anonymous
  • anonymous
mathcalculus HELP: Determine the values of where the tangent line is horizontal for the function:
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
anonymous
  • anonymous
i know i have to find the derivative and set it to zero but it's not coming out to be correct. can anyone help me
anonymous
  • anonymous
so i did 3x^2-6x-4=0

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anonymous
  • anonymous
i tried to use the quadratic formula and got sqrt(21)+3/3
anonymous
  • anonymous
+ or - sqrt(21)+3/3
anonymous
  • anonymous
also aka 2.52753...
dumbcow
  • dumbcow
derivative seems correct
anonymous
  • anonymous
to find what x = to... ?
anonymous
  • anonymous
i used quadratic formula
anonymous
  • anonymous
@dumbcow dont i have to do that to find x??
anonymous
  • anonymous
im getting it wrong,
dumbcow
  • dumbcow
yes everything looks correct to me...do they want exact or decimal answer?
dumbcow
  • dumbcow
http://www.wolframalpha.com/input/?i=3x%5E2-6x-4%3D0
anonymous
  • anonymous
can i use quadratic formula for ths one?
anonymous
  • anonymous
@dumbcow
anonymous
  • anonymous
??
anonymous
  • anonymous
????????????????????????
dumbcow
  • dumbcow
yes of course you use quadratic formula...thats how you got your answer that i said looked correct
anonymous
  • anonymous
im not getting that using quadratic formula
anonymous
  • anonymous
im getting something totally different and wrong
dumbcow
  • dumbcow
\[x = \frac{3 \pm \sqrt{21}}{3}\]
anonymous
  • anonymous
yes! but from 6+2*sqrt(21)/6?
anonymous
  • anonymous
shouldnt it be 1+ or - sqrt 21/3
dumbcow
  • dumbcow
same thing, just a matter of splitting up fraction or keeping it as single fraction
anonymous
  • anonymous
no it's not because the answer is 1+ sqrt (7/3) gives me 2.52753 and 1+sqrt 21/3 gives me 1.86086!
anonymous
  • anonymous
@dumbcow
dumbcow
  • dumbcow
hmm \[\frac{\sqrt{7}}{\sqrt{3}} = \frac{\sqrt{21}}{3} \]
anonymous
  • anonymous
hmmm?
anonymous
  • anonymous
@dumbcow
anonymous
  • anonymous
try it on a calculator.
dumbcow
  • dumbcow
http://www.wolframalpha.com/input/?i=1%2Bsqrt%287%2F3%29+%2C+1%2Bsqrt%2821%29%2F3
dumbcow
  • dumbcow
oh you added the "1" before dividing by "3"
anonymous
  • anonymous
okay from my answer.... not the internet.. 6+2 sort(21)/3.... where do i go from there?
dumbcow
  • dumbcow
well it should be a 6 on bottom
anonymous
  • anonymous
no i didn't add anything.
anonymous
  • anonymous
okay sure a 6. i thought it could be a 3 to narrow it down
anonymous
  • anonymous
so 6+or-2sqrt(21)/6
dumbcow
  • dumbcow
i dont see the problem, you posted answer in beginning... " i tried to use the quadratic formula and got sqrt(21)+3/3 "
anonymous
  • anonymous
so it is a 3 in the denominator!
dumbcow
  • dumbcow
\[\frac{6 \pm 2\sqrt{21}}{6} = \frac{2(3 \pm \sqrt{21})}{6} = \frac{3 \pm \sqrt{21}}{3}\]

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