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highschoolmom2010
 3 years ago
Verify that each equation is an identity by showing that each expression on the left simplifies to 1.
highschoolmom2010
 3 years ago
Verify that each equation is an identity by showing that each expression on the left simplifies to 1.

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highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1no where im lost

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.0take left hand side expression, plugin tanA = sinA/cosA

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1im still really confused

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.0did they teach you ' tan = sin/cos' yet ?

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1so im learning it here

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.0ok, dont learn it here. wait until they start them officially lets do it the known way

phi
 3 years ago
Best ResponseYou've already chosen the best response.1they may want you to use the definitions of sin(A)= opp/adj = a/c and tan(A)= a/b

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1376501404557:dw

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.0exactly, look at above triangle, first find sinA, and tanA

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1376501580565:dw

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.0yes, find tanA also, and plug them in left side of given expression

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1assuming that is alpha....

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.0uhh this time, thats 'a', sorry

phi
 3 years ago
Best ResponseYou've already chosen the best response.1they are using lower case for the side and capital for the angle opposite that side

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1\[\tan A=\frac{ a }{ b }\] oh then let me fix sin A

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1\[\sin A=\frac{ a }{ c }\]

phi
 3 years ago
Best ResponseYou've already chosen the best response.1now what is \[ \frac{1}{\sin A} \]

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1@phi im not sure

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.0plug them directly, we can simplify after pluggin in may be

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1\[\frac{ 1 }{ \frac{ a }{ c} }\]

phi
 3 years ago
Best ResponseYou've already chosen the best response.1the short way is "flip" both sides of sin A = a/c the long way is go through these steps multiply both sides by c: c sin A = a divide both sides by a (c sin A)/a = 1 divide both sides by sin A c/a = 1/ sin A

phi
 3 years ago
Best ResponseYou've already chosen the best response.1or do what you did , and multiply top and bottom by c/a

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1that ^^kinda confused me

phi
 3 years ago
Best ResponseYou've already chosen the best response.1\[ \frac{ 1\cdot \frac{c}{a} }{ \frac{ a }{ c} \cdot \frac{c}{a}} \] the idea is you can multiply top and bottom by the same number (or fraction) now simplify

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1\[\frac{ \frac{ c }{ a } }{ 1 }\]

phi
 3 years ago
Best ResponseYou've already chosen the best response.1yes, and anything divided by 1 is itself

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1co the left side =c/a

phi
 3 years ago
Best ResponseYou've already chosen the best response.1yes. (and remember the short cut) if you have a/b = c/d then b/a = d/c (flip both sides) in this case sin A = a/c 1/sinA = c/a

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1right side = b/a then

phi
 3 years ago
Best ResponseYou've already chosen the best response.1now what is \[ \frac{1}{\sin^2 A} =\frac{1}{\sin A} \cdot \frac{1}{\sin A} \]

phi
 3 years ago
Best ResponseYou've already chosen the best response.1you know 1/sin A = c/a so you know 1/sin A * 1/sinA = (c/a)*(c/a) \[ \frac{c}{a}\cdot \frac{c}{a}\]

phi
 3 years ago
Best ResponseYou've already chosen the best response.1which is top times top and bottom times bottom

phi
 3 years ago
Best ResponseYou've already chosen the best response.1another way to do this is remember \[ \sin^2 A \text{ means } \sin A \cdot \sin A \] you know sin A= a/c so \[ \sin^2 A \text{ means } \sin A \cdot \sin A = \frac{a}{c}\cdot \frac{a}{c}=\frac{a\cdot a}{c\cdot c}=\frac{a^2}{c^2}\]

phi
 3 years ago
Best ResponseYou've already chosen the best response.1and \[ \frac{1}{\sin^2 A} = \frac{c^2}{a^2} \] using the flip rule

phi
 3 years ago
Best ResponseYou've already chosen the best response.1I should mention that \[ \left(\sin A \right)^2 \text{ is often written as }\sin^2 A \] then mean the same thing. (sin A) times itself: (sin A)(sin A)

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1im following and writing too

phi
 3 years ago
Best ResponseYou've already chosen the best response.1so far you have \[ \frac{1}{(\sin A)^2 }= \frac{c^2}{a^2} \] now what is 1/(tan A)^2 ?

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.11 sec ill write it out on paper and then ^^

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1\[\frac{ 1 }{ \tan A^2} \]=\[\frac{ b^2 }{ a^2 }\]

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1well i wrote tan A ^2 wrong

phi
 3 years ago
Best ResponseYou've already chosen the best response.1yes, so the equation is \[ \frac{c^2}{a^2} \frac{b^2}{a^2} = 1 \] re: tan A^2 yes, you should put parens in (tan A)^2. but we know what you mean now, the fractions on the left side have a common denominator can you rewrite as one fraction ?

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1\[\frac{ c^2b^2 }{ a }=1\]

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1i knew i forgot something

phi
 3 years ago
Best ResponseYou've already chosen the best response.1now, what is the pythagoras equation for this problem ?

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1what does that mean

phi
 3 years ago
Best ResponseYou've already chosen the best response.1do you know the pythagorean theorem ?

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1oh yea a^2+b^2=c^2

phi
 3 years ago
Best ResponseYou've already chosen the best response.1and what do you get if you subtract b^2 from both sides ?

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1c^2/a^2=1b^2

phi
 3 years ago
Best ResponseYou've already chosen the best response.1no, that is too complicated. start with a^2+b^2=c^2 and write b^2 on both sides and simplify

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1a^2+b^2b^2=c^2b^2 a^2=c^2b^2

phi
 3 years ago
Best ResponseYou've already chosen the best response.1now use that in your equation \[\frac{ c^2b^2 }{ a^2 }=1 \] I would replace the top

phi
 3 years ago
Best ResponseYou've already chosen the best response.1in other words c^2 b^2 is the same as a^2 (by pythagoras)

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1so what do we do now.....

phi
 3 years ago
Best ResponseYou've already chosen the best response.1the idea is that c^2b^2 = a^2 so replace c^2b^2 with a^2 in your equation \[ \frac{ c^2b^2 }{ a^2 }=1 \]

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1\[\frac{ a^2 }{ a^2 }=1\]

phi
 3 years ago
Best ResponseYou've already chosen the best response.1and something divided by itself is 1 i.e. a^2 divided by itself is 1 you get 1=1 and you are done. You showed both sides are equal

highschoolmom2010
 3 years ago
Best ResponseYou've already chosen the best response.1ty @phi & @ganeshie8
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