CD is tangent to circle O at D. Find the diameter of the circle for BC = 13 and DC = 30. Round to the nearest tenth. (The diagram is not drawn to scale.)

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CD is tangent to circle O at D. Find the diameter of the circle for BC = 13 and DC = 30. Round to the nearest tenth. (The diagram is not drawn to scale.)

Mathematics
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https://study.ashworthcollege.edu/access/content/group/45b8c516-1008-46d7-aa1d-bb9b62c786ff/geometry_exam_12_files/mc013-2.jpg
The theorem you need to solve this problem is attached below.
I see that but i really dont get how to do it.

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wait! 13(13=30)
13(13+30)
See if you can solve the equation. 30² = 13( 13 + x) where x = AB, the diameter of the circle.
Ohh...Okay
56.23
On the equation you wrote, you forgot to square the tangent length.
Oh i see
Is 56 right?
56.231 for x = AB which is the diameter is what I got. Same as your answer.
Round to the nearest tenth.
Okay thanks! Can you help me out with some other ones too please?
What is 56.231 to the nearest tenth?
56.2
Yes.
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Circle O and circle P are congruent. What can you conclude from the diagram? https://study.ashworthcollege.edu/access/content/group/45b8c516-1008-46d7-aa1d-bb9b62c786ff/geometry_exam_12_files/mc001-1.jpg
Please help...
I think you need the theorem that begins: In the same circle or in congruent circles, congruent central angles have ________________________________? That would be, I think, what you could conclude. But, first look up that theorem.
The same measure?

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