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mathcalculus Group Title

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  • one year ago
  • one year ago

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  1. mathcalculus Group Title
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    • one year ago
  2. mathcalculus Group Title
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    how is the answer -7sqrt (6)/t^8?

    • one year ago
  3. mathcalculus Group Title
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    @BangkokGarrett

    • one year ago
  4. mathcalculus Group Title
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    @dan815

    • one year ago
  5. mathcalculus Group Title
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    i tried using the quotient rule .. but that didn't work

    • one year ago
  6. katherine.ok Group Title
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    so find derivative of sqrt(6)*t^-7?

    • one year ago
  7. mathcalculus Group Title
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    also the power rule... so what's next?

    • one year ago
  8. katherine.ok Group Title
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    -7(t^-8)sqrt(6)

    • one year ago
  9. mathcalculus Group Title
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    yes how did you get to the answer?

    • one year ago
  10. katherine.ok Group Title
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    make it first look like sqrt(6)*t^-7

    • one year ago
  11. mathcalculus Group Title
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    why?

    • one year ago
  12. katherine.ok Group Title
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    notice that sqrt (6) is constant. and t^-7 is the variable you are worrying about.

    • one year ago
  13. mathcalculus Group Title
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    can i not use the power rule then quotient rule?

    • one year ago
  14. katherine.ok Group Title
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    because this is simply exponent derivative,you not need to worry about quotient rule , power rule.

    • one year ago
  15. Jhannybean Group Title
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    \[\large f(t) = \frac{\sqrt{6}}{t^7} = \sqrt{6}t^{-7}\]\[\large f'(t) = \sqrt{6} \cdot -7 t^{-7-1} \]\[\large f'(t) = -7 \sqrt{6}t^{-8}\]\[\large f'(t) = \frac{-7\sqrt{6}}{t^8}\]

    • one year ago
  16. katherine.ok Group Title
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    power rule and quotient rule is applicable in more complicated setting where you have f(x)*g(x) .

    • one year ago
  17. mathcalculus Group Title
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    ohhhhhhh. right right. this is just simple derivative

    • one year ago
  18. mathcalculus Group Title
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    okay. thank you!

    • one year ago
  19. Jhannybean Group Title
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    You should know that \[\large \frac{d}{dx} x^{n} =\frac{nx^{n-1}}{n-1}\]

    • one year ago
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