anonymous
  • anonymous
Square root of -36? Are all negative square roots undefined?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
no because there are imaginary numbers also
anonymous
  • anonymous
|dw:1377543316643:dw|
anonymous
  • anonymous
I haven't learned imaginary numbers!

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jdoe0001
  • jdoe0001
not just all negative square roots, all EVEN RADICALS with a negative quantity are so-called imaginary \(\bf \large \sqrt[4]{-23}\qquad \sqrt[202]{-79}\qquad \sqrt[24]{-11}\) and so on
jdoe0001
  • jdoe0001
http://www.mathsisfun.com/numbers/imaginary-numbers.html
jdoe0001
  • jdoe0001
check your book, it's surely has such chapter
anonymous
  • anonymous
I'm doing summer hw, I haven't started the course, so there's no book.
jdoe0001
  • jdoe0001
w0t?
jdoe0001
  • jdoe0001
well, plenty of material online for that http://www.youtube.com/watch?v=rDLDGQMKT3M
anonymous
  • anonymous
the square root of -36 is 6
anonymous
  • anonymous
I think its fair to say I am going to fail Algebra this year. Lol, yay!
anonymous
  • anonymous
is the same as when you take regular square roots but this time you use ( i ) to represent the negative inside the quare root
anonymous
  • anonymous
But, how come on my wkst, when it asked for the sq root of -17, my teacher wrote undefined?
jdoe0001
  • jdoe0001
it's undefined, i = imaginary \(\bf \sqrt{-1}= i\implies imaginary\\ \sqrt{-36} \implies \sqrt{6^2}\times \sqrt{-1} \implies 6 \times \sqrt{-1} \implies 6 \times i \implies 6i\)
anonymous
  • anonymous
i would have to assume then that all negative square roots are undefined for this part of the course
anonymous
  • anonymous
So, undefined & imaginary are the same thing?
anonymous
  • anonymous
yes
anonymous
  • anonymous
wait no
anonymous
  • anonymous
dont pay mind to me
anonymous
  • anonymous
Lol, I suck at math and I am literally getting nowhere with these negative square roots!
anonymous
  • anonymous
undefined means that there is no answer in real numbers
jdoe0001
  • jdoe0001
you see, the root function, one can say is clueless where the number is coming from all it tells you is that, "if you multiply this number by itself, you'd get THAT" that's all the root function does, reason why usually you'd get a + and a - version, because both versions multiplied by itself will yield THAT value so when you have a -1 in an even root, signs multiplication won't give a negative ever if the terms are even -2 * -2 = +4 -whatever * -whatever = + whateverelse so what the system does for the sake of SIMPLIFICATION is, it squeezes out of the radical as much POSITIVE as it can, and then leaves out what it cannot remove, the -1
anonymous
  • anonymous
So for square root of negative 17, negative 14, negative 36, and 0. I can put undefined?
anonymous
  • anonymous
yes and the square root of 0 is 0 so that one is not undefinded
anonymous
  • anonymous
@JAMG THANK YOU! This other guy is confusing me.
jdoe0001
  • jdoe0001
hmm, well, if your teacher wants to use undefined instead of imaginary, yes "imaginary" is the currency though, but undefined is ok-for-use
anonymous
  • anonymous
Alright, thanks everyone, I'll just go for it!
anonymous
  • anonymous
:)

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