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I got .53 Using sin
Not sin :P We need to use a trig function that includes a known quantity as well as the unknown one. Sin is opposite over hypotenuse, but the hypotenuse gives us no information. We use tangent because tangent is opposite over adjacent, which includes our x as well as our known quantity
Sine is opposite over hypotenuse. You have opposite side over adjacent side which is NOT sine.
I thought we would do...|dw:1377069953819:dw|
Interesting, law of sines O.o
Not necessary, though.
I dont know then...:(
Checked it, answer is the same, just.....a much longer way of doing it that isnt needed xD
Yeah, it's the same answer doing it the faster way with tangent. It's nice to know the law of sines, but you should also know the more efficient way of doing this problem :3
I thought that was more efficient cause i can do it really easy that way...
Well, do whats comfortable of course. But do you understand what I did by chance?
Yes you used tan and then multiplied.
Mhm. As long as you know what I did, then thats fine. The more you know the better, but use whats comfortable in the end. You got the right answer, so good job!