan \frac{ 1.0 }{ W }\] \[W* \tan 28=\frac{ 1.0 }{ W }*W\] \[W \tan 28=1.0\] im unsure of how to do that
remember that tan(28) is some (ugly) number which a calculator will know. divide both sides by tan(28)
but when i plug in 1/tan(28) the calculator gave me this -3.55328644813
your calculator is in "radian mode" you want to be in degree mode
change the mode to degrees
so approx 1.9
horray ok and for the last pne
|dw:1375977256082:dw| \[\cos(33)=\frac{ w }{ 4.5 }\] \[4.5*\cos(33)=\frac{ w }{ 4.5 }*4.5\] \[4.5\cos(33)=W\] \[W \approx3.8\]
ty @phi & @ganeshie8 for the help