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Find the values of w and then x. Round lengths to the nearest tenth and angle measures to the nearest degree.
 8 months ago
 8 months ago
Find the values of w and then x. Round lengths to the nearest tenth and angle measures to the nearest degree.
 8 months ago
 8 months ago

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katherine.okBest ResponseYou've already chosen the best response.3
you have multiple ways. one is to recognize that this is isoceles triangle ( the triangle shape with two equal sides)
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.0
i saw that to begin with
 8 months ago

katherine.okBest ResponseYou've already chosen the best response.3
which makes the right triangle have internal sum of 90+ 42+w= 180.
 8 months ago

katherine.okBest ResponseYou've already chosen the best response.3
or does w mean the height?
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.0
i believe w is height
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.0
im not entirely sure
 8 months ago

katherine.okBest ResponseYou've already chosen the best response.3
then sin42= w/102
 8 months ago

katherine.okBest ResponseYou've already chosen the best response.3
and cos 42= (2/x)/102
 8 months ago

katherine.okBest ResponseYou've already chosen the best response.3
cos42= (x/2)/102****
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.0
\[(102)*\sin 42=\frac{ w }{ 102 }*102\] \[102 \sin 42=w\] w\[\approx 68\]
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.0
so how now that i have found w how do i get x?
 8 months ago

satellite73Best ResponseYou've already chosen the best response.0
half of \(x\) is \(\sqrt{102^268^2}\)
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.0
can i have a fraction in the numerator
 8 months ago

satellite73Best ResponseYou've already chosen the best response.0
so \(x=2\sqrt{102^268^2}\)
 8 months ago

satellite73Best ResponseYou've already chosen the best response.0
http://www.wolframalpha.com/input/?i=2sqrt%28102^268^2%29
 8 months ago

jdoe0001Best ResponseYou've already chosen the best response.0
@highschoolmom2010 you can always just use the cosine of 42 degrees you know don't spare functions with your SOH CAH TOA
 8 months ago

katherine.okBest ResponseYou've already chosen the best response.3
Satelite using wolfram alpha. LOL hes definitely not highschool student.
 8 months ago

katherine.okBest ResponseYou've already chosen the best response.3
cos42=x/204= (x/2)/102 (the one i typed few mins ago)
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.0
^^confused _
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.0
@ganeshie8 any help
 8 months ago

jdoe0001Best ResponseYou've already chosen the best response.0
\(\bf sin(42^o) = \cfrac{\textit{opposite side}}{\textrm{hypotenuse}} \implies \cfrac{w}{102} \implies \color{blue}{sin(42^o) \times 102} = w\\ cos(42^o) = \cfrac{\textit{adjacent side}}{\textrm{hypotenuse}} \implies \cfrac{\textit{half of "x"}}{102} \implies \color{green}{cos(42^o) \times 102} = \textit{half of "x"}\)
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.0
\[\cos (42)\rightarrow 65*102\]
 8 months ago

jdoe0001Best ResponseYou've already chosen the best response.0
well, if "half of x" = 65, yes
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.0
ive done confused myself again
 8 months ago

jdoe0001Best ResponseYou've already chosen the best response.0
then again, if you already know that x= 65 * 2, you don't have to do the cosine part :)
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.0
aw heck imma use @satellite73 s method
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.0
\[\sqrt{108^2+68^2}=10868=40\] \[\sqrt{40}=2\sqrt{10}\]
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.0
but that doesnt look right
 8 months ago

jdoe0001Best ResponseYou've already chosen the best response.0
using the cosine, I get ahemm, something else for "x"
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.0
i dont understand now to use it with this problem
 8 months ago

katherine.okBest ResponseYou've already chosen the best response.3
okay wild katherine has appeared.
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.0
dw:1376262142492:dw
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.0
:( math is really hard for me right now yall
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.0
ya know that makes it a whole lot easier
 8 months ago

katherine.okBest ResponseYou've already chosen the best response.3
now the number should be above 150, which is so much more amazing than just sqrt(40).
 8 months ago

highschoolmom2010Best ResponseYou've already chosen the best response.0
ty @katherine.ok @satellite73 @jdoe0001
 8 months ago
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