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seems unlikely but maybe
Following me around again @satellite73
I got the same answer , lemme see if i can get a different answer by doing it right ..
no it is not right
@Hero yeah, i need to keep you honest!
Here's how to figure out if you ever doubt yourself , take your number you get for x which in your case you got -2 , & simply substitute it for x .. so it should be (2)(-2)-8(2)(-2)+1 = -2 squared - 16
I was hoping I would be able to travel to and fro without having to watch my back.
What is it then ?
The first problem is here: 2(x-4)(2x+1)=(x-4)(x+4) l /x-4 You can divide by x-4, if you don't know that x-4 is not=0.
Use quad formula, complete the square or whatever method you feel comfortable with to isolate x.
Compounded here: 2(2x+1)=x+4 l -x+4 4x+2-x+4=0 IF the step before were correct, you would subtract (x+4), not subtract x and add 4.
*You CAN'T divide by x-4, if you don't know that x-4 is not=0.
@Hero did i make you nervous or something?
No, you didn't, I just goofed.
(2x−8)(2x+1)=x^2−16 Multiply the right side: 2x(2x+1)−8(2x+1)=x^2−16 4x^2+2x−16x−8=x^2−16 4x^2−14x−8=x^2−16 Subtract x^2 from both sides: 3x^2−14x−8=−16 Add 16 to both sides: 3x^2−14x+8=0
Now, you can use quad formula, or complete the square, or whatever method feels comfortable for you.
I need to know what x is.
Do you know any methods to isolate x such as factoring, quadratic formula or complete the square?
I know methods to facrorise.
Well, believe it or not 3x^2 -14x + 8 = 0 Is factorable
That only works if you have a perfect square.
3x^2 - 14x + 8 = 0 that's not a perfect square, but it is factorable. Try finding two numbers that multiply to get 24 yet add to get -14 m x n = 24 m + n = -14
12 and 2.
Actually -12 and -2
We can replace -14 with -(12 + 2) in the equation: 3x^2 - (12 + 2)x + 8 = 0 3x^2 -12x - 2x + 8 = 0
Now we can factor by grouping.
If you factor the first two terms you get 3x(x - 4) If you factor the last two terms you gete -2(x - 4) So you have 3x(x - 4) - 2(x - 4) = 0 x - 4 is also common to both so you factor that out to get (x - 4)(3x - 2) = 0 From here, you use zero product property: x - 4 = 0 3x - 2 = 0 So there are two values of x