what is an equation of a line parallel to y=7x+5 with an x-intercept of 6
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ur given eqn is in the form y=mx+c...so m(slope) is 7...now for a line parallel to ur eqn..the slope remains same...so u havethe eqn of the line as y=7x+c...where c is the a constant to be determine...Now X intercept( thats where the line cuts the X axis) is 6..so at that point where the line cuts the X axis..the y co-ordinate should be 0... so the line passes through..(6,0)..so put (6,0) in place of x any Y...the eqn should be satisfied...so..0=42+c..so c=-42...hence eqn of line y=7x-42
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First, get the equation into y =mx + b form.
Here, we know the slope (m) is 7, so the slope of our new line is also 7. We also know a point on the new line (6, 0). So, let's figure out the y intercept.
y = 7x + b
0 = 7(6) + b
0 = 42 + b
b = -42
So, the equation is y = 7x - 42. In ax + by = c form, just rearrange.
y = 7x - 42