anonymous
  • anonymous
Find an equation in standard form for the line described: Passing through the points (1,4) and (-3,4) If you could show the conversion from slope intercept to standard form in your work, that would help me understand this a lot!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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jdoe0001
  • jdoe0001
can you get the slope off those 2 points?
anonymous
  • anonymous
Yeah, it's 0/-4
anonymous
  • anonymous
Which means that the line is horizontal?

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jdoe0001
  • jdoe0001
yes
jdoe0001
  • jdoe0001
so our slope is 0, so let's use a point off those 2 available to us :) let's say we use ( -3, 4) and plug them in the slope-intercept form, gimme a sec
anonymous
  • anonymous
Alright... then what?
anonymous
  • anonymous
So basically it's 4=-3x0/4+b
jdoe0001
  • jdoe0001
\(\bf y-y_1=m(x-x_1)\quad \textit{using } (\color{red}{-3, 4}) \quad y-(\color{red}{4})=(0)(x-(\color{red}{-3}))\) what do you get off that if you solve for "y"?
anonymous
  • anonymous
you get y=4?
jdoe0001
  • jdoe0001
|dw:1377544478589:dw| as you can see, as you suspected, it's a horizontal line
anonymous
  • anonymous
So then how would this answer be converted into standard form? Or is y=4 already in standard form?
jdoe0001
  • jdoe0001
standard form? looks in order to me already unless you mean y = mx+b so-called slope-intercept form
anonymous
  • anonymous
no no, I mean the Ax+By=C form
jdoe0001
  • jdoe0001
well, yes, y = 4 is standard polynomial form you only have 1 variable, and 1 independent term, or so-called constant thus you could just rewrite it as y-4 = 0
jdoe0001
  • jdoe0001
http://www.mathsisfun.com/algebra/standard-form.html

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