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anonymous
 3 years ago
Help (Attached below) Determine the extrema of below on the given interval
anonymous
 3 years ago
Help (Attached below) Determine the extrema of below on the given interval

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i know we have to find the derivative and set it to zero

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i got x= 8 and x= 2/9

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0now to have the intervals, im a little lost on...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0would there only be 2 intervals?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0or 3? 02/9 then 2/98 and 8infinity?

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.0ok... so whats the derivative...?

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.0ok... so what are the solutions...?

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.0yep... so on [0, 4] substitute x = 0, 2/9 and 4 into the original equation and find the corresponding values...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0because the 2 critical numbers are 8 and 2/9

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.0well (a) is asking for the location of that min and max on the interval x = 0 to x = 4 and as x = 2/9 is a critical point...you don't know its nature

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ooooooh, 8 would be the other one

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.0so the value x =0 is f(0) = 2 x = 2/9 f(2/9) = 3.76 x = 4 f(4) = ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so the max is 3.76 and min is 334?

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.0so just test x = 9, x = 8 and x = 9... and see what happens... I think x = 2/9 remains the max

campbell_st
 3 years ago
Best ResponseYou've already chosen the best response.0its an add interval since x = 9 gives a very large negative number
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