highschoolmom2010
  • highschoolmom2010
using Sin, Cos, Tan For parts (a)–(c), find the value of w to the nearest tenth
Mathematics
chestercat
  • chestercat
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highschoolmom2010
  • highschoolmom2010
1 Attachment
ganeshie8
  • ganeshie8
familiar wid SOH-CAH-TOA ?
phi
  • phi
you are zipping along... now learning trig ?

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phi
  • phi
when you get time (if you want to see more info) http://www.khanacademy.org/math/trigonometry/basic-trigonometry/basic_trig_ratios/v/basic-trigonometry
highschoolmom2010
  • highschoolmom2010
not really understand but @phi that is in my lessons for geometry
ganeshie8
  • ganeshie8
yeah usually they put trig ratios right after similar triangles
highschoolmom2010
  • highschoolmom2010
i can kinda do it not really well yet
phi
  • phi
khan explains it better than trying to learn it from reading explanations here. This site is better for going over your problems
highschoolmom2010
  • highschoolmom2010
ok ok so watch his videos first :D
highschoolmom2010
  • highschoolmom2010
|dw:1375894551709:dw| doesnt really show how to do this @ganeshie8
ganeshie8
  • ganeshie8
first go to the 54 degree corner and stare at the triangle from there
ganeshie8
  • ganeshie8
|dw:1375895636780:dw|
ganeshie8
  • ganeshie8
|dw:1375895683012:dw|
ganeshie8
  • ganeshie8
thats opposite side eh ?
highschoolmom2010
  • highschoolmom2010
yes thats the opposite
ganeshie8
  • ganeshie8
wat about 17, wat is it
phi
  • phi
Here is khan working this type of problem http://www.khanacademy.org/math/trigonometry/basic-trigonometry/basic_trig_ratios/v/example--trig-to-solve-the-sides-and-angles-of-a-right-triangle
phi
  • phi
the hypotenuse is opposite the 90º angle. 17 in (a) is the hypotenuse
highschoolmom2010
  • highschoolmom2010
idk what i was thinking it is hyp,
highschoolmom2010
  • highschoolmom2010
this is really confusing
highschoolmom2010
  • highschoolmom2010
@phi i think i got it |dw:1375975866022:dw| \[\sin 54=\frac{ w }{ 17 }\] \[17*\sin 54=\frac{ w }{ 17 }*17\] \[17\sin54=W\] \[W \approx13.8\]
phi
  • phi
yes.
highschoolmom2010
  • highschoolmom2010
ok now can yall check my b and c part when i get the posted
ganeshie8
  • ganeshie8
yea sure. remember this - hypotenuse is the longest side. it wont change no matter which corner u go
phi
  • phi
once you get the idea and stay focused (don't make a dumb mistake) and you know how to work a calculator this stuff is not hard.
highschoolmom2010
  • highschoolmom2010
|dw:1375976336846:dw| this one i get mixed up \[\tan \frac{ 1.0 }{ W }\] \[W* \tan 28=\frac{ 1.0 }{ W }*W\] \[W \tan 28=1.0\] im unsure of how to do that
phi
  • phi
remember that tan(28) is some (ugly) number which a calculator will know. divide both sides by tan(28)
phi
  • phi
you get w= 1/tan(28)
highschoolmom2010
  • highschoolmom2010
but when i plug in 1/tan(28) the calculator gave me this -3.55328644813
phi
  • phi
your calculator is in "radian mode" you want to be in degree mode
ganeshie8
  • ganeshie8
change the mode to degrees
highschoolmom2010
  • highschoolmom2010
ohh ok
highschoolmom2010
  • highschoolmom2010
1.88
highschoolmom2010
  • highschoolmom2010
so approx 1.9
phi
  • phi
yes
highschoolmom2010
  • highschoolmom2010
horray ok and for the last pne
highschoolmom2010
  • highschoolmom2010
|dw:1375977256082:dw| \[\cos(33)=\frac{ w }{ 4.5 }\] \[4.5*\cos(33)=\frac{ w }{ 4.5 }*4.5\] \[4.5\cos(33)=W\] \[W \approx3.8\]
highschoolmom2010
  • highschoolmom2010
ty @phi & @ganeshie8 for the help

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