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anonymous
 3 years ago
(csc x + 1)(csc x  1)
anonymous
 3 years ago
(csc x + 1)(csc x  1)

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NoelGreco
 3 years ago
Best ResponseYou've already chosen the best response.0FOIL it and apply trig identity

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so its \[(\csc x)^21=cot^22x\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@itsmylife how did you get that

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0can you show how you got that plz

NoelGreco
 3 years ago
Best ResponseYou've already chosen the best response.0There are three Pythagorean trig identities that you simply must memorize.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0go here @pvs285 http://www.sosmath.com/trig/Trig5/trig5/trig5.html

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0can you just show the work to answer this question plz?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\left( \csc x+1 \right)\left( \csc x1 \right)=\csc ^{2}x1=\cot ^{2}x\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\sin^2x+\cos^2x=1,\frac{ \sin^2 x}{ \sin^2x }+\frac{ \cos^2x }{ \sin^2x }=\frac{ 1 }{ \sin^2x }, 1+\cot^2x=cosec^2x\]

NoelGreco
 3 years ago
Best ResponseYou've already chosen the best response.0It is against the policies of this site to simply provide answers.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0huh u said it was cot^2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ik i whant you to explain it to me so i uderstand

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it might be a mistake ;)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\csc ^{2}x\cot ^{2}=1,or \csc ^{2}x1=\cot ^{2}x\] It is an identity.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so there is no work involved?

NoelGreco
 3 years ago
Best ResponseYou've already chosen the best response.0pvs: it appears you are in over your head. If you have a question such as this, and can't pick up on the idea of a trig identity you might want to slow down and back up.

ybarrap
 3 years ago
Best ResponseYou've already chosen the best response.0$$ \tt \bf \Large(\csc x + 1)(\csc x 1)\\ \Large=\csc^2x\csc x +\csc x 1\\ \Large=\csc^2x1\\\\ \Large=\left(\dfrac{1}{\sin x}\right)^21\\ \Large=\dfrac{1}{\sin^2x}1\\ \Large=\dfrac{1}{\sin^2x}\dfrac{\sin^2x}{\sin^2x}\\\\ \Large=\dfrac{1\sin^2x}{\cos^2x}\\\\ \Large=\dfrac{\cos^2x}{\sin^2x}\\\\ \Large=\cot^2x $$ Please let me kow if you have any questions. Good luck.
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