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OpenSessame Group Title

Compare the quantity in Column A with the quantity in Column B. PA is tangent to the circle at A. https://study.ashworthcollege.edu/access/content/group/45b8c516-1008-46d7-aa1d-bb9b62c786ff/geometry_exam_12_files/mc011-2.jpg

  • one year ago
  • one year ago

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  1. OpenSessame Group Title
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    Column A: AP Column B: AX

    • one year ago
  2. OpenSessame Group Title
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    A. The quantity in Column A is greater. B. The quantity in Column B is greater. C. The two quantities are equal. D. The relationship cannot be determined from the information given.

    • one year ago
  3. Mandre Group Title
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    From what I can see D is the answer, but I might be missing something so maybe someone who knows better than me will answer :).

    • one year ago
  4. OpenSessame Group Title
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    Okay, thanks:)

    • one year ago
  5. OpenSessame Group Title
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    @Directrix Help me out again please?

    • one year ago
  6. Directrix Group Title
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    Are we given that segment AP is a tangent to the circle. This type problem, Quantitative Comparison, was on the SATs at one time. So, if segment AP is a tangent, it will be stated. Look at the question and see. And, if there are several questions based on this diagram, look above the first question for given information.

    • one year ago
  7. OpenSessame Group Title
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    Whats given, im not sure how to read the picture?

    • one year ago
  8. OpenSessame Group Title
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    I just know the two things im supposed to compare and that AP is tangent.

    • one year ago
  9. dumbcow Group Title
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    ok here is what you need...look at first 2 theorems http://en.wikipedia.org/wiki/Circles#Theorems

    • one year ago
  10. dumbcow Group Title
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    from those you can find.... AX = 9 AP = 2sqrt13

    • one year ago
  11. Directrix Group Title
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    AP = 2sqrt13 is based on the assumption that segment AP is a tangent, is it not? @dumbcow

    • one year ago
  12. dumbcow Group Title
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    it states that AP is tangent to circle

    • one year ago
  13. Directrix Group Title
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    @OpenSessame The solution for AX comes from this theorem:

    • one year ago
  14. OpenSessame Group Title
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    So that would mean that AP is bigger?

    • one year ago
  15. OpenSessame Group Title
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    The problem is thats what i got at first and it said it was wrong. And Directrix is says that PA is tangent of the circle.

    • one year ago
  16. dumbcow Group Title
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    in original post "Compare the quantity in Column A with the quantity in Column B. PA is tangent to the circle at A. "

    • one year ago
  17. Directrix Group Title
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    1) The problem is thats what i got at first and it said it was wrong. --> I don't know what you are saying here. What did you write the first time and was told what you wrote is wrong? 2) is says that PA is tangent of the circle. Okay. Finally, I see it. Thanks for your patience on that.

    • one year ago
  18. Directrix Group Title
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    @OpenSessame Tell me about this: 1) The problem is thats what i got at first and it said it was wrong. --> I don't know what you are saying here. What did you write the first time and was told what you wrote is wrong?

    • one year ago
  19. OpenSessame Group Title
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    That AP is the bigger quantity.

    • one year ago
  20. Directrix Group Title
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    AX = 9 = sqrt(81) ----> LARGER AP = 2sqrt13 = sqrt(52)

    • one year ago
  21. OpenSessame Group Title
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    So the answer would be B?

    • one year ago
  22. Directrix Group Title
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    Yes.

    • one year ago
  23. OpenSessame Group Title
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    Okay thanks! I have a few other questions i need help with...

    • one year ago
  24. Directrix Group Title
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    Close this thread and open a new post. I'll meet you at the new post.

    • one year ago
  25. OpenSessame Group Title
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    Okay!

    • one year ago
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