anonymous
  • anonymous
Solve the system by the substitution method. xy = 12 x2 + y2 = 40
Mathematics
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
Why can't you do your own work
anonymous
  • anonymous
y dont u pop off
anonymous
  • anonymous
no thanks

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
yea get off my question if u just wanna start trouble toodels
anonymous
  • anonymous
Thats hilarious sorry! :) But anyways you can use either equation: \[xy = 12 \]\[x= \frac{ 12 }{ y }\] OR \[x^2 + y^2 = 40 \]\[x + y = \sqrt{40}\]\[x = \sqrt{40} - y\] **The y and the x can be switched....
anonymous
  • anonymous
All you need to do is plug in.
anonymous
  • anonymous
haha i know .. ok then y does it give me 4 quandrants to pick from ?
anonymous
  • anonymous
example {( 2, 6), ( 6, 2), ( 2, -6), ( 6, -2)}
anonymous
  • anonymous
@ilfy214
anonymous
  • anonymous
From what I solved I got these solutions. 6, 2, -2
anonymous
  • anonymous
im just confused on plugging them in ..
anonymous
  • anonymous
Doesn't it depend on how you solved your equation? Also, when I plugged in -2 and 6 for the first problem, I got -12 instead of 12.
anonymous
  • anonymous
im going w/ b
anonymous
  • anonymous
I was thinking for along the lines of C?
anonymous
  • anonymous
i just dont understand how i allways mess that up
anonymous
  • anonymous
Because in B, if you try using ( 2, -6) and ( -2, 6) you already have a problem for the equation below:\[xy = 12\]\[(2)(-6) = -12\]\[(-2)(6)= -12\]
anonymous
  • anonymous
Its okay! Just choose the options that give you BOTH positive answers
anonymous
  • anonymous
thank u i appreciate it !! :)
anonymous
  • anonymous
You're welcome! :D

Looking for something else?

Not the answer you are looking for? Search for more explanations.