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raebaby420
Group Title
Please help..
What are the solutions to the following system of equations?
y = x2 + 12x + 30
8x − y = 10
(−4, −2) and (2, 5)
(−2, −4) and (2, 5)
(−2, −4) and (5, 2)
No Real Solutions
 11 months ago
 11 months ago
raebaby420 Group Title
Please help.. What are the solutions to the following system of equations? y = x2 + 12x + 30 8x − y = 10 (−4, −2) and (2, 5) (−2, −4) and (2, 5) (−2, −4) and (5, 2) No Real Solutions
 11 months ago
 11 months ago

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raebaby420 Group TitleBest ResponseYou've already chosen the best response.0
@Nurali
 11 months ago

uri Group TitleBest ResponseYou've already chosen the best response.0
@DebbieG Help her ^_^ Uri is proud of you.
 11 months ago

DebbieG Group TitleBest ResponseYou've already chosen the best response.0
What methods have you learned for solving a system? Substitution, elimination?
 11 months ago

raebaby420 Group TitleBest ResponseYou've already chosen the best response.0
Elimination I think
 11 months ago

raebaby420 Group TitleBest ResponseYou've already chosen the best response.0
And some substitution but I cant remember how to do that method
 11 months ago

DebbieG Group TitleBest ResponseYou've already chosen the best response.0
I would probably opt for substitution here, since you have a quadratic (a parabola) and a linear equation (a line). But either would work. If you solve the 2nd equation for y, then you have two equations that both give y as a function of x, right? E.g., you have y={some stuff} and y={some different stuff} so since y= both of those things, you can set them equal to each other.
 11 months ago

DebbieG Group TitleBest ResponseYou've already chosen the best response.0
When you do that, you'll have a single, quadratic equation to solve.
 11 months ago

raebaby420 Group TitleBest ResponseYou've already chosen the best response.0
..... that makes no sense
 11 months ago

DebbieG Group TitleBest ResponseYou've already chosen the best response.0
What part didn't make sense? Here are your two equations: \[y=x^2+12x+30\]\[8xy=10\]Can you solve the 2nd one for y?
 11 months ago

raebaby420 Group TitleBest ResponseYou've already chosen the best response.0
Idk how.. I only know how to solve the ones with Y on the other side of the equal sign
 11 months ago

DebbieG Group TitleBest ResponseYou've already chosen the best response.0
You just need to rearrange 8xy=10 so that the y is by itself. Try adding y to both sides: 8xy+y=10+y What do you get when you simplify that? Then subtract 10 from both sides.
 11 months ago

raebaby420 Group TitleBest ResponseYou've already chosen the best response.0
IM SO FREAKING LOST
 11 months ago

raebaby420 Group TitleBest ResponseYou've already chosen the best response.0
THANKS GUYS. I don't need any more help
 11 months ago

DebbieG Group TitleBest ResponseYou've already chosen the best response.0
@jessssloukaa the idea is not to do the problem FOR her.
 11 months ago
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