Please help. What are the solutions to the following system of equations? y = x2 + 12x + 30 8x − y = 10 (−4, −2) and (2, 5) (−2, −4) and (2, 5) (−2, −4) and (5, 2) No Real Solutions

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@Jack1

be unique y in second equation, then plug in to first equation... in seceon 8x - y = 10 -> y = 8x - 10 now plug in it to first equation and find x... y = x2 + 12x + 30 -> 8x - 10 = x2 +12x + 30 got it lady? ;)

hey @raebaby420 , sorry bout the "issues" last time anyway, as @mhmdrz91 said use the second equation to find what y equals (in terms of x) then sub in that result into the first equation (as per post above, cheers mhmd)

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