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Factor the polynomial: 54k^2-24

Mathematics
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hint: 54k^2 - 24 6(9k^2 - 4)
Where did you get the 9k^2 in the second line?

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Other answers:

I factored out 6 from the expression
54k^2 - 24 6*9k^2 - 6*4 6(9k^2 - 4) .. using the distributive property
@jim_thompson5910 oh okay I get it, but then there's no number that multipies to give -4 and adds to 9? thats where im stuck at
from here, you would use the difference of squares rule to factor
and 9k^2 - 4 is really 9k^2 + 0k - 4 so you need to find two numbers that multiply to 9*(-4) = -36 and add to 0, then you factor by grouping or you can use the difference of squares rule to factor
the difference of squares rule?
difference of squares a^2 - b^2 = (a - b)(a+b)
ex: 25x^2 - 49 (5x)^2 - (7)^2 (5x - 7)(5x + 7) So 25x^2 - 49 factors to (5x - 7)(5x + 7)
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im sorry im still confuse by this
basically it has to do with common factors
did you see my factoring example with 25x^2 - 49
so use that to factor 9k^2 - 4
Following your example so far I've got (3K)^2-(2)^2
keep going
I got (3x-2)(3x-2) ?? @jim_thompson5910
close, very close
but not quite
where did i go wrong?
the difference of squares rule is a^2 - b^2 = (a - b)(a+b)
notice how it's minus, then plus (not two minuses)
it's NOT a^2 - b^2 = (a - b)(a-b)
so then its (3x-2)(3x+2)
good
the final answer is 6(3k-2)(3k+2)

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