Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
highschoolmom2010
Group Title
The sine, cosine, and tangent ratios each have a reciprocal ratio. The reciprocal ratios are cosecant (csc), secant (sec), and cotangent (cot). use triangle ABC to write the definitions
sec A
csc B
cot B
 11 months ago
 11 months ago
highschoolmom2010 Group Title
The sine, cosine, and tangent ratios each have a reciprocal ratio. The reciprocal ratios are cosecant (csc), secant (sec), and cotangent (cot). use triangle ABC to write the definitions sec A csc B cot B
 11 months ago
 11 months ago

This Question is Closed

katherine.ok Group TitleBest ResponseYou've already chosen the best response.0
Are you given or have you learned that csc= reciprocal of which , and sec of which , and cot is reciprocal of which?
 11 months ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
dw:1376262907756:dw not covered in my book so i kinda know a little
 11 months ago

katherine.ok Group TitleBest ResponseYou've already chosen the best response.0
csc= sin inverse. cot= tan inverse, sec= cos inverse. (Sorry for the informal uses of words)
 11 months ago

katherine.ok Group TitleBest ResponseYou've already chosen the best response.0
So the normal numerator of sin would be denomenator of csc , and etc..
 11 months ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
so its like flipped
 11 months ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.1
For the sake of clarity, let's not use "inverse" in this manner. This is a reciprocal. I can see why you used "inverse", but a few lessons down the road, you WILL regret it if you call it that. Pick an Angle!! Let's call it "B". It your drawing, it's one of the acute angles. After that, the definitions require memorization. You will be required to know which side is adjacent to the given acute angle and which side is opposite the given acute angle. \(\sin(B) = \dfrac{m(Opposite\;Side)}{m(Hypotenuse)} = \dfrac{1}{\csc(B)}\) \(\cos(B) = \dfrac{m(Adjacent\;Side)}{m(Hypotenuse)} = \dfrac{1}{\sec(B)}\) \(\tan(B) = \dfrac{m(Opposite\;Side)}{m(Adjacent\;Side)} = \dfrac{1}{\cot(B)}\)
 11 months ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.1
SecA = 1/cosA Find cosA first, this will let you find sec A. CosA = adjacent/hypotenuse. dw:1376263854146:dw
 11 months ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
cos A= 9/15
 11 months ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
so would the sec A= 15/9?
 11 months ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.1
Correct! Now try cscB = 1/sinB Sin = opp/hyp. dw:1376264245185:dw
 11 months ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
sin (b)=9/15
 11 months ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
csc=15/9
 11 months ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.1
Correct. Now try cotB. cotB = 1/tanB.
 11 months ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
dw:1376265085663:dw \[\tan (B)=\frac{ 9 }{ 12 }\]
 11 months ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
cot B= 12/9
 11 months ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
@agent0smith do i have to simplify ^^
 11 months ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.1
Yes, I would.
 11 months ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
so the cot (b)= 4/3 csc (B)=5/3 sec (B)=5/3
 11 months ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.1
Yep :)
 11 months ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
cool i get it now :D ty
 11 months ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.1
Oh except wasn't one of those sec A? secA was 5/3
 11 months ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
@agent0smith i have A written down lol
 11 months ago

highschoolmom2010 Group TitleBest ResponseYou've already chosen the best response.0
ty @agent0smith @tkhunny & @katherine.ok for the help :D
 11 months ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.1
Good job :)
 11 months ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.