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superloz Group Title

help http://prntscr.com/1l4tko http://prntscr.com/1l4ttt

  • one year ago
  • one year ago

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  1. superloz Group Title
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    how to find the second one?

    • one year ago
  2. OpenSessame Group Title
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    The diagonals are in the middle of the triangle so its basically it is breaking it up in 4 equal peices.

    • one year ago
  3. superloz Group Title
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    pok

    • one year ago
  4. superloz Group Title
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    ok

    • one year ago
  5. superloz Group Title
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    then

    • one year ago
  6. OpenSessame Group Title
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    So if you are trying to find ac it would what half of it twice.

    • one year ago
  7. OpenSessame Group Title
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    so (x+4)(x+4)

    • one year ago
  8. superloz Group Title
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    simplify?

    • one year ago
  9. OpenSessame Group Title
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    Since you have the sum of the length of the diaganols you have to make an equation equal to 20.

    • one year ago
  10. OpenSessame Group Title
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    (2x-3)(2x-3)+(x+4)(x+4)=20

    • one year ago
  11. OpenSessame Group Title
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    You have to solve for x before moving on

    • one year ago
  12. superloz Group Title
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    is the answer 7?

    • one year ago
  13. OpenSessame Group Title
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    Uh one sec still solving!

    • one year ago
  14. OpenSessame Group Title
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    Plug it in to check!

    • one year ago
  15. OpenSessame Group Title
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    I dont think thats it?

    • one year ago
  16. superloz Group Title
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    idk

    • one year ago
  17. superloz Group Title
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    i solve this for x (2x-3)(2x-3)+(x+4)(x+4)=20

    • one year ago
  18. OpenSessame Group Title
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    You have to do the quadratic eqaution...

    • one year ago
  19. superloz Group Title
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    idk how to do quad

    • one year ago
  20. OpenSessame Group Title
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    did you get 5x^2-4x+25=20 when you simplified?

    • one year ago
  21. superloz Group Title
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    yep

    • one year ago
  22. OpenSessame Group Title
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    Okay you need quad to find x give me a minute and ill do it...

    • one year ago
  23. superloz Group Title
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    ok

    • one year ago
  24. OpenSessame Group Title
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    Its an imaginary number...

    • one year ago
  25. OpenSessame Group Title
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    Assuming the rhombus is ABCD and E is the intersection of the diagonals, then we know the diagonals perpendicularly bisect each other, so AE is half of one diagonal and BE is half the other diagonal. That allows us to solve for x: (x+4) + (2x-3) = 20/2 3x + 1 = 10 3x = 9 x = 3 and since BE = 2x - 3 = 3 is half of BD, BD = 2*3 = 6 (answer C).

    • one year ago
  26. OpenSessame Group Title
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    Figured out the better way to solve it lol

    • one year ago
  27. superloz Group Title
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    thank you

    • one year ago
  28. OpenSessame Group Title
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    DO you understand how i got there?

    • one year ago
  29. superloz Group Title
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    so BE is half and BD is the other half?

    • one year ago
  30. superloz Group Title
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    each is 3?

    • one year ago
  31. OpenSessame Group Title
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    Wait!!! i messed up lol you plug the three in x+4 and multiply it by 2 because you are finding ac

    • one year ago
  32. OpenSessame Group Title
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    For some reason i thought it was the other one. But it will be 14 in that case.

    • one year ago
  33. superloz Group Title
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    thanks

    • one year ago
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