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how to find the second one?

pok

ok

then

So if you are trying to find ac it would what half of it twice.

so (x+4)(x+4)

simplify?

Since you have the sum of the length of the diaganols you have to make an equation equal to 20.

(2x-3)(2x-3)+(x+4)(x+4)=20

You have to solve for x before moving on

is the answer 7?

Uh one sec still solving!

Plug it in to check!

I dont think thats it?

idk

i solve this for x (2x-3)(2x-3)+(x+4)(x+4)=20

You have to do the quadratic eqaution...

idk how to do quad

did you get 5x^2-4x+25=20 when you simplified?

yep

Okay you need quad to find x give me a minute and ill do it...

ok

Its an imaginary number...

Figured out the better way to solve it lol

thank you

DO you understand how i got there?

so BE is half and BD is the other half?

each is 3?

Wait!!! i messed up lol you plug the three in x+4 and multiply it by 2 because you are finding ac

For some reason i thought it was the other one. But it will be 14 in that case.

thanks