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highschoolmom2010
Group Title
find the measure of < x using trigonometric ratios
 11 months ago
 11 months ago
highschoolmom2010 Group Title
find the measure of < x using trigonometric ratios
 11 months ago
 11 months ago

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highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
 11 months ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
@ganeshie8 IM HORRIBLE AT THESE
 11 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.0
we'll handle this the same way... SOHCAHTOA go to the angle corner, and figure out given sides as opposite,adjacent and hyp
 11 months ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.1
Use tangent here. Tanx = opposite/adjacent. What side is opposite angle x? dw:1376249499008:dw \[\Large \tan x = \frac{ \text{opposite} }{\text{adjacent} }\]
 11 months ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
opposite of <x 8 adjacent to <x 5 hypotenuse unknown
 11 months ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.1
Hypotenuse we don't need, use tanx = opp/adj.
 11 months ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
i know i like to list what i know :DD
 11 months ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.1
Okay :)
 11 months ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.1
That's a good tactic, especially for subjects like physics :)
 11 months ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
\[\tan(x)=\frac{ 8 }{ 5 }\] \[(5)*\tan x=\frac{ 8 }{ 5 }*(5)\]
 11 months ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
like that ?
 11 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.0
nopes ! leave it as it is tanx = 8/5
 11 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.0
yes ! just divide the right side, then take inverse tan both sides
 11 months ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
i am used to having to to that i suppose
 11 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.0
haha i bet you're !
 11 months ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.1
No need for extra work here :P \[\tan(x)=\frac{ 8 }{ 5 }\] so \[x = \tan^{1} \frac{ 8 }{ 5 }\]which you need a calculator for.
 11 months ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
x\[\approx 58\]
 11 months ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.1
Looks about right!
 11 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.0
right right !
 11 months ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
so when finding angles like ^^ use tan^1
 11 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.0
see, you have tan x = 8/5
 11 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.0
you want to find x, so to find x you have to isolate x
 11 months ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.1
tan^1 is the "opposite" of tan, so you use it to undo it. Just like a square root is the opposite of squared, a square root undoes the squard.
 11 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.0
take tan^1 both sides : tan x = 8/5 tan^1 tan x = tan^1 8/5 x = tan^1 8/5
 11 months ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
oh ok that makes sense :D
 11 months ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.0
left side, tan^1 and tan cancel out
 11 months ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.1
TY soo much @agent0smith && @ganeshie8
 11 months ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.1
If you have sinx = some number, then you'd use sin^1(some number) to undo it. Same for cosx = some number. But make sure you isolate the sinx or cosx, so it's like sinx = ... or cosx = ... ie you can't just do cos^1 of 10cosx = 5, you'd have to divide by 10 first.
 11 months ago
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