mathcalculus
HELP: Determine the values of where the tangent line is horizontal for the function:



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mathcalculus
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zzr0ck3r
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take the derivative, and set it equal to zero

mathcalculus
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then plug into original function?

zzr0ck3r
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nope, it wants x values, so solve for = 0, and that's your answer

mathcalculus
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oh ok.

zzr0ck3r
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example
f(x) = x^2 + 2x
f'(x) = 2x+2
2x+2 = 0
x = 1
so f(x) has horizontal tangent at x = 1

mathcalculus
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@zzr0ck3r thank you=]

zzr0ck3r
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np

zzr0ck3r
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I will note that in most cases when they say "value" that implies y, but in this situation they said "x value".

mathcalculus
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to take the derivative: we must use the power and quotient rule for this question right?

mathcalculus
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i missed up on something, hats not coming out right..