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raebaby420
Group Title
PLEASE HELP :3
Solve 2x + 5y = −13
3x − 4y = −8
(4, 1)
(−4, 1)
(4, −1)
(−4, −1)
 11 months ago
 11 months ago
raebaby420 Group Title
PLEASE HELP :3 Solve 2x + 5y = −13 3x − 4y = −8 (4, 1) (−4, 1) (4, −1) (−4, −1)
 11 months ago
 11 months ago

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raebaby420 Group TitleBest ResponseYou've already chosen the best response.0
@Jack1 for ones like these: there is no parenthesis, or exponents, so I staret with the multiplication.. I want to get my y's to one side.. how do I do that? I divide them?
 11 months ago

Jack1 Group TitleBest ResponseYou've already chosen the best response.0
i like to subtract first to isolate the one term on one side so 2x + 5y = −13 2x = 13 5y x = (13/2)  (5/2)y
 11 months ago

Jack1 Group TitleBest ResponseYou've already chosen the best response.0
or if not, get them both in terms of 6x
 11 months ago

Jack1 Group TitleBest ResponseYou've already chosen the best response.0
2x + 5y = 13 so 6x + 15y = 39 and 3x  4y = 8 so 6x  8y = 16 therefore 6x = 39  15y and 6x = 16 + 8y
 11 months ago

raebaby420 Group TitleBest ResponseYou've already chosen the best response.0
AH I thought so, u do them apart and I knew I took the 5 from that side
 11 months ago

Nurali Group TitleBest ResponseYou've already chosen the best response.1
2x + 5y = −13(1) 3x − 4y = −8 (2) in equation 1 2x=135y x=135y/2 put x in equation 2 3(135y/2)4y=8 3915y/24y=8 3915y8y=16 23y=16+39 23y=23 y=1 put y in equation 1 2x + 5y = −13 2x+5(1)=13 2x5=13 2x=13+5 2x=8 x=4
 11 months ago

Jack1 Group TitleBest ResponseYou've already chosen the best response.0
6x = 39  15y = 16 + 8y 39  15y = 16 + 8y 39 = 16 + 23y 23 = 23y 1 = y
 11 months ago

raebaby420 Group TitleBest ResponseYou've already chosen the best response.0
I see.
 11 months ago

raebaby420 Group TitleBest ResponseYou've already chosen the best response.0
The next one I have I have to get the value of y.. is it the same way we get the value of x?
 11 months ago

Jack1 Group TitleBest ResponseYou've already chosen the best response.0
exactly the same way, it doesn't matter if the term is called x or y or q, its all the same when using simultaneous equations
 11 months ago

raebaby420 Group TitleBest ResponseYou've already chosen the best response.0
Ok I think I gotcha
 11 months ago

raebaby420 Group TitleBest ResponseYou've already chosen the best response.0
What is the value of y in the solution to the following system of equations? 5x − 3y = −11 2x − 6y = −14 −1 0 1 2
 11 months ago

raebaby420 Group TitleBest ResponseYou've already chosen the best response.0
This is what I have. ill let u no what I get
 11 months ago

raebaby420 Group TitleBest ResponseYou've already chosen the best response.0
ok so I got
 11 months ago

raebaby420 Group TitleBest ResponseYou've already chosen the best response.0
5x3y=11 +3y ____________ 5x=11+3y
 11 months ago

raebaby420 Group TitleBest ResponseYou've already chosen the best response.0
correct?
 11 months ago

uri Group TitleBest ResponseYou've already chosen the best response.0
where is +3y coming from?
 11 months ago

Jack1 Group TitleBest ResponseYou've already chosen the best response.0
ignore uri, he's a little slow and apparently i hate him ;D
 11 months ago

uri Group TitleBest ResponseYou've already chosen the best response.0
Huh? I'm a girl..and that's not the way to talk.
 11 months ago

raebaby420 Group TitleBest ResponseYou've already chosen the best response.0
Where do I go from 5x=11+3y
 11 months ago

Jack1 Group TitleBest ResponseYou've already chosen the best response.0
sure u are... online anyway an i bet u tell that to all the boys ;P
 11 months ago

uri Group TitleBest ResponseYou've already chosen the best response.0
Ah? last time i checked..i was a girl.
 11 months ago

Jack1 Group TitleBest ResponseYou've already chosen the best response.0
double it change it to 10x
 11 months ago

raebaby420 Group TitleBest ResponseYou've already chosen the best response.0
..... sooo no one is going to help me but we will argue on my question?... Thanks guys
 11 months ago

raebaby420 Group TitleBest ResponseYou've already chosen the best response.0
Now your confusing me and not helping me
 11 months ago

Jack1 Group TitleBest ResponseYou've already chosen the best response.0
5x=11+3y 10x = 22 + 6
 11 months ago

uri Group TitleBest ResponseYou've already chosen the best response.0
You are not even teaching her the right thing.Also,You are very mean and you don't know how to respond to someone..when they ask you a question. I might link you this:http://openstudy.com/codeofconduct Next time if you're mean to me.I'll report you to Preetha. @Jack1
 11 months ago

Jack1 Group TitleBest ResponseYou've already chosen the best response.0
so thats equation 1 in a form we can use now for equation 2: 2x − 6y = −14 change it so u get 10x on one side
 11 months ago

Jack1 Group TitleBest ResponseYou've already chosen the best response.0
sorry, back to equation 1: it should be 10x = 22 + 6y, not 10x = 22 + 6, my bad now equation 2: 2x − 6y = −14 (times 5) 10x  30y = 70 (add 30y to both sides) 10x  30y + 30y = 70 + 30y 10x = 70 + 30y
 11 months ago

Jack1 Group TitleBest ResponseYou've already chosen the best response.0
so equation 1 is now 10x = 22 + 6y and equation 2 is now 10x = 70 + 30y so 10x = 22 + 6y = 70 + 30y 22 + 6y = 70 + 30y can u solve from here?
 11 months ago

thomaster Group TitleBest ResponseYou've already chosen the best response.0
@Jack1 She made a new question http://openstudy.com/study#/updates/52120b0fe4b0450ed75d4d22
 11 months ago

Jack1 Group TitleBest ResponseYou've already chosen the best response.0
@raebaby420
 11 months ago

Jack1 Group TitleBest ResponseYou've already chosen the best response.0
god u are such a girl XP
 11 months ago

uri Group TitleBest ResponseYou've already chosen the best response.0
You called me a boy dat mad me cry..:3
 11 months ago

Jack1 Group TitleBest ResponseYou've already chosen the best response.0
im sorry i called u a boy, i was jus playing and i took it too far, my bad
 11 months ago

uri Group TitleBest ResponseYou've already chosen the best response.0
It's alright.
 11 months ago
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