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valiyuh Group Title

m is the segment bisector of segment JK . JM= 1/8x , and JK= 3/4x-6 . How do i find MK? Help?

  • one year ago
  • one year ago

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  1. mathstudent55 Group Title
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    What does segment bisector mean?

    • one year ago
  2. valiyuh Group Title
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    its a line that divides a segment in half?

    • one year ago
  3. mathstudent55 Group Title
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    Right. In this case, I think M is simply a point, but it still cuts the segment JK into two congruent segments.

    • one year ago
  4. mathstudent55 Group Title
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    |dw:1377144056587:dw|

    • one year ago
  5. mathstudent55 Group Title
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    Ok?

    • one year ago
  6. mathstudent55 Group Title
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    Since M is a bisector, what do you know about the length of JM and the length of KM?

    • one year ago
  7. valiyuh Group Title
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    Well i know that since m is the bisector both sides are equal which mean that since JM is 1/8x MK is also 1/8x

    • one year ago
  8. mathstudent55 Group Title
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    Good. |dw:1377144680791:dw|

    • one year ago
  9. mathstudent55 Group Title
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    Form the figure you see that JM + MK = JK, right?

    • one year ago
  10. valiyuh Group Title
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    yes .

    • one year ago
  11. mathstudent55 Group Title
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    Great. Below JM, MK, and JK, can you write what each one is equal to? Copy my line below and write it below that line. JM + MK = JK

    • one year ago
  12. valiyuh Group Title
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    1/8x + 1/8x = 3/4x-6 like this?

    • one year ago
  13. mathstudent55 Group Title
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    Exactly. That is the equation you must solve now to find x.

    • one year ago
  14. mathstudent55 Group Title
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    \( \dfrac{1}{8}x + \dfrac{1}{8}x = \dfrac{3}{4}x - 6\) Solve for x.

    • one year ago
  15. valiyuh Group Title
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    This is the part were im getting confused? Do i add both 1/8x to get 2/8x? or am i wrong?

    • one year ago
  16. mathstudent55 Group Title
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    Yes, you are correct. \(\dfrac{2}{8}x = \dfrac{3}{4}x - 6 \) The fraction on the left can be reduced.

    • one year ago
  17. valiyuh Group Title
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    alright so now i subtract the 3/4 to the other side so now its 2/8 - 3/4?

    • one year ago
  18. mathstudent55 Group Title
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    Why don't you reduce the 2/8 fraction first?

    • one year ago
  19. mathstudent55 Group Title
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    \(\dfrac{1}{4}x = \dfrac{3}{4}x - 6 \)

    • one year ago
  20. mathstudent55 Group Title
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    Now the fractions have a common denominator. Now you can subtract (3/4)x over to the left side.

    • one year ago
  21. valiyuh Group Title
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    it gave me -2x=-6?

    • one year ago
  22. mathstudent55 Group Title
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    What happened to the denominator of 4? You subtracted 1/4 - 3/4, not 1 - 3.

    • one year ago
  23. mathstudent55 Group Title
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    \(\dfrac{1}{4}x - \dfrac{3}{4}x = - 6 \) \(-\dfrac{2}{4}x = - 6 \)

    • one year ago
  24. valiyuh Group Title
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    oh okay i see and from there i cancel the -2/4x and take it to the other side having -6/-2/4 right?

    • one year ago
  25. mathstudent55 Group Title
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    Now you multiply both sides by -4/2.

    • one year ago
  26. mathstudent55 Group Title
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    \( -\dfrac{4}{2}\left( -\dfrac{2}{4}x \right) = -\dfrac{4}{2}(- 6) \)

    • one year ago
  27. mathstudent55 Group Title
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    Did you get an answer for x?

    • one year ago
  28. valiyuh Group Title
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    12?

    • one year ago
  29. mathstudent55 Group Title
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    Correct.

    • one year ago
  30. mathstudent55 Group Title
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    After you multiply out the right side, you get x = 12. That's not the final answer of the problem, because the problem asks what is MK.

    • one year ago
  31. valiyuh Group Title
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    yes thats correct.

    • one year ago
  32. mathstudent55 Group Title
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    Above, you had written an expression for MK in terms of x. Now you know x, so you can find MK. MK = (1/8)x, and x = 12, so what is MK?

    • one year ago
  33. valiyuh Group Title
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    1.5?

    • one year ago
  34. mathstudent55 Group Title
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    Yes. MK = 12/8 = 1.5

    • one year ago
  35. mathstudent55 Group Title
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    You got it! Great job.

    • one year ago
  36. valiyuh Group Title
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    Thank you so much you really helped me !(:

    • one year ago
  37. mathstudent55 Group Title
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    You are very welcome.

    • one year ago
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