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blahblahblah375
 one year ago
Samantha and Jake are training for a marathon.In the first week of training Jake ran an average of 7.75 minutes per mile. Later, in week four of training he ran an average of 7.00 minutes per mile. In the first week of training Samantha ran an average of 8.10 minutes per mile. Later, in week six of training she ran an average of 6.60 minutes per mile.
In which week will Jake and Samantha have the same average minutes per mile?
If Jake and Samantha continue to train until week 33, what will their times be
blahblahblah375
 one year ago
Samantha and Jake are training for a marathon.In the first week of training Jake ran an average of 7.75 minutes per mile. Later, in week four of training he ran an average of 7.00 minutes per mile. In the first week of training Samantha ran an average of 8.10 minutes per mile. Later, in week six of training she ran an average of 6.60 minutes per mile. In which week will Jake and Samantha have the same average minutes per mile? If Jake and Samantha continue to train until week 33, what will their times be

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blahblahblah375
 one year ago
Best ResponseYou've already chosen the best response.0how did you figure that out @britbrat4290

britbrat4290
 one year ago
Best ResponseYou've already chosen the best response.1X + 4Y = 32 3X + 10Y = 84 (16/2 , 12/2)........(8 , 6).....My own method I teach my students Mult by 5.......5X + 20Y = 160........20Y = 160  5X Mult by 2.......6X + 20Y = 168........20Y = 168  6X 160  5X = 168  6X..........Add 6X 160 + X = 168...................Subtract 160 X = 8 ANSWER in week 8

blahblahblah375
 one year ago
Best ResponseYou've already chosen the best response.0what about what there times will be at week 33 is there an equation i can do to figure it out?

blahblahblah375
 one year ago
Best ResponseYou've already chosen the best response.0plug what in for x?

britbrat4290
 one year ago
Best ResponseYou've already chosen the best response.1the answer u were trying to find in the begggininng 8

blahblahblah375
 one year ago
Best ResponseYou've already chosen the best response.0but plug it into what
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