A community for students.
Here's the question you clicked on:
 0 viewing
britbrat4290
 one year ago
Solve the equation on the interval [0, 2π).
sin2 x  cos2 x = 0
britbrat4290
 one year ago
Solve the equation on the interval [0, 2π). sin2 x  cos2 x = 0

This Question is Closed

Coolsector
 one year ago
Best ResponseYou've already chosen the best response.0and you should convince yourself why it is fine to divide by cos2x . ( it is fine. )

britbrat4290
 one year ago
Best ResponseYou've already chosen the best response.0wud it b pie/4, pie/6 ?

Coolsector
 one year ago
Best ResponseYou've already chosen the best response.0so the general solution for tan(x) = tan(y) x = y + pi*k so in our case: tan(2x) = tan(pi/4) 2x = pi/4 + pi*k x = pi/8 + (pi/2) * k

Coolsector
 one year ago
Best ResponseYou've already chosen the best response.0pi/8 , 5pi/8 , 9pi/8 , 13pi/8

Coolsector
 one year ago
Best ResponseYou've already chosen the best response.0i first wrote tan(2x) = 0 which was WRONG

britbrat4290
 one year ago
Best ResponseYou've already chosen the best response.0pi/4, 3pi/4, 5pi/4, 7pi/4

Coolsector
 one year ago
Best ResponseYou've already chosen the best response.0no, x=pi/8 , 5pi/8 , 9pi/8 , 13pi/8

Coolsector
 one year ago
Best ResponseYou've already chosen the best response.0\[\sin(2x)  \cos(2x) = 0\]

Coolsector
 one year ago
Best ResponseYou've already chosen the best response.0or \[\sin^2(x)  \cos^2(x) = 0\]

Coolsector
 one year ago
Best ResponseYou've already chosen the best response.0cause i solved for the FIRST one

britbrat4290
 one year ago
Best ResponseYou've already chosen the best response.0it said i got it right for the four i picked? weird

Coolsector
 one year ago
Best ResponseYou've already chosen the best response.0but what was the correct question i wrote here two

Coolsector
 one year ago
Best ResponseYou've already chosen the best response.0i think i solved for the wrong one

britbrat4290
 one year ago
Best ResponseYou've already chosen the best response.0im lost sry its ok bc i got it right so its all good :)

Coolsector
 one year ago
Best ResponseYou've already chosen the best response.0cause if the question was : sin^2(x)  cos^2(x) = 0 then we get tan^2(x) = 1 tan(x) = +/1 so 1. tan(x) = 1 tan(x) = tan(pi/4) x = pi/4 + pi * k x = pi/4 , 5pi/4 2.tan(x) = 1 tan(x) = tan(pi/4) x = pi/4 + pi*k x = 3pi/4 , 7pi/4 so : x = pi/4, 3pi/4, 5pi/4, 7pi/4

Coolsector
 one year ago
Best ResponseYou've already chosen the best response.0and i thought it was sin(2x)  cos(2x) = 0
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.