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Problem I have is step 1

i got x(3y*dy/dx) +y^3

so.. 3xy*dydx +y^3

dy/dx**

you mean 3 x y^2 dy/dx for the first part
d/dx of y^3 is 3 y^2 dy/dx

okay im lost with the second part.

i know that you took the derivative of xy^3= 3xy^2

+xy= 1?

*dy/dx

yes.

use the power rule
\[ \frac{d y^n}{dx} = n y^{n-1} \frac{dy}{dx} \]

this isn't applying chain rule or is it? because i understand what youre doing here makes sense/

yes, it is the chain rule

okay, let me give this a try.

okay I got this down: x*3y^2(dy/dx) +3y +x(dy/dx)+y=0

you mean y^3 not 3y , right ?

oh so only find the derivative of [y^3]...

thanks btw! :)

then i should just plot the points for x and y

wait a min. what should i do with dy/dx?

solve for dy/dx and then sub in for x and y to get the value of dy/dx at the point (2,1)

how?

use algebra

question: is it possible to divide this: -4x/-2y ????

how the hell can someone divide this and get 2x/y?????

this is so frustrating, please help me understand this.

at the point (2,1)

no no, i know that. i was just looking at an example and i see that they divide -4x/-2y and got 2x/y

it frustrated me to see this and not know how they even possibly do it.

are you asking how to get from
\[ \frac{-4x}{-2y} = \frac{2x}{y} \]
?
-4/-2 is +2

yes but with diferet variables?? 0.o

different*

what is the question ?

oh the slope is -1/4! =]

yes. also, the tangent line goes through point (2,1)
so you can find the intercept.

cool, how do you know this?

okie doke

y=-1/4x+3/2

yes