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Solve the equation on the interval [0, 2π).
sin2 x  cos2 x = 0
 8 months ago
 8 months ago
Solve the equation on the interval [0, 2π). sin2 x  cos2 x = 0
 8 months ago
 8 months ago

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CoolsectorBest ResponseYou've already chosen the best response.0
and you should convince yourself why it is fine to divide by cos2x . ( it is fine. )
 8 months ago

britbrat4290Best ResponseYou've already chosen the best response.0
wud it b pie/4, pie/6 ?
 8 months ago

CoolsectorBest ResponseYou've already chosen the best response.0
so the general solution for tan(x) = tan(y) x = y + pi*k so in our case: tan(2x) = tan(pi/4) 2x = pi/4 + pi*k x = pi/8 + (pi/2) * k
 8 months ago

CoolsectorBest ResponseYou've already chosen the best response.0
pi/8 , 5pi/8 , 9pi/8 , 13pi/8
 8 months ago

CoolsectorBest ResponseYou've already chosen the best response.0
i first wrote tan(2x) = 0 which was WRONG
 8 months ago

britbrat4290Best ResponseYou've already chosen the best response.0
pi/4, 3pi/4, 5pi/4, 7pi/4
 8 months ago

CoolsectorBest ResponseYou've already chosen the best response.0
no, x=pi/8 , 5pi/8 , 9pi/8 , 13pi/8
 8 months ago

CoolsectorBest ResponseYou've already chosen the best response.0
\[\sin(2x)  \cos(2x) = 0\]
 8 months ago

CoolsectorBest ResponseYou've already chosen the best response.0
or \[\sin^2(x)  \cos^2(x) = 0\]
 8 months ago

CoolsectorBest ResponseYou've already chosen the best response.0
cause i solved for the FIRST one
 8 months ago

britbrat4290Best ResponseYou've already chosen the best response.0
it said i got it right for the four i picked? weird
 8 months ago

CoolsectorBest ResponseYou've already chosen the best response.0
but what was the correct question i wrote here two
 8 months ago

CoolsectorBest ResponseYou've already chosen the best response.0
i think i solved for the wrong one
 8 months ago

britbrat4290Best ResponseYou've already chosen the best response.0
im lost sry its ok bc i got it right so its all good :)
 8 months ago

CoolsectorBest ResponseYou've already chosen the best response.0
cause if the question was : sin^2(x)  cos^2(x) = 0 then we get tan^2(x) = 1 tan(x) = +/1 so 1. tan(x) = 1 tan(x) = tan(pi/4) x = pi/4 + pi * k x = pi/4 , 5pi/4 2.tan(x) = 1 tan(x) = tan(pi/4) x = pi/4 + pi*k x = 3pi/4 , 7pi/4 so : x = pi/4, 3pi/4, 5pi/4, 7pi/4
 8 months ago

CoolsectorBest ResponseYou've already chosen the best response.0
and i thought it was sin(2x)  cos(2x) = 0
 8 months ago
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