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anonymous
 3 years ago
Solve the system by the substitution method.
xy = 12
x2 + y2 = 40
anonymous
 3 years ago
Solve the system by the substitution method. xy = 12 x2 + y2 = 40

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Why can't you do your own work

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yea get off my question if u just wanna start trouble toodels

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Thats hilarious sorry! :) But anyways you can use either equation: \[xy = 12 \]\[x= \frac{ 12 }{ y }\] OR \[x^2 + y^2 = 40 \]\[x + y = \sqrt{40}\]\[x = \sqrt{40}  y\] **The y and the x can be switched....

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0All you need to do is plug in.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0haha i know .. ok then y does it give me 4 quandrants to pick from ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0example {( 2, 6), ( 6, 2), ( 2, 6), ( 6, 2)}

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0From what I solved I got these solutions. 6, 2, 2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0im just confused on plugging them in ..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Doesn't it depend on how you solved your equation? Also, when I plugged in 2 and 6 for the first problem, I got 12 instead of 12.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I was thinking for along the lines of C?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i just dont understand how i allways mess that up

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Because in B, if you try using ( 2, 6) and ( 2, 6) you already have a problem for the equation below:\[xy = 12\]\[(2)(6) = 12\]\[(2)(6)= 12\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Its okay! Just choose the options that give you BOTH positive answers

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thank u i appreciate it !! :)
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