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isn't it 1/2(6x)^(-1/2)

how does it go from there to the answer: sqrt(6)/2 sqrt(x)

\[\sqrt{6x} = \frac{ 1 }{ 2 }(6x)^{\frac{ -1 }{ 2 }}(6)\]

ok

im no sure about the chain rule its confusing

i know its: [f(g(x))]'= f'(g(x))*g'(x)

no

oh wait, i think so a while ago.

let me open

does it always work?

thanks im going to read it right now

Yeah, just let me know.

ugh i gave it a shot. wrong. :(

How'd it become 1/4?

i did 1/2 *-1/2

huh?

down in the denominator?

can you show me the steps to the answer? just want to see how you did it so i can ask

oh the answer is sqrt (6)/2 sqrt(x)

It's the same thing actually xD

alrigght thanks ! :)))

Mhm, np ^_^ Hope that made sense xD