At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
This is the answer: 0 small tile, 6 large tiles; minimum cost $27
i know the answer is : 0 small tile, 6 large tiles; minimum cost $27 but i got 0 small tiles, 30 large tiles; minimum cost of $135
here is my work could. Someone tell me were i went wrong? The smallest size the mosaic can be is 3’ X 5’ or 36” X 60” (2160sq”) The area of the small tiles are 4” X 4” or 16sq” at a cost of $3.50 each The area of the large tiles are 6” X 12” or 72sq” at a cost of $4.50 each Let x = the number of small tiles Let y = the number of large tiles (Area of the small tiles) (Number of small tiles) + (area of the large tiles) (number of large tiles) = minimum area of the mosaic 16x + 72y = 2160 Start by finding “y” 16x + 72y = 2160 16x + y = 30 y = 30 – 16x Plug “y” back into the original equation to find x (the number of small tiles) 16x + 72y = 2160 16x + 72(30 – 16x) = 2160 16x + 2160 – 1152x = 2160 -1136x = 0 x = 0/-1136 x = 0 The number of small tiles (x) = 0 Plug “x” into the original equation to find “y” (the number of large tiles) 16x + 72y = 2160 16(0) + 72y = 2160 72y = 2160 y = 2160/72 y = 30 The number of large tiles (y) = 30 Minimum cost = (price of each small tile) (Number of small tiles) + (price of each large tile) (number of large tiles) Minimum cost = $3.50x + $4.50y Minimum cost = $3.50(0) + $4.50(30) Minimum cost = $0 + $135 Minimum cost = $135 So in order to minimize the cost the artist should use 0 small tiles and 30 large tiles to keep a minimum cost of $135
@mojo872 can you help me please?
As far as I can see, all of your workings are correct - the artist lays out 30 large tiles (6 high and 5 wide), to create a mosaic that is 3 feet high and 5 feet wide, which means the answer is indeed $135. Can you check the question wording again, and make sure all of the numbers you typed out are correct?
@mojo872 that’s exactly how the question is worded. I copied it from the test my teacher gave me. I sent in that answer and got 0 pts. Though. I’ve emailed my teacher asking for an explanation … maybe there’s something missing from the question that she’s not giving me. I don’t know but I’ll wait and see. Thx for your help though :)
No problem. On reviewing your workings, I think you've made an incorrect algebraic manipulation here - when dividing by 72: Start by finding “y” 16x + 72y = 2160 16x + y = 30 y = 30 – 16x I still agree that the cheapest way is to use 30 large tiles (which seems obvious because they are 4.5 times bigger than the small tiles, and only cost $1 more), but I don't think your workings prove that, and I don't know how to prove it rigorously. However, your answer is still correct, as far as I can see, so that doesn't explain getting zero! Let us know what your teacher says...
ok so my teacher finnally responded. here's what she said ... "You are missing a lot of other inequalities that play a huge factor in solving this problem. You need not only the area, but the height equation, the width equation, and the real world constraints. You only have two of the 6 that you need."
This problem is simpler than you think. If you calculate the price per square inch of the small word tiles and the large word tiles, you'll see that the large word tiles are much cheaper per square inch. Therefore, it will be much cheaper to cover with all large word tiles. The only problem that could occur is if the large tiles are of a size that is not divisible into the dimensions of the entire mosaic, but in this case they are, so just use large tiles. 4 ft x 6 ft = 24 sq ft = 2160 sq in. 6 in. x 12 in. = 72 sq in. (2160 sq in. / 72 sq in. = 135 large tiles
but umm ... 2160 / 72 = 30 not 135 @mathstudent55
Sorry. I meant 30, not 135. I had just looked at 135 and wrote it by mistake. You are correct, it's 30 large tiles.
haha its ok ... I think my teachers crazy. I don’t see how the answer could possibly be 6 large tiles
This problem is simpler than you think. If you calculate the price per square inch of the small word tiles and the large word tiles, you'll see that the large word tiles are much cheaper per square inch. Therefore, it will be much cheaper to cover with all large word tiles. The only problem that could occur is if the large tiles are of a size that is not divisible into the dimensions of the entire mosaic, but in this case they are, so just use large tiles. 5 ft x 3 ft = 15 sq ft = 2160 sq in. 6 in. x 12 in. = 72 sq in. (2160 sq in. / 72 sq in. = 30 large tiles
I also wrote above 4 ft x 6 fx = 24 sq ft = 2160 sq in. In fact, 4 ft x 6 ft = 24 sq ft = 3456 sq in. I meant 3 ft x 5 ft = 15 sq ft = 2160 sq in. I corrected in my last response.
@mathstudent55 @mojo872 so what would the equation be for the real answer? how would you get that?