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Is this --> APO = BPO supposed to be △APO ≅ △BPO ?

Yes i didnt know how to write the triangle thing...

I know how to do B but a is were im confused...

First, the marked up diagram.

I'll do the statements; you do the reasons after I get the statements posted.

OKay!

1. Circle O with tangents PA and PB
2. Segment AO is perpendicular to Segment PA
Segment OB is perpendicular to Segment PB
3. △APO and △BPO are right triangles
4. PA = PB
5. PO = PO
6. △APO ≅ △BPO
---------

Just saw that lol, three because they are tangents so they touch the other line at 90 degrees

How about those reasons - you have more to do.

Im seriously lost at theorems and things thats mainly what i need help with...

Ugh:( I hate Geometry lol...

1. Given
2. If a radius is drawn to a tangent to a circle at the point of tangency, the the radius is perpendicular to the tangent.
3. Definition of right triangles.
4. Tangents drawn to a circle from an outside point are congruent.
5. Reflexive Property
6. HL (Hypotenuse Leg) Theorem
You'll need this for part two which you said you had done.

You're up for part 2.

For part two...

Since AOP and AOB are congruent you can think of AOB as 64 too. Now these two angles make a straight line and a straight line is 180 degrees so the two angles added together must be 180.
180 – 64 = 116 degrees is

I think 116 is correct.

Okay :)

im studing for the final so like everything...

Tmrw...