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anonymous
 2 years ago
If the names of 5 boys and 7 girls are written on slips of paper in hat, what are the odds that the first two slips drawn from the hat will name 2 girls?
anonymous
 2 years ago
If the names of 5 boys and 7 girls are written on slips of paper in hat, what are the odds that the first two slips drawn from the hat will name 2 girls?

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kropot72
 2 years ago
Best ResponseYou've already chosen the best response.0The odds are the ratio of an event occurring to that of its not occurring. The probability that the first slip drawn has a girl's name is 7/12. Having drawn a girl's name first, the probability of the second slip drawn having a girl's name is 6/11. Therefore \[P(2\ girl's\ names)=\frac{7\times6}{12\times11}=\frac{7}{22}\] The probability of the first two slips not naming two girls is given by \[P(other\ than\ 2\ girl's\ names)=1P(2\ girl's\ names)=1\frac{7}{22}=\frac{15}{22}\] Therefore the required odds are \[\frac{7}{22}:\frac{15}{22}=7:15\]
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