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stupidinmath

  • 2 years ago

If AD=BC, why is AE=BF?

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  1. stupidinmath
    • 2 years ago
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    If AD & BC are trisected.. |dw:1376758896091:dw|

  2. SamuelAlden917
    • 2 years ago
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    I'm good at math U+I=69.

  3. stupidinmath
    • 2 years ago
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    @SamuelAlden917 a good one huh? XD Silly

  4. SamuelAlden917
    • 2 years ago
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    Why don’t you be the numerator and I be the denominator and both of us reduce to simplest form?

  5. stupidinmath
    • 2 years ago
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    Bwahaha! You're making me laugh, really.

  6. SamuelAlden917
    • 2 years ago
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    1/3>((-1^1/5)/27U)^1/2 Simply this to know how I feel about you. i>3U

  7. stupidinmath
    • 2 years ago
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    *i>3U ? </3 haha

  8. surjithayer
    • 2 years ago
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    AD=BC \[\frac{ 1 }{3 }AD=\frac{ 1 }{ 3 }BC\] Or AE=BF

  9. stupidinmath
    • 2 years ago
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    Thank you @surjithayer :)

  10. surjithayer
    • 2 years ago
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    YW

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