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Find the image of P(–2, –1) after two reflections; first Ry=5 and then Rx=1.
A. (–2, –1)
B. (–1, –6)
C. (4, –9)
D. (1, –5)
 one year ago
 one year ago
OpenSessame Group Title
Find the image of P(–2, –1) after two reflections; first Ry=5 and then Rx=1. A. (–2, –1) B. (–1, –6) C. (4, –9) D. (1, –5)
 one year ago
 one year ago

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e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
So the Ry=5 and Rx=1 are the lines you need to reflect across?
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
Those are the reflections
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
A reflection is usually over a line.... so I want to make sure that is the notation you are using.
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
I think so...
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
http://www.mathopenref.com/reflect.html Like it says there, "A transformation where each point in a shape appears at an equal distance on the opposite side of a given line  the line of reflection. " So, start by just doing a rough sketch. Does not need to be exact, but you need to find where the dot and line would be and how far the line is from the dot. If you can do that with math, great! But a sketch can help.
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
Okay, but i dont understand what i have to do...
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
Well, it needs to be an equal distance from the line on the other side of the line.
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
Where did the line come from????
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
You lost me..
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
Ry=5 \(\leftarrow\) that is the line part.
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
Let me show you an example.
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
Okay...Just show me with this one
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
If I work this that is me giving you an answer. If I work an example you can follow the process and answer your own homework. Lets say I take this random dot: dw:1376455485961:dw And lets say I have Ry=1, so the line where every Y is 1.
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
dw:1376455572591:dw
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
Well, im really lost man...So i wouldnt even get it
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
That is an example already, im just doing a text review for before i take it. so it doesnt count
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
The important measure is the distance from the dot to the line. dw:1376455620753:dw Because I need to put the reflection the SAME DISTANCE on the other side of the line.
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
dw:1376455677255:dw
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
Do the distance is the number in the equation?
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
Let me try to do mine...one sec
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
The distance is the measure from your point and the line.
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
Yours is done twice.... so see what you get for the first step and I can check it. Then the second step.
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
dw:1376455841757:dw
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
OK, that is a good (2,1).
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
dw:1376455914360:dw
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
Now what do i do exactly?
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
OK, so what is the measure of the distance between your dot and the line? dw:1376456012468:dw
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
Not quite. Tewo problems. This is change in y, not x, and distance is always positive.
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
Yes. So your point is 4 above the line. That means the reflection must be 4 BELOW the line!
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
so at 5?
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
wait no....4?
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
The line is at 5. So 4 below 5.... or 54=?
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
Above is +, below is . Similarly, to the left of is , to the right of is +. Has to do with the Cartesian (xy) plane rules.
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
Ohhhh so 9?
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
Yes. That means the X is the same and the Y is now 9. So, the point after 1 translation is at (2,9). dw:1376456612998:dw
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
Now you have the line Rx=1 to do the second reflection over.
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
okay:) i get it!
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
dw:1376456678313:dw
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
dw:1376456695550:dw
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
So, how far this time?
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
\(\large\ddot\smile\)
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
so the point would me three to the right?
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
so (4,9)????
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
Yes, 3 to the right of 1. And yep, that is it. (4,9).
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
wait im gonna see if it matches...
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
Now, once you get good at the math, you should not need a sketch, but if yuou are ever in doubt, the rough sketch is there to help!
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
Okay, the textbook just didnt really explain it
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
The thing I think most people mes up here is the line.... because x=0 is the y axis, and y=0 is the x axis. So they give you a y line but you draw it the same way as the x axis and that can be confusing!
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
yea, thats the right answer! thanks:)
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
Can you help with some other questions that i dont get?
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
Probably. I can explain it the same basic way I always do and hopefully it works like this and you get it!
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
Okay, thanks:)
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
What composition of rigid motions and a dilation maps EFGH to the dashed figure? https://study.ashworthcollege.edu/access/content/group/45b8c516100846d7aa1dbb9b62c786ff/geometry_exam_9_files/mc0201.jpg
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
OK. Dilation is going to be the size change. The rigit motion will get it from one place to the other.
 one year ago

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Okay...
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
It is probably easiest to do the dilation first. That will be some multiplication number. It is a ratio of the sides.
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
Okay...
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
For example, this would be a dialation by 3..... dw:1376457753408:dw So start by finding how long the sides of both rectangles are.
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
wait is the answer D2*T<0,6>
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
2x the size, so yah, a dialation of 2. I didn't do the rest yet, but that would probably do it.
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
Really??? woooohoooo
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
Hmmm.... 6.... is that enough on the translation?
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
Idk...
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
Well, lets look at this real quick: dw:1376458028692:dw Now you need to double the size.
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
The dialation is times 2?
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
dw:1376458060944:dw OK, that makes them reflections of each other.
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
So now, one of two things needs to happne.... It either needs to be reflected over the x axis, OR, corner H needs to go all the way down to the bottom corner. dw:1376458143764:dw
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
so its shifted down 6
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
Well, is that 6? That bottom corner is at 9....
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
or 10, actually.... counted wrong.
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
So it has to go from 2 above to 10 below... so....
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
so uhm...It would be 11?
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
Yep! So 2D, T\(\langle 0,12\rangle\) is more like it.
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
that isnt one of my options
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
Hmmm.... AH.... OK... the dialaion is probably also changing the translation! \(2\langle 0,6\rangle = \langle 0,12\rangle\)
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
So my bad. Looks like you did have it right.
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
YUS:) thanks though!
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
The hexagon GIKMPR and FJN are regular. The dashed line segments form 30° angles. What is r(240drg,0)(G)
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
Well, the good news is you should understand the why a bit better! By exploring these, it lets you understand the why of it all....
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
Hmmm..... I have not seen that form of question.... my geometry was a while back, and they have changed some of the things they do... Do you know what it is looking for, any terms? An angle?
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
240 degrees
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
Thats really all i understand...
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
r is usually a radius.... but there is no distance....
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
I think r is the point?
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
Is it R and not r?
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
Thats the problem..
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
hmmm..... Well, 240/30=8 segments.
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
so 8 to the left or right?
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
Well, if r is right... but that would be a guess on my part. Right 8 of G? I would need to see the reference to know they type of peoblem to get this one.
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
So would it be K???
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
I would only be guessing without the book and chapter.
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
Okay...Well for me thats better then nothing!
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
The vertices of a triangle are P(–8, 6), Q(1, –3), and R(–6, –3). Name the vertices of \[R _{y=x}(PQR)\]
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
Is that a reflection over the y axis?
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
I believe it is.
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
AH HA! Found a reference! http://www.regentsprep.org/Regents/math/geometry/GT6/composition.htm
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
You did??
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
The composition part does not matter here.... the \(R_y\) part is reflection over the y axis!
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
So just make it the other sign?
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
And even better! http://www.regentsprep.org/Regents/math/geometry/GT5/reviewTranformations.htm
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
Would the first point be (6,8)
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
OHHHH!!! MAKES SENSE!
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
so (6,8)
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
Amazing what finding a reference to the symbols can do!
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
YEA! Thanks so much man!
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
Write a sequence of rigid motions that maps ab and xy
 one year ago

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LAST ONE AND I WILL UNDERSTAND GEOMETRY!
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
That composition part also confirms what we talked about with the <0,6> becoming <0,12>. The SECOND part of the compositon happens first!
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
the second part is (AB=XY)
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
Are those seperate calculations for those two?
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
The top doesnt matter just look at the lines
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
Yah, well, then that is some sort of what? Rotation, reflection etc?
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
Reflection?
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
Remember that A is going to X and B is going to Y..... should be a huge clue.... YES! Some sort of reflection.
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
So, you just need to find the line they are reflected over.
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
It would be half way between them.
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
Are they both the same distance from x=0?
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
yES...
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
Did you count the distance from 0 to X and 0 to A?
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
Take a second look.... they are not the same.
 one year ago

e.mccormick Group TitleBest ResponseYou've already chosen the best response.2
You want the line half way between. So take the distance between the two points and divide by 2. It will be that far to the left of the right most line, and right of the left most line.
 one year ago

OpenSessame Group TitleBest ResponseYou've already chosen the best response.0
okay...
 one year ago
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