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highschoolmom2010Best ResponseYou've already chosen the best response.1
@ganeshie8 IM HORRIBLE AT THESE
 8 months ago

ganeshie8Best ResponseYou've already chosen the best response.0
we'll handle this the same way... SOHCAHTOA go to the angle corner, and figure out given sides as opposite,adjacent and hyp
 8 months ago

agent0smithBest ResponseYou've already chosen the best response.1
Use tangent here. Tanx = opposite/adjacent. What side is opposite angle x? dw:1376249499008:dw \[\Large \tan x = \frac{ \text{opposite} }{\text{adjacent} }\]
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.1
opposite of <x 8 adjacent to <x 5 hypotenuse unknown
 8 months ago

agent0smithBest ResponseYou've already chosen the best response.1
Hypotenuse we don't need, use tanx = opp/adj.
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.1
i know i like to list what i know :DD
 8 months ago

agent0smithBest ResponseYou've already chosen the best response.1
That's a good tactic, especially for subjects like physics :)
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.1
\[\tan(x)=\frac{ 8 }{ 5 }\] \[(5)*\tan x=\frac{ 8 }{ 5 }*(5)\]
 8 months ago

ganeshie8Best ResponseYou've already chosen the best response.0
nopes ! leave it as it is tanx = 8/5
 8 months ago

ganeshie8Best ResponseYou've already chosen the best response.0
yes ! just divide the right side, then take inverse tan both sides
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.1
i am used to having to to that i suppose
 8 months ago

agent0smithBest ResponseYou've already chosen the best response.1
No need for extra work here :P \[\tan(x)=\frac{ 8 }{ 5 }\] so \[x = \tan^{1} \frac{ 8 }{ 5 }\]which you need a calculator for.
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.1
x\[\approx 58\]
 8 months ago

agent0smithBest ResponseYou've already chosen the best response.1
Looks about right!
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.1
so when finding angles like ^^ use tan^1
 8 months ago

ganeshie8Best ResponseYou've already chosen the best response.0
see, you have tan x = 8/5
 8 months ago

ganeshie8Best ResponseYou've already chosen the best response.0
you want to find x, so to find x you have to isolate x
 8 months ago

agent0smithBest ResponseYou've already chosen the best response.1
tan^1 is the "opposite" of tan, so you use it to undo it. Just like a square root is the opposite of squared, a square root undoes the squard.
 8 months ago

ganeshie8Best ResponseYou've already chosen the best response.0
take tan^1 both sides : tan x = 8/5 tan^1 tan x = tan^1 8/5 x = tan^1 8/5
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.1
oh ok that makes sense :D
 8 months ago

ganeshie8Best ResponseYou've already chosen the best response.0
left side, tan^1 and tan cancel out
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.1
TY soo much @agent0smith && @ganeshie8
 8 months ago

agent0smithBest ResponseYou've already chosen the best response.1
If you have sinx = some number, then you'd use sin^1(some number) to undo it. Same for cosx = some number. But make sure you isolate the sinx or cosx, so it's like sinx = ... or cosx = ... ie you can't just do cos^1 of 10cosx = 5, you'd have to divide by 10 first.
 8 months ago
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