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highschoolmom2010
 one year ago
find the measure of < x using trigonometric ratios
highschoolmom2010
 one year ago
find the measure of < x using trigonometric ratios

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highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.1@ganeshie8 IM HORRIBLE AT THESE

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0we'll handle this the same way... SOHCAHTOA go to the angle corner, and figure out given sides as opposite,adjacent and hyp

agent0smith
 one year ago
Best ResponseYou've already chosen the best response.1Use tangent here. Tanx = opposite/adjacent. What side is opposite angle x? dw:1376249499008:dw \[\Large \tan x = \frac{ \text{opposite} }{\text{adjacent} }\]

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.1opposite of <x 8 adjacent to <x 5 hypotenuse unknown

agent0smith
 one year ago
Best ResponseYou've already chosen the best response.1Hypotenuse we don't need, use tanx = opp/adj.

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.1i know i like to list what i know :DD

agent0smith
 one year ago
Best ResponseYou've already chosen the best response.1That's a good tactic, especially for subjects like physics :)

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.1\[\tan(x)=\frac{ 8 }{ 5 }\] \[(5)*\tan x=\frac{ 8 }{ 5 }*(5)\]

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0nopes ! leave it as it is tanx = 8/5

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0yes ! just divide the right side, then take inverse tan both sides

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.1i am used to having to to that i suppose

agent0smith
 one year ago
Best ResponseYou've already chosen the best response.1No need for extra work here :P \[\tan(x)=\frac{ 8 }{ 5 }\] so \[x = \tan^{1} \frac{ 8 }{ 5 }\]which you need a calculator for.

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.1x\[\approx 58\]

agent0smith
 one year ago
Best ResponseYou've already chosen the best response.1Looks about right!

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.1so when finding angles like ^^ use tan^1

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0see, you have tan x = 8/5

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0you want to find x, so to find x you have to isolate x

agent0smith
 one year ago
Best ResponseYou've already chosen the best response.1tan^1 is the "opposite" of tan, so you use it to undo it. Just like a square root is the opposite of squared, a square root undoes the squard.

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0take tan^1 both sides : tan x = 8/5 tan^1 tan x = tan^1 8/5 x = tan^1 8/5

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.1oh ok that makes sense :D

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0left side, tan^1 and tan cancel out

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.1TY soo much @agent0smith && @ganeshie8

agent0smith
 one year ago
Best ResponseYou've already chosen the best response.1If you have sinx = some number, then you'd use sin^1(some number) to undo it. Same for cosx = some number. But make sure you isolate the sinx or cosx, so it's like sinx = ... or cosx = ... ie you can't just do cos^1 of 10cosx = 5, you'd have to divide by 10 first.
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