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westsayyid
 one year ago
Just getting started with MIt 6.189. I am not understanding how Problem 10 Exam 1 returns 0,5. Can someone assist.
def f(a):
a=a+5
return a
b=0
f(b)
print b, ",",
b = f(b)
print b
westsayyid
 one year ago
Just getting started with MIt 6.189. I am not understanding how Problem 10 Exam 1 returns 0,5. Can someone assist. def f(a): a=a+5 return a b=0 f(b) print b, ",", b = f(b) print b

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rsmith6559
 one year ago
Best ResponseYou've already chosen the best response.1The first call to f(b) doesn't assign the return value, the second does.

e.mccormick
 one year ago
Best ResponseYou've already chosen the best response.1To expand on what rsmith6559 said: f(b) is a call to the function f with the value of b. The function does the internal math in a separate namespace. Nothing has actually changed in the original b. Then f returns the input + 5, but f(b) is on a line by itself so that goes nowhere. Sort of like if a person tosses a ball and nobody is there to catch it then it is not caught. The ball falls to the ground and rolls away. b = f(b) starts out the same way. A copy of b is put into f in a separate namespace. f does its work and tosses back 5. This time there is b= out there so b catches the address that points to 5. To do this it had to drop the address that pointed to 0. Now b is a representation of 5 and no longer 0. Because the print statements happen after each of these steps, you get the unchanged b then the changed b. All of this is wonderfully summarized by rsmith6559, but if you still wanted more: there it is!

dan815
 one year ago
Best ResponseYou've already chosen the best response.1def f(a): a=a+5 return a you got a function f function f takes an input and adds 5 to it, and returns that value... f(b)= b+5 f(0)=0+5=5 then its printing, what you input and the new value with this command print b, ",", < right now b is still 0 b = f(b) < now b became b=0+5=5 print b < this is added to the top print command because there is a comma at the end of it

Nastur79
 one year ago
Best ResponseYou've already chosen the best response.0def f(a): a=a+5 return a b=0 f(b) # nothing print b, ",", # print 0 b = f(b) # b = f(0) = "a = 0 + 5" = "a = 5" = 5 print b #print 5

sidd607
 one year ago
Best ResponseYou've already chosen the best response.0when f(b) is called the first time, the function returns 5 but it doesn't change the value of b. So it remains 0. but the the next time you assign b=f(b) as the function returns 5 which is then assigned to the variable b. Hence this time it prints 5. so the output is 0,5
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