anonymous
  • anonymous
In circle O, PA and PB are tangents. a. Prove APO = BPO . b. Find m BOD for m AOP = 64. Explain your reasoning.
Mathematics
schrodinger
  • schrodinger
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
@Directrix
Directrix
  • Directrix
Is this --> APO = BPO supposed to be △APO ≅ △BPO ?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Yes i didnt know how to write the triangle thing...
anonymous
  • anonymous
I know how to do B but a is were im confused...
Directrix
  • Directrix
First, the marked up diagram.
1 Attachment
Directrix
  • Directrix
I'll do the statements; you do the reasons after I get the statements posted.
anonymous
  • anonymous
OKay!
anonymous
  • anonymous
Okay the first is given. and the second is a rule i cant but my finger on the name but says that if a circle has two tangents they are perpendicular.
Directrix
  • Directrix
1. Circle O with tangents PA and PB 2. Segment AO is perpendicular to Segment PA Segment OB is perpendicular to Segment PB 3. △APO and △BPO are right triangles 4. PA = PB 5. PO = PO 6. △APO ≅ △BPO ---------
Directrix
  • Directrix
1. Given 2. If a radius is drawn to a tangent to a circle at the point of tangency, the the radius is perpendicular to the tangent. 3.
anonymous
  • anonymous
Just saw that lol, three because they are tangents so they touch the other line at 90 degrees
Directrix
  • Directrix
How about those reasons - you have more to do.
anonymous
  • anonymous
Im seriously lost at theorems and things thats mainly what i need help with...
Directrix
  • Directrix
You'll need to study them and then to learn them. There's just no getting around that in Geometry. They come back after proofs in the form of problems to work.
anonymous
  • anonymous
Ugh:( I hate Geometry lol...
Directrix
  • Directrix
1. Given 2. If a radius is drawn to a tangent to a circle at the point of tangency, the the radius is perpendicular to the tangent. 3. Definition of right triangles. 4. Tangents drawn to a circle from an outside point are congruent. 5. Reflexive Property 6. HL (Hypotenuse Leg) Theorem You'll need this for part two which you said you had done.
Directrix
  • Directrix
You're up for part 2.
anonymous
  • anonymous
For part two...
anonymous
  • anonymous
Since AOP and AOB are congruent you can think of AOB as 64 too. Now these two angles make a straight line and a straight line is 180 degrees so the two angles added together must be 180. 180 – 64 = 116 degrees is
Directrix
  • Directrix
I think 116 is correct.
1 Attachment
anonymous
  • anonymous
Okay :)
Directrix
  • Directrix
I don't know which theorems your class has studied up until this point but I think the ones in the proof will be okay. After you study them more, then we can talk about their application. You obviously know many of them but are a little rusty on others. No big deal. Just make yourself study them.
anonymous
  • anonymous
im studing for the final so like everything...
anonymous
  • anonymous
Tmrw...

Looking for something else?

Not the answer you are looking for? Search for more explanations.