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highschoolmom2010
 one year ago
Find the values of w and then x. Round lengths to the nearest tenth and angle measures to the nearest degree.
highschoolmom2010
 one year ago
Find the values of w and then x. Round lengths to the nearest tenth and angle measures to the nearest degree.

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katherine.ok
 one year ago
Best ResponseYou've already chosen the best response.3you have multiple ways. one is to recognize that this is isoceles triangle ( the triangle shape with two equal sides)

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.0i saw that to begin with

katherine.ok
 one year ago
Best ResponseYou've already chosen the best response.3which makes the right triangle have internal sum of 90+ 42+w= 180.

katherine.ok
 one year ago
Best ResponseYou've already chosen the best response.3or does w mean the height?

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.0i believe w is height

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.0im not entirely sure

katherine.ok
 one year ago
Best ResponseYou've already chosen the best response.3then sin42= w/102

katherine.ok
 one year ago
Best ResponseYou've already chosen the best response.3and cos 42= (2/x)/102

katherine.ok
 one year ago
Best ResponseYou've already chosen the best response.3cos42= (x/2)/102****

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.0\[(102)*\sin 42=\frac{ w }{ 102 }*102\] \[102 \sin 42=w\] w\[\approx 68\]

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.0so how now that i have found w how do i get x?

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0half of \(x\) is \(\sqrt{102^268^2}\)

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.0can i have a fraction in the numerator

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0so \(x=2\sqrt{102^268^2}\)

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0@highschoolmom2010 you can always just use the cosine of 42 degrees you know don't spare functions with your SOH CAH TOA

katherine.ok
 one year ago
Best ResponseYou've already chosen the best response.3Satelite using wolfram alpha. LOL hes definitely not highschool student.

katherine.ok
 one year ago
Best ResponseYou've already chosen the best response.3cos42=x/204= (x/2)/102 (the one i typed few mins ago)

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.0^^confused _

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.0@ganeshie8 any help

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0\(\bf sin(42^o) = \cfrac{\textit{opposite side}}{\textrm{hypotenuse}} \implies \cfrac{w}{102} \implies \color{blue}{sin(42^o) \times 102} = w\\ cos(42^o) = \cfrac{\textit{adjacent side}}{\textrm{hypotenuse}} \implies \cfrac{\textit{half of "x"}}{102} \implies \color{green}{cos(42^o) \times 102} = \textit{half of "x"}\)

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.0\[\cos (42)\rightarrow 65*102\]

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0well, if "half of x" = 65, yes

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.0ive done confused myself again

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0then again, if you already know that x= 65 * 2, you don't have to do the cosine part :)

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.0aw heck imma use @satellite73 s method

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.0\[\sqrt{108^2+68^2}=10868=40\] \[\sqrt{40}=2\sqrt{10}\]

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.0but that doesnt look right

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0using the cosine, I get ahemm, something else for "x"

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.0i dont understand now to use it with this problem

katherine.ok
 one year ago
Best ResponseYou've already chosen the best response.3okay wild katherine has appeared.

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.0dw:1376262142492:dw

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.0:( math is really hard for me right now yall

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.0ya know that makes it a whole lot easier

katherine.ok
 one year ago
Best ResponseYou've already chosen the best response.3now the number should be above 150, which is so much more amazing than just sqrt(40).

highschoolmom2010
 one year ago
Best ResponseYou've already chosen the best response.0ty @katherine.ok @satellite73 @jdoe0001
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