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superloz
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help
http://prntscr.com/1l4tko
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 11 months ago
 11 months ago
superloz Group Title
help http://prntscr.com/1l4tko http://prntscr.com/1l4ttt
 11 months ago
 11 months ago

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superloz Group TitleBest ResponseYou've already chosen the best response.0
how to find the second one?
 11 months ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.1
The diagonals are in the middle of the triangle so its basically it is breaking it up in 4 equal peices.
 11 months ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.1
So if you are trying to find ac it would what half of it twice.
 11 months ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.1
so (x+4)(x+4)
 11 months ago

superloz Group TitleBest ResponseYou've already chosen the best response.0
simplify?
 11 months ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.1
Since you have the sum of the length of the diaganols you have to make an equation equal to 20.
 11 months ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.1
(2x3)(2x3)+(x+4)(x+4)=20
 11 months ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.1
You have to solve for x before moving on
 11 months ago

superloz Group TitleBest ResponseYou've already chosen the best response.0
is the answer 7?
 11 months ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.1
Uh one sec still solving!
 11 months ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.1
Plug it in to check!
 11 months ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.1
I dont think thats it?
 11 months ago

superloz Group TitleBest ResponseYou've already chosen the best response.0
i solve this for x (2x3)(2x3)+(x+4)(x+4)=20
 11 months ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.1
You have to do the quadratic eqaution...
 11 months ago

superloz Group TitleBest ResponseYou've already chosen the best response.0
idk how to do quad
 11 months ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.1
did you get 5x^24x+25=20 when you simplified?
 11 months ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.1
Okay you need quad to find x give me a minute and ill do it...
 11 months ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.1
Its an imaginary number...
 11 months ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.1
Assuming the rhombus is ABCD and E is the intersection of the diagonals, then we know the diagonals perpendicularly bisect each other, so AE is half of one diagonal and BE is half the other diagonal. That allows us to solve for x: (x+4) + (2x3) = 20/2 3x + 1 = 10 3x = 9 x = 3 and since BE = 2x  3 = 3 is half of BD, BD = 2*3 = 6 (answer C).
 11 months ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.1
Figured out the better way to solve it lol
 11 months ago

superloz Group TitleBest ResponseYou've already chosen the best response.0
thank you
 11 months ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.1
DO you understand how i got there?
 11 months ago

superloz Group TitleBest ResponseYou've already chosen the best response.0
so BE is half and BD is the other half?
 11 months ago

superloz Group TitleBest ResponseYou've already chosen the best response.0
each is 3?
 11 months ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.1
Wait!!! i messed up lol you plug the three in x+4 and multiply it by 2 because you are finding ac
 11 months ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.1
For some reason i thought it was the other one. But it will be 14 in that case.
 11 months ago
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