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mathcalculus
 one year ago
Help (Attached below) Determine the extrema of below on the given interval
mathcalculus
 one year ago
Help (Attached below) Determine the extrema of below on the given interval

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mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0i know we have to find the derivative and set it to zero

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0i got x= 8 and x= 2/9

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0now to have the intervals, im a little lost on...

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0would there only be 2 intervals?

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0or 3? 02/9 then 2/98 and 8infinity?

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0ok... so whats the derivative...?

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0then i set it to = 0

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0ok... so what are the solutions...?

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0yep... so on [0, 4] substitute x = 0, 2/9 and 4 into the original equation and find the corresponding values...

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0because the 2 critical numbers are 8 and 2/9

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0well (a) is asking for the location of that min and max on the interval x = 0 to x = 4 and as x = 2/9 is a critical point...you don't know its nature

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0ooooooh, 8 would be the other one

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0so the value x =0 is f(0) = 2 x = 2/9 f(2/9) = 3.76 x = 4 f(4) = ?

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0so the max is 3.76 and min is 334?

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0so just test x = 9, x = 8 and x = 9... and see what happens... I think x = 2/9 remains the max

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0its an add interval since x = 9 gives a very large negative number
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