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NoelGrecoBest ResponseYou've already chosen the best response.0
FOIL it and apply trig identity
 8 months ago

itsmylifeBest ResponseYou've already chosen the best response.0
so its \[(\csc x)^21=cot^22x\]
 8 months ago

pvs285Best ResponseYou've already chosen the best response.0
@itsmylife how did you get that
 8 months ago

pvs285Best ResponseYou've already chosen the best response.0
can you show how you got that plz
 8 months ago

itsmylifeBest ResponseYou've already chosen the best response.0
pythagorean identity
 8 months ago

NoelGrecoBest ResponseYou've already chosen the best response.0
There are three Pythagorean trig identities that you simply must memorize.
 8 months ago

itsmylifeBest ResponseYou've already chosen the best response.0
go here @pvs285 http://www.sosmath.com/trig/Trig5/trig5/trig5.html
 8 months ago

pvs285Best ResponseYou've already chosen the best response.0
can you just show the work to answer this question plz?
 8 months ago

surjithayerBest ResponseYou've already chosen the best response.1
\[\left( \csc x+1 \right)\left( \csc x1 \right)=\csc ^{2}x1=\cot ^{2}x\]
 8 months ago

itsmylifeBest ResponseYou've already chosen the best response.0
\[\sin^2x+\cos^2x=1,\frac{ \sin^2 x}{ \sin^2x }+\frac{ \cos^2x }{ \sin^2x }=\frac{ 1 }{ \sin^2x }, 1+\cot^2x=cosec^2x\]
 8 months ago

NoelGrecoBest ResponseYou've already chosen the best response.0
It is against the policies of this site to simply provide answers.
 8 months ago

pvs285Best ResponseYou've already chosen the best response.0
huh u said it was cot^2
 8 months ago

pvs285Best ResponseYou've already chosen the best response.0
ik i whant you to explain it to me so i uderstand
 8 months ago

itsmylifeBest ResponseYou've already chosen the best response.0
it might be a mistake ;)
 8 months ago

surjithayerBest ResponseYou've already chosen the best response.1
\[\csc ^{2}x\cot ^{2}=1,or \csc ^{2}x1=\cot ^{2}x\] It is an identity.
 8 months ago

pvs285Best ResponseYou've already chosen the best response.0
so there is no work involved?
 8 months ago

NoelGrecoBest ResponseYou've already chosen the best response.0
pvs: it appears you are in over your head. If you have a question such as this, and can't pick up on the idea of a trig identity you might want to slow down and back up.
 8 months ago

ybarrapBest ResponseYou've already chosen the best response.0
$$ \tt \bf \Large(\csc x + 1)(\csc x 1)\\ \Large=\csc^2x\csc x +\csc x 1\\ \Large=\csc^2x1\\\\ \Large=\left(\dfrac{1}{\sin x}\right)^21\\ \Large=\dfrac{1}{\sin^2x}1\\ \Large=\dfrac{1}{\sin^2x}\dfrac{\sin^2x}{\sin^2x}\\\\ \Large=\dfrac{1\sin^2x}{\cos^2x}\\\\ \Large=\dfrac{\cos^2x}{\sin^2x}\\\\ \Large=\cot^2x $$ Please let me kow if you have any questions. Good luck.
 8 months ago
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