anonymous
  • anonymous
If the names of 5 boys and 7 girls are written on slips of paper in hat, what are the odds that the first two slips drawn from the hat will name 2 girls?
Probability
schrodinger
  • schrodinger
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

kropot72
  • kropot72
The odds are the ratio of an event occurring to that of its not occurring. The probability that the first slip drawn has a girl's name is 7/12. Having drawn a girl's name first, the probability of the second slip drawn having a girl's name is 6/11. Therefore \[P(2\ girl's\ names)=\frac{7\times6}{12\times11}=\frac{7}{22}\] The probability of the first two slips not naming two girls is given by \[P(other\ than\ 2\ girl's\ names)=1-P(2\ girl's\ names)=1-\frac{7}{22}=\frac{15}{22}\] Therefore the required odds are \[\frac{7}{22}:\frac{15}{22}=7:15\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Looking for something else?

Not the answer you are looking for? Search for more explanations.