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britbrat4290
 one year ago
Solve the system by the substitution method.
xy = 12
x2 + y2 = 40
britbrat4290
 one year ago
Solve the system by the substitution method. xy = 12 x2 + y2 = 40

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live10000000
 one year ago
Best ResponseYou've already chosen the best response.4Why can't you do your own work

britbrat4290
 one year ago
Best ResponseYou've already chosen the best response.1yea get off my question if u just wanna start trouble toodels

ilfy214
 one year ago
Best ResponseYou've already chosen the best response.1Thats hilarious sorry! :) But anyways you can use either equation: \[xy = 12 \]\[x= \frac{ 12 }{ y }\] OR \[x^2 + y^2 = 40 \]\[x + y = \sqrt{40}\]\[x = \sqrt{40}  y\] **The y and the x can be switched....

ilfy214
 one year ago
Best ResponseYou've already chosen the best response.1All you need to do is plug in.

britbrat4290
 one year ago
Best ResponseYou've already chosen the best response.1haha i know .. ok then y does it give me 4 quandrants to pick from ?

britbrat4290
 one year ago
Best ResponseYou've already chosen the best response.1example {( 2, 6), ( 6, 2), ( 2, 6), ( 6, 2)}

ilfy214
 one year ago
Best ResponseYou've already chosen the best response.1From what I solved I got these solutions. 6, 2, 2

britbrat4290
 one year ago
Best ResponseYou've already chosen the best response.1im just confused on plugging them in ..

ilfy214
 one year ago
Best ResponseYou've already chosen the best response.1Doesn't it depend on how you solved your equation? Also, when I plugged in 2 and 6 for the first problem, I got 12 instead of 12.

ilfy214
 one year ago
Best ResponseYou've already chosen the best response.1I was thinking for along the lines of C?

britbrat4290
 one year ago
Best ResponseYou've already chosen the best response.1i just dont understand how i allways mess that up

ilfy214
 one year ago
Best ResponseYou've already chosen the best response.1Because in B, if you try using ( 2, 6) and ( 2, 6) you already have a problem for the equation below:\[xy = 12\]\[(2)(6) = 12\]\[(2)(6)= 12\]

ilfy214
 one year ago
Best ResponseYou've already chosen the best response.1Its okay! Just choose the options that give you BOTH positive answers

britbrat4290
 one year ago
Best ResponseYou've already chosen the best response.1thank u i appreciate it !! :)
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