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NoelGreco
 one year ago
Best ResponseYou've already chosen the best response.0FOIL it and apply trig identity

itsmylife
 one year ago
Best ResponseYou've already chosen the best response.0so its \[(\csc x)^21=cot^22x\]

pvs285
 one year ago
Best ResponseYou've already chosen the best response.0@itsmylife how did you get that

pvs285
 one year ago
Best ResponseYou've already chosen the best response.0can you show how you got that plz

itsmylife
 one year ago
Best ResponseYou've already chosen the best response.0pythagorean identity

NoelGreco
 one year ago
Best ResponseYou've already chosen the best response.0There are three Pythagorean trig identities that you simply must memorize.

itsmylife
 one year ago
Best ResponseYou've already chosen the best response.0go here @pvs285 http://www.sosmath.com/trig/Trig5/trig5/trig5.html

pvs285
 one year ago
Best ResponseYou've already chosen the best response.0can you just show the work to answer this question plz?

surjithayer
 one year ago
Best ResponseYou've already chosen the best response.1\[\left( \csc x+1 \right)\left( \csc x1 \right)=\csc ^{2}x1=\cot ^{2}x\]

itsmylife
 one year ago
Best ResponseYou've already chosen the best response.0\[\sin^2x+\cos^2x=1,\frac{ \sin^2 x}{ \sin^2x }+\frac{ \cos^2x }{ \sin^2x }=\frac{ 1 }{ \sin^2x }, 1+\cot^2x=cosec^2x\]

NoelGreco
 one year ago
Best ResponseYou've already chosen the best response.0It is against the policies of this site to simply provide answers.

pvs285
 one year ago
Best ResponseYou've already chosen the best response.0huh u said it was cot^2

pvs285
 one year ago
Best ResponseYou've already chosen the best response.0ik i whant you to explain it to me so i uderstand

itsmylife
 one year ago
Best ResponseYou've already chosen the best response.0it might be a mistake ;)

surjithayer
 one year ago
Best ResponseYou've already chosen the best response.1\[\csc ^{2}x\cot ^{2}=1,or \csc ^{2}x1=\cot ^{2}x\] It is an identity.

pvs285
 one year ago
Best ResponseYou've already chosen the best response.0so there is no work involved?

NoelGreco
 one year ago
Best ResponseYou've already chosen the best response.0pvs: it appears you are in over your head. If you have a question such as this, and can't pick up on the idea of a trig identity you might want to slow down and back up.

ybarrap
 one year ago
Best ResponseYou've already chosen the best response.0$$ \tt \bf \Large(\csc x + 1)(\csc x 1)\\ \Large=\csc^2x\csc x +\csc x 1\\ \Large=\csc^2x1\\\\ \Large=\left(\dfrac{1}{\sin x}\right)^21\\ \Large=\dfrac{1}{\sin^2x}1\\ \Large=\dfrac{1}{\sin^2x}\dfrac{\sin^2x}{\sin^2x}\\\\ \Large=\dfrac{1\sin^2x}{\cos^2x}\\\\ \Large=\dfrac{\cos^2x}{\sin^2x}\\\\ \Large=\cot^2x $$ Please let me kow if you have any questions. Good luck.
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