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Solve the triangle. Round lengths to the nearest tenth and angle measures to the nearest degree. a = 7, b = 7, c = 5
A. A = 70°, B = 70°, C = 40°
B. A = 69°, B = 69°, C = 42°
C. A = 42°, B = 69°, C = 69°
D. A = 69°, B = 42°, C = 69°
 8 months ago
 8 months ago
Solve the triangle. Round lengths to the nearest tenth and angle measures to the nearest degree. a = 7, b = 7, c = 5 A. A = 70°, B = 70°, C = 40° B. A = 69°, B = 69°, C = 42° C. A = 42°, B = 69°, C = 69° D. A = 69°, B = 42°, C = 69°
 8 months ago
 8 months ago

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CoolsectorBest ResponseYou've already chosen the best response.1
dw:1375999433432:dw
 8 months ago

CoolsectorBest ResponseYou've already chosen the best response.1
law of cosines for angle C: c^2 = a^2 + b^2  2abcosC 25 = 49 + 49  2 * 49 * cosC > cosC = 0.7448979... C = 41.85 > C = 42 degrees now for A and B : A+B+C =180 A+B = 180  42 A+B = 138 since A = B we can find them : 2A = 138 A = B = 69 ANSWER IS B :)
 8 months ago
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