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highschoolmom2010
 3 years ago
Find the values of w and then x. Round lengths to the nearest tenth and angle measures to the nearest degree.
highschoolmom2010
 3 years ago
Find the values of w and then x. Round lengths to the nearest tenth and angle measures to the nearest degree.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you have multiple ways. one is to recognize that this is isoceles triangle ( the triangle shape with two equal sides)

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.0i saw that to begin with

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0which makes the right triangle have internal sum of 90+ 42+w= 180.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0or does w mean the height?

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.0i believe w is height

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.0im not entirely sure

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and cos 42= (2/x)/102

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.0\[(102)*\sin 42=\frac{ w }{ 102 }*102\] \[102 \sin 42=w\] w\[\approx 68\]

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.0so how now that i have found w how do i get x?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0half of \(x\) is \(\sqrt{102^268^2}\)

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.0can i have a fraction in the numerator

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so \(x=2\sqrt{102^268^2}\)

jdoe0001
 3 years ago
Best ResponseYou've already chosen the best response.0@highschoolmom2010 you can always just use the cosine of 42 degrees you know don't spare functions with your SOH CAH TOA

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Satelite using wolfram alpha. LOL hes definitely not highschool student.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0cos42=x/204= (x/2)/102 (the one i typed few mins ago)

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.0^^confused _

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.0@ganeshie8 any help

jdoe0001
 3 years ago
Best ResponseYou've already chosen the best response.0\(\bf sin(42^o) = \cfrac{\textit{opposite side}}{\textrm{hypotenuse}} \implies \cfrac{w}{102} \implies \color{blue}{sin(42^o) \times 102} = w\\ cos(42^o) = \cfrac{\textit{adjacent side}}{\textrm{hypotenuse}} \implies \cfrac{\textit{half of "x"}}{102} \implies \color{green}{cos(42^o) \times 102} = \textit{half of "x"}\)

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.0\[\cos (42)\rightarrow 65*102\]

jdoe0001
 3 years ago
Best ResponseYou've already chosen the best response.0well, if "half of x" = 65, yes

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.0ive done confused myself again

jdoe0001
 3 years ago
Best ResponseYou've already chosen the best response.0then again, if you already know that x= 65 * 2, you don't have to do the cosine part :)

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.0aw heck imma use @satellite73 s method

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{108^2+68^2}=10868=40\] \[\sqrt{40}=2\sqrt{10}\]

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.0but that doesnt look right

jdoe0001
 3 years ago
Best ResponseYou've already chosen the best response.0using the cosine, I get ahemm, something else for "x"

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.0i dont understand now to use it with this problem

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay wild katherine has appeared.

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1376262142492:dw

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.0:( math is really hard for me right now yall

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.0ya know that makes it a whole lot easier

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0now the number should be above 150, which is so much more amazing than just sqrt(40).

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.0ty @katherine.ok @satellite73 @jdoe0001
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