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mathcalculus

HELP: Determine the values of where the tangent line is horizontal for the function:

  • 8 months ago
  • 8 months ago

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  1. mathcalculus
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    • 8 months ago
  2. zzr0ck3r
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    take the derivative, and set it equal to zero

    • 8 months ago
  3. mathcalculus
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    then plug into original function?

    • 8 months ago
  4. zzr0ck3r
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    nope, it wants x values, so solve for = 0, and that's your answer

    • 8 months ago
  5. mathcalculus
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    oh ok.

    • 8 months ago
  6. zzr0ck3r
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    example f(x) = x^2 + 2x f'(x) = 2x+2 2x+2 = 0 x = -1 so f(x) has horizontal tangent at x = -1

    • 8 months ago
  7. mathcalculus
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    @zzr0ck3r thank you=]

    • 8 months ago
  8. zzr0ck3r
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    np

    • 8 months ago
  9. zzr0ck3r
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    I will note that in most cases when they say "value" that implies y, but in this situation they said "x value".

    • 8 months ago
  10. mathcalculus
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    to take the derivative: we must use the power and quotient rule for this question right?

    • 8 months ago
  11. mathcalculus
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    i missed up on something, hats not coming out right..

    • 8 months ago
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