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 one year ago
Find the image of P(–2, –1) after two reflections; first Ry=5 and then Rx=1.
A. (–2, –1)
B. (–1, –6)
C. (4, –9)
D. (1, –5)
 one year ago
Find the image of P(–2, –1) after two reflections; first Ry=5 and then Rx=1. A. (–2, –1) B. (–1, –6) C. (4, –9) D. (1, –5)

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e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2So the Ry=5 and Rx=1 are the lines you need to reflect across?

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0Those are the reflections

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2A reflection is usually over a line.... so I want to make sure that is the notation you are using.

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2http://www.mathopenref.com/reflect.html Like it says there, "A transformation where each point in a shape appears at an equal distance on the opposite side of a given line  the line of reflection. " So, start by just doing a rough sketch. Does not need to be exact, but you need to find where the dot and line would be and how far the line is from the dot. If you can do that with math, great! But a sketch can help.

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0Okay, but i dont understand what i have to do...

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2Well, it needs to be an equal distance from the line on the other side of the line.

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0Where did the line come from????

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2Ry=5 \(\leftarrow\) that is the line part.

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2Let me show you an example.

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0Okay...Just show me with this one

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2If I work this that is me giving you an answer. If I work an example you can follow the process and answer your own homework. Lets say I take this random dot: dw:1376455485961:dw And lets say I have Ry=1, so the line where every Y is 1.

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2dw:1376455572591:dw

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0Well, im really lost man...So i wouldnt even get it

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0That is an example already, im just doing a text review for before i take it. so it doesnt count

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2The important measure is the distance from the dot to the line. dw:1376455620753:dw Because I need to put the reflection the SAME DISTANCE on the other side of the line.

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2dw:1376455677255:dw

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0Do the distance is the number in the equation?

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0Let me try to do mine...one sec

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2The distance is the measure from your point and the line.

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2Yours is done twice.... so see what you get for the first step and I can check it. Then the second step.

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0dw:1376455841757:dw

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2OK, that is a good (2,1).

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0dw:1376455914360:dw

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0Now what do i do exactly?

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2OK, so what is the measure of the distance between your dot and the line? dw:1376456012468:dw

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2Not quite. Tewo problems. This is change in y, not x, and distance is always positive.

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2Yes. So your point is 4 above the line. That means the reflection must be 4 BELOW the line!

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2The line is at 5. So 4 below 5.... or 54=?

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2Above is +, below is . Similarly, to the left of is , to the right of is +. Has to do with the Cartesian (xy) plane rules.

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2Yes. That means the X is the same and the Y is now 9. So, the point after 1 translation is at (2,9). dw:1376456612998:dw

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2Now you have the line Rx=1 to do the second reflection over.

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0dw:1376456678313:dw

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0dw:1376456695550:dw

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2So, how far this time?

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2\(\large\ddot\smile\)

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0so the point would me three to the right?

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2Yes, 3 to the right of 1. And yep, that is it. (4,9).

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0wait im gonna see if it matches...

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2Now, once you get good at the math, you should not need a sketch, but if yuou are ever in doubt, the rough sketch is there to help!

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0Okay, the textbook just didnt really explain it

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2The thing I think most people mes up here is the line.... because x=0 is the y axis, and y=0 is the x axis. So they give you a y line but you draw it the same way as the x axis and that can be confusing!

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0yea, thats the right answer! thanks:)

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0Can you help with some other questions that i dont get?

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2Probably. I can explain it the same basic way I always do and hopefully it works like this and you get it!

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0What composition of rigid motions and a dilation maps EFGH to the dashed figure? https://study.ashworthcollege.edu/access/content/group/45b8c516100846d7aa1dbb9b62c786ff/geometry_exam_9_files/mc0201.jpg

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2OK. Dilation is going to be the size change. The rigit motion will get it from one place to the other.

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2It is probably easiest to do the dilation first. That will be some multiplication number. It is a ratio of the sides.

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2For example, this would be a dialation by 3..... dw:1376457753408:dw So start by finding how long the sides of both rectangles are.

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0wait is the answer D2*T<0,6>

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.22x the size, so yah, a dialation of 2. I didn't do the rest yet, but that would probably do it.

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0Really??? woooohoooo

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2Hmmm.... 6.... is that enough on the translation?

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2Well, lets look at this real quick: dw:1376458028692:dw Now you need to double the size.

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0The dialation is times 2?

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2dw:1376458060944:dw OK, that makes them reflections of each other.

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2So now, one of two things needs to happne.... It either needs to be reflected over the x axis, OR, corner H needs to go all the way down to the bottom corner. dw:1376458143764:dw

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0so its shifted down 6

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2Well, is that 6? That bottom corner is at 9....

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2or 10, actually.... counted wrong.

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2So it has to go from 2 above to 10 below... so....

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0so uhm...It would be 11?

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2Yep! So 2D, T\(\langle 0,12\rangle\) is more like it.

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0that isnt one of my options

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2Hmmm.... AH.... OK... the dialaion is probably also changing the translation! \(2\langle 0,6\rangle = \langle 0,12\rangle\)

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2So my bad. Looks like you did have it right.

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0YUS:) thanks though!

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0The hexagon GIKMPR and FJN are regular. The dashed line segments form 30° angles. What is r(240drg,0)(G)

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2Well, the good news is you should understand the why a bit better! By exploring these, it lets you understand the why of it all....

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2Hmmm..... I have not seen that form of question.... my geometry was a while back, and they have changed some of the things they do... Do you know what it is looking for, any terms? An angle?

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0Thats really all i understand...

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2r is usually a radius.... but there is no distance....

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0I think r is the point?

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2Is it R and not r?

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0Thats the problem..

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2hmmm..... Well, 240/30=8 segments.

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0so 8 to the left or right?

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2Well, if r is right... but that would be a guess on my part. Right 8 of G? I would need to see the reference to know they type of peoblem to get this one.

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0So would it be K???

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2I would only be guessing without the book and chapter.

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0Okay...Well for me thats better then nothing!

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0The vertices of a triangle are P(–8, 6), Q(1, –3), and R(–6, –3). Name the vertices of \[R _{y=x}(PQR)\]

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2Is that a reflection over the y axis?

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2AH HA! Found a reference! http://www.regentsprep.org/Regents/math/geometry/GT6/composition.htm

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2The composition part does not matter here.... the \(R_y\) part is reflection over the y axis!

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0So just make it the other sign?

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2And even better! http://www.regentsprep.org/Regents/math/geometry/GT5/reviewTranformations.htm

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0Would the first point be (6,8)

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0OHHHH!!! MAKES SENSE!

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2Amazing what finding a reference to the symbols can do!

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0YEA! Thanks so much man!

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0Write a sequence of rigid motions that maps ab and xy

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0LAST ONE AND I WILL UNDERSTAND GEOMETRY!

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2That composition part also confirms what we talked about with the <0,6> becoming <0,12>. The SECOND part of the compositon happens first!

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0the second part is (AB=XY)

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2Are those seperate calculations for those two?

OpenSessame
 one year ago
Best ResponseYou've already chosen the best response.0The top doesnt matter just look at the lines

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2Yah, well, then that is some sort of what? Rotation, reflection etc?

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2Remember that A is going to X and B is going to Y..... should be a huge clue.... YES! Some sort of reflection.

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2So, you just need to find the line they are reflected over.

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2It would be half way between them.

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2Are they both the same distance from x=0?

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2Did you count the distance from 0 to X and 0 to A?

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2Take a second look.... they are not the same.

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.2You want the line half way between. So take the distance between the two points and divide by 2. It will be that far to the left of the right most line, and right of the left most line.
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