I forgot how to factorise this! :(
3x^2 +2xy - 8y^2 - 8x +14y-3

- AonZ

I forgot how to factorise this! :(
3x^2 +2xy - 8y^2 - 8x +14y-3

- schrodinger

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- anonymous

Is this your equation? \[3x^2 +2xy - 8y^2 - 8x +14y-3\]

- AonZ

yes

- anonymous

Sorry, I was trying to get my question answered.. Anyways! What do we know? We know that the following can be factored out:
\[x^2\]\[8y^2\]\[14\]
I left out 3 and why because they can only be only be factored out by 1.

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- anonymous

Not "why". I meant "y"

- AonZ

umm ok...

- anonymous

Am I not making any sense? damn

- AonZ

for some reason i cant factorise this question :/
i dont see taking out these common factors to be any help...

- AonZ

i know its possible to factorise this but i ahve no idea how
http://www.wolframalpha.com/input/?i=factorize+3x%5E2+%2B2xy+-+8y%5E2+-+8x+%2B14y-3

- anonymous

It will! Promise.

- AonZ

umm, what method of factorising is this?

- anonymous

REVERSE FOIL
Starting with 3x^2 and 8y^2, what can they be factored into?

- anonymous

3 and 1, x and x
2 and 4, y and y

- AonZ

sorry, but i dont understand what your talking about :/

- anonymous

\[3x \times x = 3x^2\]\[2y \times 4y = 8y^2\] Is that not correct?

- AonZ

yes thats correct

- anonymous

But its a negative so \[-4y \times 2y = -8y^2\]

- AonZ

ok

- anonymous

But really from that link you posted, you can take out \[(x+2y-3)\]
From the this you can take out x
\[3x^2 + 2xy - 8x\]
From this you can factor out 2y \[2xy - 8y^2 +14y\]
And lastly -3\[-3\]

- anonymous

...."you can factor out"....

- anonymous

I guess you can I tried to find the greatest common factor in each, instead of reverse foil. Reverse FOIL is mostly for trinomials..

- AonZ

mhm i tried that. Btw i never done reverse foil before so is there any other way?

- AonZ

is it possible if you find the greatest common factor?

- anonymous

Yes. I just showed you...
Also some methods are:
- Number of Terms
- Factor Out the GCF First
- Reversing FOIL
- Guess and Check

- anonymous

Its possible because that is what I did. For your x, you can factor out x ONLY because 3 is not a factor of 8. Also the lowest variable is x in all three.
\[3x^2+2xyâ8x\]

- AonZ

|dw:1376184367770:dw|

- anonymous

you forgot to completely factor out \[( 8x^2 - 14y)\]

- AonZ

|dw:1376184611607:dw|

- anonymous

Also, this equation is an alternate form of your polynomial, not your polynomial factored out... Besides did you mean to write this instead?\[x (3 x+2 y-8)+(14-8 y) y-3\]

- AonZ

mhm yea

- anonymous

Its okay :)

- anonymous

Lets try this again!
Take out your GCF from your polynomial....
\[3x^2 +2xy - 8y^2 - 8x +14y - 3\]

- AonZ

not sure how...

- anonymous

X, Y and your constant are separate cases. Like what I wrote if you scroll up.

- anonymous

Let me try again! Here is your GCF, right? \[(x+2y â 3)\]
When it comes to your x variables, only x can be factored out since 3 is not a factor of 8 even thought 2 is. Also you can't factor out x^2 because each monomial does not x^2. They all have at least one. \[3x^2 + 2xy â 8x\] Also these monomials are the only ones with an "x"

- AonZ

still dont get how you got ur GCF...

- anonymous

When it come to your y variables, you can factor out 2y because 2 is the greatest common factor.
\[2xyâ8y^2+14y\]
And lastly for -3. It is the only constant. So when factoring, all you will use is (1) (-3)
\[â3\]

- anonymous

Do you know what the term GCF is? GREATEST COMMON FACTOR

- AonZ

yea... but how did you get it...

- anonymous

I thought I just showed you and explained it to you..

- anonymous

EXAMPLE: What are the factors and GCF for these numbers?
2 - 1, 2
3 - 1, 3
12 - 1, 2, 3, 4, 6, 12
The GCF for these is 1.

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