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superloz Group Title

help http://prntscr.com/1l4tko http://prntscr.com/1l4ttt

  • 11 months ago
  • 11 months ago

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  1. superloz Group Title
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    how to find the second one?

    • 11 months ago
  2. OpenSessame Group Title
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    The diagonals are in the middle of the triangle so its basically it is breaking it up in 4 equal peices.

    • 11 months ago
  3. superloz Group Title
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    pok

    • 11 months ago
  4. superloz Group Title
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    ok

    • 11 months ago
  5. superloz Group Title
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    then

    • 11 months ago
  6. OpenSessame Group Title
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    So if you are trying to find ac it would what half of it twice.

    • 11 months ago
  7. OpenSessame Group Title
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    so (x+4)(x+4)

    • 11 months ago
  8. superloz Group Title
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    simplify?

    • 11 months ago
  9. OpenSessame Group Title
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    Since you have the sum of the length of the diaganols you have to make an equation equal to 20.

    • 11 months ago
  10. OpenSessame Group Title
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    (2x-3)(2x-3)+(x+4)(x+4)=20

    • 11 months ago
  11. OpenSessame Group Title
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    You have to solve for x before moving on

    • 11 months ago
  12. superloz Group Title
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    is the answer 7?

    • 11 months ago
  13. OpenSessame Group Title
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    Uh one sec still solving!

    • 11 months ago
  14. OpenSessame Group Title
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    Plug it in to check!

    • 11 months ago
  15. OpenSessame Group Title
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    I dont think thats it?

    • 11 months ago
  16. superloz Group Title
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    idk

    • 11 months ago
  17. superloz Group Title
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    i solve this for x (2x-3)(2x-3)+(x+4)(x+4)=20

    • 11 months ago
  18. OpenSessame Group Title
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    You have to do the quadratic eqaution...

    • 11 months ago
  19. superloz Group Title
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    idk how to do quad

    • 11 months ago
  20. OpenSessame Group Title
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    did you get 5x^2-4x+25=20 when you simplified?

    • 11 months ago
  21. superloz Group Title
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    yep

    • 11 months ago
  22. OpenSessame Group Title
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    Okay you need quad to find x give me a minute and ill do it...

    • 11 months ago
  23. superloz Group Title
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    ok

    • 11 months ago
  24. OpenSessame Group Title
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    Its an imaginary number...

    • 11 months ago
  25. OpenSessame Group Title
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    Assuming the rhombus is ABCD and E is the intersection of the diagonals, then we know the diagonals perpendicularly bisect each other, so AE is half of one diagonal and BE is half the other diagonal. That allows us to solve for x: (x+4) + (2x-3) = 20/2 3x + 1 = 10 3x = 9 x = 3 and since BE = 2x - 3 = 3 is half of BD, BD = 2*3 = 6 (answer C).

    • 11 months ago
  26. OpenSessame Group Title
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    Figured out the better way to solve it lol

    • 11 months ago
  27. superloz Group Title
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    thank you

    • 11 months ago
  28. OpenSessame Group Title
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    DO you understand how i got there?

    • 11 months ago
  29. superloz Group Title
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    so BE is half and BD is the other half?

    • 11 months ago
  30. superloz Group Title
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    each is 3?

    • 11 months ago
  31. OpenSessame Group Title
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    Wait!!! i messed up lol you plug the three in x+4 and multiply it by 2 because you are finding ac

    • 11 months ago
  32. OpenSessame Group Title
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    For some reason i thought it was the other one. But it will be 14 in that case.

    • 11 months ago
  33. superloz Group Title
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    thanks

    • 11 months ago
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