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Can someone help me reduce 141/60

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does it help to know that \(141\) is divisible by \(3\) because \(1+4+1=6\) is also divisible by \(3\) ?
i.e. divide top and bottom by 3 to get your answer

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Other answers:

How would you turn that into a mixed fraction?
how many times does 20 go in to 47 ?
right and the remainder is going to be 7 right?
mixed number will be \[\large 2\tfrac{7}{20}\]
@AngelDreamGurl Do you remember long division with remainders? The remainder is the numerator and the divisor is the denominator.
Ok thanks

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