Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

sihelp

  • one year ago

If the names of 5 boys and 7 girls are written on slips of paper in hat, what are the odds that the first two slips drawn from the hat will name 2 girls?

  • This Question is Open
  1. kropot72
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    The odds are the ratio of an event occurring to that of its not occurring. The probability that the first slip drawn has a girl's name is 7/12. Having drawn a girl's name first, the probability of the second slip drawn having a girl's name is 6/11. Therefore \[P(2\ girl's\ names)=\frac{7\times6}{12\times11}=\frac{7}{22}\] The probability of the first two slips not naming two girls is given by \[P(other\ than\ 2\ girl's\ names)=1-P(2\ girl's\ names)=1-\frac{7}{22}=\frac{15}{22}\] Therefore the required odds are \[\frac{7}{22}:\frac{15}{22}=7:15\]

  2. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.