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highschoolmom2010

  • one year ago

find the measure of < x using trigonometric ratios

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  1. highschoolmom2010
    • one year ago
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  2. highschoolmom2010
    • one year ago
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    @ganeshie8 IM HORRIBLE AT THESE

  3. ganeshie8
    • one year ago
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    we'll handle this the same way... SOH-CAH-TOA go to the angle corner, and figure out given sides as opposite,adjacent and hyp

  4. agent0smith
    • one year ago
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    Use tangent here. Tanx = opposite/adjacent. What side is opposite angle x? |dw:1376249499008:dw| \[\Large \tan x = \frac{ \text{opposite} }{\text{adjacent} }\]

  5. highschoolmom2010
    • one year ago
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    opposite of <x 8 adjacent to <x 5 hypotenuse unknown

  6. agent0smith
    • one year ago
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    Hypotenuse we don't need, use tanx = opp/adj.

  7. highschoolmom2010
    • one year ago
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    i know i like to list what i know :DD

  8. agent0smith
    • one year ago
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    Okay :)

  9. agent0smith
    • one year ago
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    That's a good tactic, especially for subjects like physics :)

  10. highschoolmom2010
    • one year ago
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    \[\tan(x)=\frac{ 8 }{ 5 }\] \[(5)*\tan x=\frac{ 8 }{ 5 }*(5)\]

  11. highschoolmom2010
    • one year ago
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    like that ?

  12. ganeshie8
    • one year ago
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    nopes ! leave it as it is tanx = 8/5

  13. ganeshie8
    • one year ago
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    yes ! just divide the right side, then take inverse tan both sides

  14. highschoolmom2010
    • one year ago
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    i am used to having to to that i suppose

  15. ganeshie8
    • one year ago
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    haha i bet you're !

  16. agent0smith
    • one year ago
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    No need for extra work here :P \[\tan(x)=\frac{ 8 }{ 5 }\] so \[x = \tan^{-1} \frac{ 8 }{ 5 }\]which you need a calculator for.

  17. highschoolmom2010
    • one year ago
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    x\[\approx 58\]

  18. agent0smith
    • one year ago
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    Looks about right!

  19. ganeshie8
    • one year ago
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    right right !

  20. ganeshie8
    • one year ago
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    gw !!

  21. highschoolmom2010
    • one year ago
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    so when finding angles like ^^ use tan^-1

  22. ganeshie8
    • one year ago
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    see, you have tan x = 8/5

  23. ganeshie8
    • one year ago
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    you want to find x, so to find x you have to isolate x

  24. agent0smith
    • one year ago
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    tan^-1 is the "opposite" of tan, so you use it to undo it. Just like a square root is the opposite of squared, a square root undoes the squard.

  25. ganeshie8
    • one year ago
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    take tan^-1 both sides :- tan x = 8/5 tan^-1 tan x = tan^-1 8/5 x = tan^-1 8/5

  26. highschoolmom2010
    • one year ago
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    oh ok that makes sense :D

  27. ganeshie8
    • one year ago
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    left side, tan^-1 and tan cancel out

  28. highschoolmom2010
    • one year ago
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    TY soo much @agent0smith && @ganeshie8

  29. ganeshie8
    • one year ago
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    np :)

  30. agent0smith
    • one year ago
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    If you have sinx = some number, then you'd use sin^-1(some number) to undo it. Same for cosx = some number. But make sure you isolate the sinx or cosx, so it's like sinx = ... or cosx = ... ie you can't just do cos^-1 of 10cosx = 5, you'd have to divide by 10 first.

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