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highschoolmom2010
Group Title
The sine, cosine, and tangent ratios each have a reciprocal ratio. The reciprocal ratios are cosecant (csc), secant (sec), and cotangent (cot). use triangle ABC to write the definitions
sec A
csc B
cot B
 one year ago
 one year ago
highschoolmom2010 Group Title
The sine, cosine, and tangent ratios each have a reciprocal ratio. The reciprocal ratios are cosecant (csc), secant (sec), and cotangent (cot). use triangle ABC to write the definitions sec A csc B cot B
 one year ago
 one year ago

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katherine.ok Group TitleBest ResponseYou've already chosen the best response.0
Are you given or have you learned that csc= reciprocal of which , and sec of which , and cot is reciprocal of which?
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
dw:1376262907756:dw not covered in my book so i kinda know a little
 one year ago

katherine.ok Group TitleBest ResponseYou've already chosen the best response.0
csc= sin inverse. cot= tan inverse, sec= cos inverse. (Sorry for the informal uses of words)
 one year ago

katherine.ok Group TitleBest ResponseYou've already chosen the best response.0
So the normal numerator of sin would be denomenator of csc , and etc..
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
so its like flipped
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.1
For the sake of clarity, let's not use "inverse" in this manner. This is a reciprocal. I can see why you used "inverse", but a few lessons down the road, you WILL regret it if you call it that. Pick an Angle!! Let's call it "B". It your drawing, it's one of the acute angles. After that, the definitions require memorization. You will be required to know which side is adjacent to the given acute angle and which side is opposite the given acute angle. \(\sin(B) = \dfrac{m(Opposite\;Side)}{m(Hypotenuse)} = \dfrac{1}{\csc(B)}\) \(\cos(B) = \dfrac{m(Adjacent\;Side)}{m(Hypotenuse)} = \dfrac{1}{\sec(B)}\) \(\tan(B) = \dfrac{m(Opposite\;Side)}{m(Adjacent\;Side)} = \dfrac{1}{\cot(B)}\)
 one year ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.1
SecA = 1/cosA Find cosA first, this will let you find sec A. CosA = adjacent/hypotenuse. dw:1376263854146:dw
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
cos A= 9/15
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
so would the sec A= 15/9?
 one year ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.1
Correct! Now try cscB = 1/sinB Sin = opp/hyp. dw:1376264245185:dw
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
sin (b)=9/15
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
csc=15/9
 one year ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.1
Correct. Now try cotB. cotB = 1/tanB.
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
dw:1376265085663:dw \[\tan (B)=\frac{ 9 }{ 12 }\]
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
cot B= 12/9
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
@agent0smith do i have to simplify ^^
 one year ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.1
Yes, I would.
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
so the cot (b)= 4/3 csc (B)=5/3 sec (B)=5/3
 one year ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.1
Yep :)
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
cool i get it now :D ty
 one year ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.1
Oh except wasn't one of those sec A? secA was 5/3
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
@agent0smith i have A written down lol
 one year ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
ty @agent0smith @tkhunny & @katherine.ok for the help :D
 one year ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.1
Good job :)
 one year ago
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