anonymous
  • anonymous
In circle O, m
Mathematics
schrodinger
  • schrodinger
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
https://study.ashworthcollege.edu/access/content/group/45b8c516-1008-46d7-aa1d-bb9b62c786ff/geometry_exam_12_files/mc008-3.jpg
Directrix
  • Directrix
Angle R is an inscribed angle of a circle. Use the attached theorem to get the measure of the arc it cuts off. The intercepted arc is in blue.
Directrix
  • Directrix
The measure of an inscribed angle is how related to its intercepted arc?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
I understand the theorem but how do find the length?
Directrix
  • Directrix
Read the part of the attachment that says that the measure of the inscribed angle is ...... ? What comes next?
anonymous
  • anonymous
1/2 the measue of the arc
anonymous
  • anonymous
so multply it by two?
Directrix
  • Directrix
Yes. So if angle R is 23, what is the measure of arc NQ ?
anonymous
  • anonymous
do its 46?
Directrix
  • Directrix
Yes. Next, do you see that central angle O cuts off the same arc that angle R did?
anonymous
  • anonymous
Right so 23?
Directrix
  • Directrix
No, the central angle is not 23. On the previous problem, what did we say is the measure of the central angle of a circle in relation to its intercepted arc?
anonymous
  • anonymous
1/2
Directrix
  • Directrix
No, that was the inscribed angle. We're talking central angles.
anonymous
  • anonymous
I have no idea...
Directrix
  • Directrix
Read this.
anonymous
  • anonymous
Okay i did..
anonymous
  • anonymous
It is the arc!
anonymous
  • anonymous
So the Angle is 46!
Directrix
  • Directrix
That is correct.
anonymous
  • anonymous
THANK YOU SOO MUCH!
Directrix
  • Directrix
You are welcome.
anonymous
  • anonymous
https://study.ashworthcollege.edu/access/content/group/45b8c516-1008-46d7-aa1d-bb9b62c786ff/geometry_exam_12_files/mc003-1.jpg For this wouldnt the X angle be 77?
Directrix
  • Directrix
Yes.
anonymous
  • anonymous
Because they are congruent right?
anonymous
  • anonymous
https://study.ashworthcollege.edu/access/content/group/45b8c516-1008-46d7-aa1d-bb9b62c786ff/geometry_exam_12_files/mc012-1.jpg This is confusing me again...
Directrix
  • Directrix
There is a little bit more to it. You don't know that the angles are congruent right off the bat. Look at the two congruent chords of the circle that go with the arcs cut off by the two central angles. Because in a circle, congruent chords have congruent arcs and the two central angles cut off congruent arcs, their measures are the same.
anonymous
  • anonymous
Okay, well thank you a lot!
Directrix
  • Directrix
We have done one like that.
Directrix
  • Directrix
Here's the theorem you need. ^^
Directrix
  • Directrix
So, what is the equation you would write to solve the equation.
anonymous
  • anonymous
Alright! I got it from here! Thanks man!
anonymous
  • anonymous
X^2=5(12+5)
Directrix
  • Directrix
Very good.
Directrix
  • Directrix
X^2 = ?
anonymous
  • anonymous
9.2?
anonymous
  • anonymous
85
anonymous
  • anonymous
Would it be 9.2 or 85???
Directrix
  • Directrix
x^2 = 85 x = 9.2? Yes.
anonymous
  • anonymous
Okay:) thanks!
Directrix
  • Directrix
I'll look for you online when I'm on. I enjoyed working with you.
anonymous
  • anonymous
Thanks same with you!

Looking for something else?

Not the answer you are looking for? Search for more explanations.