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Pumpkin890
Group Title
A substance of unknown mass absorbs 138 kilojoules of energy, going from 298 to 303 Kelvin. If the specific heat of the substance is 7.11 J/g·°C, how much of the substance was present?
Answer
3.88 kg
32.3 g
3.88 g
32.3 kg
I need help setting up this equation.
q = mcΔT
138 = 5*(7.11)triangleT
i have this but I feel like its wrong
 11 months ago
 11 months ago
Pumpkin890 Group Title
A substance of unknown mass absorbs 138 kilojoules of energy, going from 298 to 303 Kelvin. If the specific heat of the substance is 7.11 J/g·°C, how much of the substance was present? Answer 3.88 kg 32.3 g 3.88 g 32.3 kg I need help setting up this equation. q = mcΔT 138 = 5*(7.11)triangleT i have this but I feel like its wrong
 11 months ago
 11 months ago

This Question is Closed

TheDoctorRules Group TitleBest ResponseYou've already chosen the best response.1
First you need to convert kilojoules to joules 138*1000=138000 J And you must convert kelvins to celsius 298273=25 C 303273=30 Now 3025= 5 So your equation is now 138000=x * 7.11 * 5 138000=35.6x So x=3876g or x=3.88kg D
 11 months ago

TheDoctorRules Group TitleBest ResponseYou've already chosen the best response.1
Woops I mean A haha
 11 months ago

Pumpkin890 Group TitleBest ResponseYou've already chosen the best response.0
Thanks so much for your help!
 11 months ago
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