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britbrat4290

  • one year ago

Solve the equation on the interval [0, 2π). sin2 x - cos2 x = 0

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  1. britbrat4290
    • one year ago
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    sry no lol

  2. Coolsector
    • one year ago
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    and you should convince yourself why it is fine to divide by cos2x . ( it is fine. )

  3. britbrat4290
    • one year ago
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    wud it b pie/4, pie/6 ?

  4. Coolsector
    • one year ago
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    wait im stupid

  5. Coolsector
    • one year ago
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    tan(2x) = 1 !!

  6. britbrat4290
    • one year ago
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    ??

  7. Coolsector
    • one year ago
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    so the general solution for tan(x) = tan(y) x = y + pi*k so in our case: tan(2x) = tan(pi/4) 2x = pi/4 + pi*k x = pi/8 + (pi/2) * k

  8. britbrat4290
    • one year ago
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    pie/4 just then

  9. Coolsector
    • one year ago
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    no

  10. britbrat4290
    • one year ago
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    u got over 8?

  11. Coolsector
    • one year ago
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    pi/8 , 5pi/8 , 9pi/8 , 13pi/8

  12. Coolsector
    • one year ago
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    i first wrote tan(2x) = 0 which was WRONG

  13. britbrat4290
    • one year ago
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    pi/4, 3pi/4, 5pi/4, 7pi/4

  14. Coolsector
    • one year ago
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    no, x=pi/8 , 5pi/8 , 9pi/8 , 13pi/8

  15. britbrat4290
    • one year ago
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    hmm

  16. Coolsector
    • one year ago
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    wait lol was it :

  17. Coolsector
    • one year ago
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    \[\sin(2x) - \cos(2x) = 0\]

  18. Coolsector
    • one year ago
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    or \[\sin^2(x) - \cos^2(x) = 0\]

  19. Coolsector
    • one year ago
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    cause i solved for the FIRST one

  20. Coolsector
    • one year ago
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    ?

  21. britbrat4290
    • one year ago
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    it said i got it right for the four i picked? weird

  22. Coolsector
    • one year ago
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    but what was the correct question i wrote here two

  23. Coolsector
    • one year ago
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    i think i solved for the wrong one

  24. britbrat4290
    • one year ago
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    im lost sry its ok bc i got it right so its all good :)

  25. Coolsector
    • one year ago
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    cause if the question was : sin^2(x) - cos^2(x) = 0 then we get tan^2(x) = 1 tan(x) = +/-1 so 1. tan(x) = 1 tan(x) = tan(pi/4) x = pi/4 + pi * k x = pi/4 , 5pi/4 2.tan(x) = -1 tan(x) = tan(-pi/4) x = -pi/4 + pi*k x = 3pi/4 , 7pi/4 so : x = pi/4, 3pi/4, 5pi/4, 7pi/4

  26. Coolsector
    • one year ago
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    and i thought it was sin(2x) - cos(2x) = 0

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