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OpenSessame Group Title

In circle O, PA and PB are tangents. a. Prove APO = BPO . b. Find m BOD for m AOP = 64. Explain your reasoning.

  • one year ago
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    @Directrix

    • one year ago
  3. Directrix Group Title
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    Is this --> APO = BPO supposed to be △APO ≅ △BPO ?

    • one year ago
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    Yes i didnt know how to write the triangle thing...

    • one year ago
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    I know how to do B but a is were im confused...

    • one year ago
  6. Directrix Group Title
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    First, the marked up diagram.

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  7. Directrix Group Title
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    I'll do the statements; you do the reasons after I get the statements posted.

    • one year ago
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    OKay!

    • one year ago
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    Okay the first is given. and the second is a rule i cant but my finger on the name but says that if a circle has two tangents they are perpendicular.

    • one year ago
  10. Directrix Group Title
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    1. Circle O with tangents PA and PB 2. Segment AO is perpendicular to Segment PA Segment OB is perpendicular to Segment PB 3. △APO and △BPO are right triangles 4. PA = PB 5. PO = PO 6. △APO ≅ △BPO --------- <POA ≅ <POB

    • one year ago
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    1. Given 2. If a radius is drawn to a tangent to a circle at the point of tangency, the the radius is perpendicular to the tangent. 3.

    • one year ago
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    Just saw that lol, three because they are tangents so they touch the other line at 90 degrees

    • one year ago
  13. Directrix Group Title
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    How about those reasons - you have more to do.

    • one year ago
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    Im seriously lost at theorems and things thats mainly what i need help with...

    • one year ago
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    You'll need to study them and then to learn them. There's just no getting around that in Geometry. They come back after proofs in the form of problems to work.

    • one year ago
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    Ugh:( I hate Geometry lol...

    • one year ago
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    1. Given 2. If a radius is drawn to a tangent to a circle at the point of tangency, the the radius is perpendicular to the tangent. 3. Definition of right triangles. 4. Tangents drawn to a circle from an outside point are congruent. 5. Reflexive Property 6. HL (Hypotenuse Leg) Theorem You'll need this for part two which you said you had done. <POA ≅ <POB Corresponding parts of congruent triangles are congruent.

    • one year ago
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    You're up for part 2.

    • one year ago
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    For part two...

    • one year ago
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    Since AOP and AOB are congruent you can think of AOB as 64 too. Now these two angles make a straight line and a straight line is 180 degrees so the two angles added together must be 180. 180 – 64 = 116 degrees is <BOD.

    • one year ago
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    I think 116 is correct.

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    Okay :)

    • one year ago
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    I don't know which theorems your class has studied up until this point but I think the ones in the proof will be okay. After you study them more, then we can talk about their application. You obviously know many of them but are a little rusty on others. No big deal. Just make yourself study them.

    • one year ago
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    im studing for the final so like everything...

    • one year ago
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    Tmrw...

    • one year ago
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