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highschoolmom2010
 3 years ago
find the measure of < x using trigonometric ratios
highschoolmom2010
 3 years ago
find the measure of < x using trigonometric ratios

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highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1@ganeshie8 IM HORRIBLE AT THESE

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.0we'll handle this the same way... SOHCAHTOA go to the angle corner, and figure out given sides as opposite,adjacent and hyp

agent0smith
 3 years ago
Best ResponseYou've already chosen the best response.1Use tangent here. Tanx = opposite/adjacent. What side is opposite angle x? dw:1376249499008:dw \[\Large \tan x = \frac{ \text{opposite} }{\text{adjacent} }\]

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1opposite of <x 8 adjacent to <x 5 hypotenuse unknown

agent0smith
 3 years ago
Best ResponseYou've already chosen the best response.1Hypotenuse we don't need, use tanx = opp/adj.

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1i know i like to list what i know :DD

agent0smith
 3 years ago
Best ResponseYou've already chosen the best response.1That's a good tactic, especially for subjects like physics :)

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1\[\tan(x)=\frac{ 8 }{ 5 }\] \[(5)*\tan x=\frac{ 8 }{ 5 }*(5)\]

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.0nopes ! leave it as it is tanx = 8/5

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.0yes ! just divide the right side, then take inverse tan both sides

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1i am used to having to to that i suppose

agent0smith
 3 years ago
Best ResponseYou've already chosen the best response.1No need for extra work here :P \[\tan(x)=\frac{ 8 }{ 5 }\] so \[x = \tan^{1} \frac{ 8 }{ 5 }\]which you need a calculator for.

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1x\[\approx 58\]

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1so when finding angles like ^^ use tan^1

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.0see, you have tan x = 8/5

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.0you want to find x, so to find x you have to isolate x

agent0smith
 3 years ago
Best ResponseYou've already chosen the best response.1tan^1 is the "opposite" of tan, so you use it to undo it. Just like a square root is the opposite of squared, a square root undoes the squard.

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.0take tan^1 both sides : tan x = 8/5 tan^1 tan x = tan^1 8/5 x = tan^1 8/5

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1oh ok that makes sense :D

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.0left side, tan^1 and tan cancel out

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1TY soo much @agent0smith && @ganeshie8

agent0smith
 3 years ago
Best ResponseYou've already chosen the best response.1If you have sinx = some number, then you'd use sin^1(some number) to undo it. Same for cosx = some number. But make sure you isolate the sinx or cosx, so it's like sinx = ... or cosx = ... ie you can't just do cos^1 of 10cosx = 5, you'd have to divide by 10 first.
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