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highschoolmom2010

  • one year ago

you see a rock climber on a cliff at a 32 degree angle. your eve level is 6 feet from the ground and you stand 1000 feet from the base of the cliff. what is the approx. height of the rock climber from the ground?

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  1. highschoolmom2010
    • one year ago
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    |dw:1376760311357:dw|

  2. ankit042
    • one year ago
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    You know how to write sin for a triangle?

  3. highschoolmom2010
    • one year ago
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    yes

  4. highschoolmom2010
    • one year ago
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    \[\sin \frac{ opp }{ hyp }\]

  5. ankit042
    • one year ago
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    Yes try using this here we know sin30=1/2

  6. highschoolmom2010
    • one year ago
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    where did you get that from

  7. ankit042
    • one year ago
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    sin30 is a standard angle...It is good to know value of sin 0,30,45,60,90 otherwise you can always use calculator :P

  8. highschoolmom2010
    • one year ago
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    oh yea ok

  9. ankit042
    • one year ago
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    Now can you proceed from here?

  10. highschoolmom2010
    • one year ago
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    eh no not really

  11. ankit042
    • one year ago
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    where are you stuck?

  12. highschoolmom2010
    • one year ago
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    basically the begining this confused me bc i was given the adjacent side to the angle

  13. ankit042
    • one year ago
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    Sorry I couldn't understand you...can you explain more

  14. timo86m
    • one year ago
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    you use cos not sin if you are given adjecent. But better yet this problem requires tan :P

  15. timo86m
    • one year ago
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    tan because you are given the adjecent. And wanna know the oppossite side.

  16. timo86m
    • one year ago
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    tan(30)=opp/adj=x/1000

  17. highschoolmom2010
    • one year ago
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    so i need to use tan

  18. timo86m
    • one year ago
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    Yup :D it is the simplest trig ID that has both opp and adj in it.

  19. timo86m
    • one year ago
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    tan(30)=opp/adj=x/1000 tan(30)=x/1000 solve for x can you do that?

  20. highschoolmom2010
    • one year ago
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    \[1000*\tan 30=\frac{ x }{ 1000 }*1000\] \[1000( \tan 30)=x\] but the angle is 32 degrees

  21. timo86m
    • one year ago
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    1000*tan 32 =x is right so far :D what you do now is evaluate tan 32 in degree mode SOrry at typo

  22. timo86m
    • one year ago
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    i must have look at that other guy who say sin 30 lol.

  23. highschoolmom2010
    • one year ago
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    1000 tan (32) gave me a crazy answer

  24. timo86m
    • one year ago
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    1000*(tan 32) =x ok so we got this far all we do is use our calculator making sure we in degree mode not radian mode tan32=0.62486935190932750978051082794943665831087020284270496 so we jsut plug that in 1000*.6248=624.8 ft sounds believeable. ooh plus 6 feet for the guys height at eye level 624.8+6

  25. highschoolmom2010
    • one year ago
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    so rock climber is approx. 630.8' from the ground

  26. timo86m
    • one year ago
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    if that is one of your answer choices :D use the one that is closest to our answer. oh and i would go with that lol.

  27. ankit042
    • one year ago
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    Ohh sorry I made a mistake...was multitasking :(

  28. highschoolmom2010
    • one year ago
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    i have no answer choices

  29. highschoolmom2010
    • one year ago
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    @timo86m

  30. timo86m
    • one year ago
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    go with 630.8 then

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