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highschoolmom2010
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Find the values of w and then x. Round lengths to the nearest tenth and angle measures to the nearest degree.
 one year ago
 one year ago
highschoolmom2010 Group Title
Find the values of w and then x. Round lengths to the nearest tenth and angle measures to the nearest degree.
 one year ago
 one year ago

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katherine.ok Group TitleBest ResponseYou've already chosen the best response.3
you have multiple ways. one is to recognize that this is isoceles triangle ( the triangle shape with two equal sides)
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
i saw that to begin with
 one year ago

katherine.ok Group TitleBest ResponseYou've already chosen the best response.3
which makes the right triangle have internal sum of 90+ 42+w= 180.
 one year ago

katherine.ok Group TitleBest ResponseYou've already chosen the best response.3
or does w mean the height?
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
i believe w is height
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
im not entirely sure
 one year ago

katherine.ok Group TitleBest ResponseYou've already chosen the best response.3
then sin42= w/102
 one year ago

katherine.ok Group TitleBest ResponseYou've already chosen the best response.3
and cos 42= (2/x)/102
 one year ago

katherine.ok Group TitleBest ResponseYou've already chosen the best response.3
cos42= (x/2)/102****
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
\[(102)*\sin 42=\frac{ w }{ 102 }*102\] \[102 \sin 42=w\] w\[\approx 68\]
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
so how now that i have found w how do i get x?
 one year ago

katherine.ok Group TitleBest ResponseYou've already chosen the best response.3
cos42= (x/2)/102
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
pythagoras
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
half of \(x\) is \(\sqrt{102^268^2}\)
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
can i have a fraction in the numerator
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
so \(x=2\sqrt{102^268^2}\)
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
http://www.wolframalpha.com/input/?i=2sqrt%28102^268^2%29
 one year ago

jdoe0001 Group TitleBest ResponseYou've already chosen the best response.0
@highschoolmom2010 you can always just use the cosine of 42 degrees you know don't spare functions with your SOH CAH TOA
 one year ago

katherine.ok Group TitleBest ResponseYou've already chosen the best response.3
Satelite using wolfram alpha. LOL hes definitely not highschool student.
 one year ago

katherine.ok Group TitleBest ResponseYou've already chosen the best response.3
cos42=x/204= (x/2)/102 (the one i typed few mins ago)
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
^^confused _
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
@ganeshie8 any help
 one year ago

jdoe0001 Group TitleBest ResponseYou've already chosen the best response.0
\(\bf sin(42^o) = \cfrac{\textit{opposite side}}{\textrm{hypotenuse}} \implies \cfrac{w}{102} \implies \color{blue}{sin(42^o) \times 102} = w\\ cos(42^o) = \cfrac{\textit{adjacent side}}{\textrm{hypotenuse}} \implies \cfrac{\textit{half of "x"}}{102} \implies \color{green}{cos(42^o) \times 102} = \textit{half of "x"}\)
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
\[\cos (42)\rightarrow 65*102\]
 one year ago

jdoe0001 Group TitleBest ResponseYou've already chosen the best response.0
well, if "half of x" = 65, yes
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
ive done confused myself again
 one year ago

jdoe0001 Group TitleBest ResponseYou've already chosen the best response.0
then again, if you already know that x= 65 * 2, you don't have to do the cosine part :)
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
aw heck imma use @satellite73 s method
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
\[\sqrt{108^2+68^2}=10868=40\] \[\sqrt{40}=2\sqrt{10}\]
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
but that doesnt look right
 one year ago

jdoe0001 Group TitleBest ResponseYou've already chosen the best response.0
using the cosine, I get ahemm, something else for "x"
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
i dont understand now to use it with this problem
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
for x
 one year ago

katherine.ok Group TitleBest ResponseYou've already chosen the best response.3
okay wild katherine has appeared.
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
dw:1376262142492:dw
 one year ago

katherine.ok Group TitleBest ResponseYou've already chosen the best response.3
cos42=x/204
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
:( math is really hard for me right now yall
 one year ago

katherine.ok Group TitleBest ResponseYou've already chosen the best response.3
x=204*cos42.
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
ya know that makes it a whole lot easier
 one year ago

katherine.ok Group TitleBest ResponseYou've already chosen the best response.3
now the number should be above 150, which is so much more amazing than just sqrt(40).
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
151.6
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
ty @katherine.ok @satellite73 @jdoe0001
 one year ago
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