Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

Solve the system 2x + 2y = -6 and 3x - 2y = 11 by using graph paper or graphing technology. What is the solution to the system? (-1, -7) (1, -4) (2, -1) (3, -2)

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SIGN UP FOR FREE
It would be a far greater service to her, and also comply with the code of conduct of the site, to explain to her HOW to arrive at an answer, rather than just spit it out. http://openstudy.com/code-of-conduct
@raebaby420, it says to "solve by graphing". Do you know how to graph each of those 2 lines? Once you graph the 2 lines, do you know what it means for a point to be a "solution to the system"? The system has 2 equations, each one graphs as a line. so every point on ONE line is a solution to THAT equation; every point on the OTHER line is a solution to THAT equation. To be a solution TO THE SYSTEM, a point would have to be on BOTH lines. When you have a graph of 2 lines (that are not parallel), what point is on BOTH lines? That is, how do you tell when you look at the graph which point is on BOTH?
@DebbieG u right... sorry...

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Not the answer you are looking for?

Search for more explanations.

Ask your own question