• anonymous
A substance of unknown mass absorbs 138 kilojoules of energy, going from 298 to 303 Kelvin. If the specific heat of the substance is 7.11 J/g·°C, how much of the substance was present? Answer 3.88 kg 32.3 g 3.88 g 32.3 kg I need help setting up this equation. q = mcΔT 138 = 5*(7.11)triangleT i have this but I feel like its wrong
Chemistry
• Stacey Warren - Expert brainly.com
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SOLVED
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