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britbrat4290
 2 years ago
Solve the equation on the interval [0, 2π).
sin2 x  cos2 x = 0
britbrat4290
 2 years ago
Solve the equation on the interval [0, 2π). sin2 x  cos2 x = 0

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Coolsector
 2 years ago
Best ResponseYou've already chosen the best response.0and you should convince yourself why it is fine to divide by cos2x . ( it is fine. )

britbrat4290
 2 years ago
Best ResponseYou've already chosen the best response.0wud it b pie/4, pie/6 ?

Coolsector
 2 years ago
Best ResponseYou've already chosen the best response.0so the general solution for tan(x) = tan(y) x = y + pi*k so in our case: tan(2x) = tan(pi/4) 2x = pi/4 + pi*k x = pi/8 + (pi/2) * k

Coolsector
 2 years ago
Best ResponseYou've already chosen the best response.0pi/8 , 5pi/8 , 9pi/8 , 13pi/8

Coolsector
 2 years ago
Best ResponseYou've already chosen the best response.0i first wrote tan(2x) = 0 which was WRONG

britbrat4290
 2 years ago
Best ResponseYou've already chosen the best response.0pi/4, 3pi/4, 5pi/4, 7pi/4

Coolsector
 2 years ago
Best ResponseYou've already chosen the best response.0no, x=pi/8 , 5pi/8 , 9pi/8 , 13pi/8

Coolsector
 2 years ago
Best ResponseYou've already chosen the best response.0\[\sin(2x)  \cos(2x) = 0\]

Coolsector
 2 years ago
Best ResponseYou've already chosen the best response.0or \[\sin^2(x)  \cos^2(x) = 0\]

Coolsector
 2 years ago
Best ResponseYou've already chosen the best response.0cause i solved for the FIRST one

britbrat4290
 2 years ago
Best ResponseYou've already chosen the best response.0it said i got it right for the four i picked? weird

Coolsector
 2 years ago
Best ResponseYou've already chosen the best response.0but what was the correct question i wrote here two

Coolsector
 2 years ago
Best ResponseYou've already chosen the best response.0i think i solved for the wrong one

britbrat4290
 2 years ago
Best ResponseYou've already chosen the best response.0im lost sry its ok bc i got it right so its all good :)

Coolsector
 2 years ago
Best ResponseYou've already chosen the best response.0cause if the question was : sin^2(x)  cos^2(x) = 0 then we get tan^2(x) = 1 tan(x) = +/1 so 1. tan(x) = 1 tan(x) = tan(pi/4) x = pi/4 + pi * k x = pi/4 , 5pi/4 2.tan(x) = 1 tan(x) = tan(pi/4) x = pi/4 + pi*k x = 3pi/4 , 7pi/4 so : x = pi/4, 3pi/4, 5pi/4, 7pi/4

Coolsector
 2 years ago
Best ResponseYou've already chosen the best response.0and i thought it was sin(2x)  cos(2x) = 0
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